\(\Rightarrow\left(\dfrac{33}{11}\right)^{2x}=81\Rightarrow3^{2x}=3^4\Rightarrow x=2\)

a) 12+(2x-11)=53

(2x-11) = 53-12

2x-11= 41

2x=41+11

2x=52

x= 52:2

x=26

Vậy...

\(b,21-\left(-6+3x\right)=9\)

\(\Rightarrow21+6-3x=9\)

\(\Rightarrow27-3x=9\)

\(\Rightarrow3x=18\)

\(\Rightarrow x=6\)

c, -(2x+4)+11=-27

=>-2x-4+11=-27

=>-2x+7=-27

=>-2x = -34

=>x=17

d, 33-(33-x)=0

=>33-33+x=0

=>x=0

1)

x^3 -16x=0`

`<=>x(x^2 -16)=0`

\(< =>\left[{}\begin{matrix}x=0\\x^2-16=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x^2=16\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=4\\x=-4\end{matrix}\right.\)

b)

`x^4 -2x^3=0`

`<=>x^3 (x-2)=0`

\(< =>\left[{}\begin{matrix}x^3=0\\x-2=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

3)

`(2x-11)(x^2 -1)=0`

\(< =>\left[{}\begin{matrix}2x-11=0\\x^2-1=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}2x=11\\x^2=1\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=1\\x=-1\end{matrix}\right.\)

4)

`x^3 -36x=0`

`<=>x(x^2 -36)=0`

\(< =>\left[{}\begin{matrix}x=0\\x^2-36=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x^2=36\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=0\\x=6\\x=-6\end{matrix}\right.\)

5)

`2x+19=0`

`<=>2x=-19`

`<=>x=-19/2`

bài về nghiệm của đa thức

\(2x+33=-11-x\)

\(2x+x=-11-33\)

\(2x+x=3x\Rightarrow3x=-44:3=\frac{-44}{3}\)

\(\Rightarrow x=\frac{-44}{3}\)

mình giải rõ ràng và dễ hiểu nhất nên k cho mình nhé

2x + 33 = -11-x

<=> 2x + x = -11-33

<=> 3x = -44

x= \(-\frac{44}{3}\) 

x=\(\frac{-44}{3}\)

a) 33^x:11^x-1=80

3^x=81

3^x=3⁴

x⁴

b) 81^2x.27^x=9¹¹

(3⁴)^2x.(3³)^x=(3²)¹¹

3^8x.3^3x=3²²

3^8x+3x=3²²

3^11.x=3²²

11.x=22

x=2

\(\frac{22}{25}\times\frac{5}{11}-\frac{33}{25}:\frac{11}{5}+\frac{58}{11}\)

\(=\frac{22}{25}\times\frac{5}{11}-\frac{33}{25}\times\frac{5}{11}+\frac{58}{11}\)

\(=\frac{5}{11}\times\left(\frac{22}{25}+\frac{33}{25}\right)+\frac{58}{11}\)

\(=\frac{5}{11}\times\frac{11}{5}+\frac{58}{11}\)

\(=1+\frac{58}{11}\)

\(=\frac{11}{11}+\frac{58}{11}\)

\(=\frac{69}{11}\)

\(8\frac{3}{11}-\left(3\frac{5}{7}-7\frac{8}{11}\right)\)

\(=\frac{91}{11}-\left(\frac{26}{7}-\frac{85}{11}\right)\)

\(=\frac{91}{11}-\frac{26}{7}+\frac{85}{11}\)

\(=\frac{91}{11}+\frac{85}{11}-\frac{26}{7}\)

\(=16-\frac{26}{7}\)

\(=\frac{86}{7}\)

\(\frac{5}{6}x+325\%=\frac{3}{2}x-30,75\)

\(=>\frac{5}{6}x+3,25=\frac{3}{2}x-30,75\)

\(=>\frac{5}{6}x-\frac{3}{2}x=-30,75-3,25\)

\(=>\frac{-2}{3}x=-34\)

\(=>x=-34:\left(-\frac{2}{3}\right)\)

\(=>x=-34.\left(\frac{3}{-2}\right)\)

\(=>x=51\)