mình làm những bài bn chưa lm nhé

9B

10A

bài 2

have repainted

bàii 3

ride - walikking

swimming

watch

2 have repainted

4 have done 

8 have stepped

9 have you ever played

7) 1 riding -walking

2 swimming

3 watching

8)

2 my mother doesn't like listening to music

5 doing more exercises makes you healthier

còn lại ok nha

chịu ???????????????????

Bài 2

5 C

Bài 3

1 D

6 C

Còn lại ol r nhé

2) 5. C

3) 2. D

6. C

Còn lại ok nha

2:

a: A(x)=0

=>-5x+3=0

=>-5x=-3

=>x=3/5

b: B(x)=0

=>2x^3-18x=0

=>2x(x^2-9)=0

=>x(x-3)(x+3)=0

=>x=0;x=3;x=-3

c: C(x)=0

=>-x(-x-5)=0

=>x(x+5)=0

=>x=0 hoặc x=-5

d: D(x)=0

=>3x-3+2x^2-2x-x^2+2x-1=0

=>x^2+3x-4=0

=>x=-4 hoặc x=1

e: E(x)=0

=>2x^3-2x-x^2+1=0

=>2x(x^2-1)-(x^2-1)=0

=>(2x-1)(x-1)(x+1)=0

=>x=1/2;x=-1;x=1

Đề đây nha mng nãy mình quên up ;)) 

trả lời nhanh cho mình và đầy đủ nhá

Ta có :

\(ab-c=ab-a+a-c=a\left(b-1\right)+\left(a-c\right)\)

\(\Rightarrow\left|ab-c\right|=\left|a\left(b-1\right)+\left(a-c\right)\right|\)

\(\Rightarrow\left|ab-c\right|\le\left|a\left(b-1\right)\right|+\left|a+c\right|\)

\(\Rightarrow\left|ab-c\right|\le\left|a\right|\left|b-1\right|+\left|a-c\right|\)

Mà \(\left|a\right|< 1;\left|b-1\right|< 10;\left|a-c\right|< 10\)

\(\Rightarrow\left|ab-c\right|< 1.10+10\)

\(\Rightarrow\left|ab-c\right|< 20\left(đpcm\right)\)

mk mới hok jop 6 à

có \(\left|a\right|< 1\),\(\left|b-1\right|< 10\)suy ra \(\left|a\right|.\left|b-1\right|< 10\Rightarrow\left|a\left(b-1\right)\right|< 10\Leftrightarrow\left|ab-a\right|< 10\)
                                                                                                                                      \(\Leftrightarrow-10< ab-a< 10\)(1)
có \(\left|a-c\right|< 10\Leftrightarrow-10< a-c< 10\)(2)
 cộng lần lượt các vế của (1) và (2) ta có \(-10+\left(-10\right)< ab-a+a-c< 10+10\Leftrightarrow-20< ab-c< 20\)
 suy ra \(\left|ab-c\right|< 20\)

Nhìn đề mk chẳng hỉu j

\(a,A=0,2\left(5x-1\right)-\dfrac{1}{2}\left(\dfrac{2}{3}x+4\right)+\dfrac{2}{3}\left(3-x\right)\)

\(=x-0,2-\dfrac{1}{3}x-2+2-\dfrac{2}{3}x\)

\(=\left(-0,2-2+2\right)+\left(x-\dfrac{1}{3}x-\dfrac{2}{3}x\right)\)

\(=-0,2\)

\(b,B=\left(x-2y\right)\left(x^2+2xy+4y^2\right)-\left(x^3-8y^3+10\right)\)

\(=x^3-8y^3-x^3+8y^3-10\)

\(=-10\)

\(c,C=4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)-4x\)

\(=4\left(x^2+2x+1\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)-4x\)

\(=4x^2+8x+4+4x^2-4x+1-8x^2+8-4x\)

\(=13\)

a) \(A=0,2\left(5x-1\right)-\dfrac{1}{2}\left(\dfrac{2}{3}x+4\right)+\dfrac{2}{3}\left(3-x\right)\)

\(A=x-\dfrac{1}{5}-\dfrac{1}{3}x-2+2-\dfrac{2}{3}x\)

\(A=\left(x-\dfrac{1}{3}x-\dfrac{2}{3}x\right)-\left(\dfrac{1}{5}+2-2\right)\)

\(A=-\dfrac{1}{5}\)

Vậy: ...

b) \(B=\left(x-2y\right)\left(x^2+2xy+4y^2\right)-\left(x^3-8y^3+10\right)\)

\(B=\left[x^3-\left(2y\right)^3\right]-\left[x^3-\left(2y\right)^3\right]-10\)

\(B=-10\)

Vậy: ...

c) \(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x+1\right)\left(x-1\right)-4x\)

\(=4\left(x^2+2x+4\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)-4x\)

\(=4x^2+8x+4+4x^2-4x+1-8x^2+8-4x\)

\(=\left(4x^2+4x^2-8x^2\right)+\left(8x-4x-4x\right)+\left(4+1+8\right)\)

\(=13\)

Vậy:...

=x−0,2−13x−2+2−23x=�−0,2−13�−2+2−23�