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1)

\(\Leftrightarrow\dfrac{3-2x}{5}-\dfrac{2-x}{3}>0\)

\(\dfrac{9-6x}{15}-\dfrac{10-5x}{15}>0\)

\(\Leftrightarrow9-6x-10+5x>0\)

\(\Leftrightarrow-x-1>0\)

=> -x > 1

=> x > -1

Câu 25: B

Bài 5:

a: 2x-(3-5x)=4(x+3)

=>2x-3+5x=4x+12

=>7x-3=4x+12

=>3x=15

=>x=5

b: =>5/3x-2/3+x=1+5/2-3/2x

=>25/6x=25/6

=>x=1

c: 3x-2=2x-3

=>3x-2x=-3+2

=>x=-1

d: =>2u+27=4u+27

=>u=0

e: =>5-x+6=12-8x

=>-x+11=12-8x

=>7x=1

=>x=1/7

f: =>-90+12x=-45+6x

=>12x-90=6x-45

=>6x-45=0

=>x=9/2

152 + (-173) - (-18) - 127 

= 152 + (-173) + 18 - 127

= (152 + 18) + (-173) - 127

= 170 + (-300)

= -130

\(152+\left(-173\right)-\left(-18\right)-127\)

\(=\left(152+18\right)-\left(173+127\right)\)

\(=170-300=-130\)

152+(-173)-(-18)-127

=152-173+18-127

=(152+18)-(173+127)

=170-300

=-130

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\(\Leftrightarrow n^5+n^2-n^2+1⋮n^3+1\)

\(\Leftrightarrow-n^3+n⋮n^3+1\)

\(\Leftrightarrow n=1\)