a) 39.(x-5)=39

=> x-5=1

=> x=6

b) (30-x).4=92

=> 30-x=23

=> x=7

39.(x-5)=39

x-5=39:39

x-5=1

x=1+5

x=6

(30-x).4=92

30-x=92:4

30-x=18

x=30-18

x=12

a: -26-(x-7)=0

=>x-7=-26

=>x=-26+7=-19

b: \(24-\left(30+x\right)=-7\)

=>\(30+x=24-\left(-7\right)\)

=>\(x+30=24+7=31\)

=>x=31-30=1

c: \(3-\left(17-x\right)=-12\)

=>\(17-x=3-\left(-12\right)\)

=>\(17-x=3+12=15\)

=>x=17-15=2

d: \(\left(5-x\right)-7=-15\)

=>\(5-x=-15+7=-8\)

=>\(x=5-\left(-8\right)=5+8=13\)

\(1,\\ a,\Leftrightarrow x-\dfrac{1}{3}=0\Leftrightarrow x=\dfrac{1}{3}\\ b,\Leftrightarrow\left[{}\begin{matrix}x-4=4\\x-4=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=0\end{matrix}\right.\\ c,\Leftrightarrow2x+1=-2\Leftrightarrow x=-\dfrac{3}{2}\\ 2,\\ a,=1\\ b,=\left(\dfrac{13}{4}\right)^2=\dfrac{169}{16}\\ c,=\left(-\dfrac{7}{4}\right)^2=\dfrac{49}{16}\\ d,=\left(\dfrac{3}{7}\right)^{20}:\left(\dfrac{3}{7}\right)^{12}=\left(\dfrac{3}{7}\right)^8=...\\ e,=\left(3\cdot5\cdot\dfrac{2}{3}\right)^2=10^2=100\)

a)9200

9200

6400

b)50

50

19,5

c)128

128

60

a)    92 : 0,01 = 9200          92 x 100 = 9200        64 : 0,01= 6400

b)    25 : 0,5 = 50           25 x 2 = 50           39 : 0,5 = 78
c)    32 : 0,25 = 128         32 x 4 = 128          15 : 0,25 = 60

a)92 : 0,01 = 9200      92 x 100 = 9200          64 : 0,01 = 6400
b)25 : 0,5 = 50            25 x 2 = 50                  39 : 0,5 = 78
c)32 : 0,25 = 128        32 x 4 = 128                 15 x 0,25 = 60

a) (x - 78) .26 = 0 => x - 78 = 0 => x = 78

b) 39 (x - 5) = 39 => x - 5 = 1 => x = 6

c) (x - 14) : 2 = 3 => x - 14 = 6 => x = 20

d) (30 - x) . 4 = 92 

=> 30 - x = 92 : 4 

=> 30 - x = 23

=> x = 30 - 23 = 7

e) 45(91 - x) = 90

=> 91 - x = 90 : 45

=> 91 - x = 2

=> x = 91 - 2 = 89

f) (2x - 6)(3x - 18) = 0

=> \(\orbr{\begin{cases}2x-6=0\\3x-18=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=6\end{cases}}\)

g) 5x + 73.21 = 73.26

=> 5x = 73.26 - 73.21

=> 5x = 73(26 - 21) = 73.5

=> x = \(\frac{73\cdot5}{5}=73\)

h) 2x - 12 - x = 0

=> 2x - x - 12 = 0

=> x - 12 = 0

=> x = 12

làm rõ giùmnha

làm rõ giùm mình với

a) \(\left(x-78\right).26=0\)                                                    b)  \(39.\left(x-5\right)=39\)

\(\left(x-78\right)=0\)                                                                  \(x-5=39:39\)

\(x=0+78\)                                                                        \(x=1+5\)

\(x=78\)                                                                                 \(x=6\)

P/S: Dấu "." là dấu nhân nhé

\(\left(x-14\right):2=3\)

\(x-14=2.3\)

\(x=6+14\)

\(x=20\)

\(\left(30-x\right):4=92\)

\(30-x=92.4\)

\(30-x=368\)

\(x=30-368\)

\(x=-338\)

a) \(2x^2-4x=0\)

\(2x\left(x-2\right)=0\)

TH1:2x=0⇒x=0

TH2:x-2=0⇒x=2

\(a,\Leftrightarrow2x\left(x-2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\\ b,\Leftrightarrow\left(x+5\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=3\end{matrix}\right.\\ c,\Leftrightarrow2\left(x-4\right)-\left(x-4\right)=0\\ \Leftrightarrow x-4=0\Leftrightarrow x=4\)

2x(x - 2) = 0

2x = 0           hoặc          x - 2 = 0

x = 0             hoặc           x = 2

(x - 3)(x + 5) = 0

x - 3 = 0         hoặc          x + 5 = 0

x  = 3             hoặc           x = -5

(x - 4)2 = 0

x = 4              

a) 87 + 92 – 32 = 179 – 32

                   = 147

b) 138 – 30 – 8 = 108 - 8

                  = 100

c) 30 x 2 : 3 = 60 : 3

                  = 20

d) 80 : 2 x 4 = 40 x 4

                  = 160