=1

=1

\(3\dfrac{1}{200}\) lớn nhất

\(2\dfrac{3}{10};2\dfrac{7}{20};3\dfrac{1}{200};2\dfrac{7}{10}\)

\(=>\dfrac{23}{10};\dfrac{47}{20};\dfrac{601}{200};\dfrac{27}{10}\)

\(=>\dfrac{460}{200};\dfrac{470}{200};\dfrac{601}{200};\dfrac{540}{200}\)

\(=>\dfrac{601}{200}\) là lớn nhất

\(=>3\dfrac{1}{200}\) là lớn nhất

27 10 = 2 , 7 93 10 = 9 , 3 247 10 = 24 , 7

\(\dfrac{11\cdot9^{11}\cdot3^7-27^{10}}{4\cdot81^1}\)

\(=\dfrac{11\cdot3^{22}\cdot3^7-\left(3^3\right)^{10}}{4\cdot3^4}\)

\(=\dfrac{11\cdot3^{29}-3^{30}}{4\cdot3^4}\)

\(=\dfrac{3^{29}\cdot\left(11-3\right)}{4\cdot3^4}\)

\(=\dfrac{3^{29}\cdot8}{4\cdot3^4}\)

\(=3^{25}\cdot2\)

@ Huỳnh Thanh Phong

Sao lại lấy 3²⁹ là thừa số chung ạ

vì 3³⁰=3²⁹.3¹ á bạn

\(\left(3x+4\right)^3=\left(9x-8\right)\left(3x^2-8\right)\)

\(27x^3+108x^2+144x+64=27x^3-72x-24x^2+64\)

\(27x^3-27x^3+108x^2+24x^2+144x+72x=64-64=0\)

\(132x^2+216x=0\)

\(x\left(132x+216\right)=0\)

\(\Rightarrow x=\hept{\begin{cases}0\\\frac{216}{132}=\frac{18}{11}\end{cases}}\)

2887 dung day

2710-199+874-498=2887 nha bạn.

=2887 nha bạn

\(\left(9x+4\right):23=8\\ \Leftrightarrow9x+4=184\\ \Leftrightarrow9x=180\\ \Leftrightarrow x=20\)

Vậy x = 20

a) \(4x^4+81=\left[\left(2x^2\right)^2+36x^2+9^2\right]-36x^2=\left(2x^2+9\right)-\left(6x\right)^2=\left(2x^2-6x+9\right)\left(2x^2+6x+9\right)\)

b) \(x^8+9x^4+1=\left[\left(x^4\right)^2+2x^4+1\right]-7x^4=\left(x^4+1\right)-\left(\sqrt{7}x^2\right)^2=\left(x^4+1-\sqrt{7}\right)\left(x^4+1+\sqrt{7}\right)\)