\(N=\dfrac{\dfrac{2.2}{3}\left(\dfrac{1}{5}-\dfrac{1}{7}-\dfrac{1}{11}\right)}{\dfrac{6.6}{2}\left(\dfrac{1}{5}-\dfrac{1}{7}-\dfrac{1}{11}\right)}=\dfrac{4}{\dfrac{3}{\dfrac{36}{2}}}=24\)

\(M=\dfrac{3\cdot\left(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}{6\cdot\left(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}=\dfrac{3}{6}=\dfrac{1}{2}\)

k) \(\dfrac{-209}{115}\) và \(\dfrac{-241}{131}\)

Ta có : \(\left(-209\right)\cdot131=-27379\)

            \(\left(-241\right)\cdot115=-27715\)

Mà \(\left(-27715\right)< \left(-27379\right)\)

\(\Rightarrow\) \(\dfrac{-209}{115}>\dfrac{-241}{131}\)

-241/131 > -209/115

= (-48)2.36+36(-304)
= -96.36+36(-304)
= 36(-96-304)
= 36(-400)
= -14400

= 0,54 + 0,24 + 0,12 + 0,1 

= 1

\(\dfrac{27}{50}+\dfrac{24}{100}+0,12+10\%\)
\(=\dfrac{27}{50}+\dfrac{12}{50}+\dfrac{6}{50}+\dfrac{5}{50}\)
\(=\dfrac{50}{50}=1\)

`27/50+24/100+0,12+10%`

`=27/50+6/25+3/25+1/10`

`=(27/50+1/10)+(6/25+3/25)`

`=(27/50+5/50)+9/25`

`=32/50+9/25`

`=16/25+9/25`

`=25/25=1`

`a)` \(18\le2x\le150\\ =>\dfrac{18}{2}\le x\le\dfrac{150}{2}\\ =>9\le x\le75\)

\(A=\left\{9;10;11;12;...;75\right\}\)

`b)` Số phần tử tập hợp A :

   \(\left(75-9\right):1+1=67\) (phần tử)

Tổng tập hợp A :

    \(\left(75+9\right).67:2=2814\)

$a)$ 18≤2�≤150=>182≤�≤1502=>9≤�≤7518≤2x≤150=>218​≤x≤2150​=>9≤x≤75

$A=\left\{9;10;11;12;...;75\right\}$

$b)$ Số phần tử tập hợp A :

   $\left(75-9\right):1+1=67$ (phần tử)

Tổng tập hợp A :

    $\left(75+9\right).67:2=2814$

4/1 x 13/15

= 52/15

52/15

mình có câu trl rồi nhé:

4 x 13/15 = 4 x 13/15 = 52/15 nhé!