câu 1) 

\(\dfrac{-12}{18}+\left(\dfrac{-21}{35}\right)=\dfrac{-19}{15}\)
câu 2) 

\(-\dfrac{3}{21}+\dfrac{6}{42}=0\)
câu 3)

\(-\dfrac{18}{24}+\dfrac{15}{21}=-\dfrac{1}{28}\)
câu 4) 

\(\dfrac{1}{6}+\dfrac{2}{5}=\dfrac{17}{30}\)
câu 5) 

\(\dfrac{3}{5}+\left(-\dfrac{7}{4}\right)=-\dfrac{23}{20}\)
câu 6) 

\(\left(-2\right)+\left(\dfrac{-5}{8}\right)=\dfrac{-21}{8}\)
câu 7) 

\(\dfrac{1}{-8}+\left(-\dfrac{5}{9}\right)=-\dfrac{49}{72}\)
câu 8) 

\(\dfrac{4}{13}+\dfrac{12}{39}=\dfrac{8}{13}\)
câu 9) 

\(\dfrac{1}{21}+\dfrac{1}{28}=\dfrac{1}{12}\)
câu 10) 

\(-\dfrac{3}{29}+\dfrac{16}{58}=\dfrac{5}{29}\)
câu 11) 

\(\dfrac{8}{40}+\left(-\dfrac{36}{45}\right)=-\dfrac{3}{5}\)
câu 12) 

\(-\dfrac{8}{18}+\left(-\dfrac{15}{27}\right)=-1\)
câu 13) 

\(\dfrac{13}{30}+\left(-\dfrac{1}{5}\right)=\dfrac{7}{30}\)
câu 14) 

\(\dfrac{2}{21}+\dfrac{1}{28}=\dfrac{11}{84}\)
câu 15) 

\(5+\left(-\dfrac{3}{4}\right)=\dfrac{17}{4}\)
câu 16) 

\(\dfrac{18}{24}+\dfrac{45}{-10}=-\dfrac{15}{4}\)

\(\dfrac{7}{21}+\dfrac{-9}{36}=\dfrac{1}{3}+\dfrac{-1}{4}=\dfrac{4}{12}+\dfrac{-3}{12}=\dfrac{1}{12}\)

\(\dfrac{-12}{18}+\dfrac{-21}{35}=\dfrac{-2}{3}+\dfrac{-3}{5}=\dfrac{-10}{15}+\dfrac{-9}{15}=\dfrac{-19}{15}\)

\(\dfrac{-18}{14}+\dfrac{15}{-21}=\dfrac{-9}{7}+\dfrac{-5}{7}=\dfrac{-14}{7}=-2\)

\(\dfrac{3}{21}+\dfrac{-6}{42}=\dfrac{1}{7}+\dfrac{-1}{7}=0\)

\(\frac{6}{18}+\frac{-14}{21}=\frac{1}{3}+\frac{-2}{3}=\frac{-1}{3}\);     ; 

\(\frac{6}{13}+\frac{-14}{39}=\frac{18}{39}+\frac{-14}{39}=\frac{4}{39}\);

\(\frac{-3}{21}+\frac{6}{42}=\frac{-1}{7}+\frac{1}{7}=0\); 

\(\frac{7}{21}+\frac{9}{-36}=\frac{1}{3}+\frac{-1}{4}=\frac{4}{12}+\frac{-3}{12}=\frac{1}{12}\)

Đặt `A=30-15+36-18+42-21+.....+96-48+102-51`

`=15+18+21+.....+48+51`

K/c mỗi số là 3 đơn vị.

Tổng có số số hạng là:

`(51-15):3+1=13` số

`=>A=(13.(15+51))/2=13.33=429`

\(30-15+36-18+42-21+...+96-48+102-51\) 

\(=\left(30-15\right)+\left(36-18\right)+\left(42-21\right)+...+\left(96-48\right)+\left(102-51\right)\) 

\(=15+18+21+...+48+51\) 

Số số hạng của \(\left(15+18+21+...+48+51\right)\) là:

              \(\left(51-15\right):3+1=13\) 

Tổng dãy \(\left(15+18+21+...+48+51\right)\) là: 

              \(\left(15+51\right).13:2=429\)

kết quả = 10 nha

60 + 57 + 54 + 51 + 48 + 45 + 42 + 39 + 36 + 33 + 30 + 27 + 24 + 21 + 18 + 15 + 12 + 9 + 6 + 3 = ?

= 630

ok mk xong trc $_$

60+57+54+51+48+45+42+39+36+33+30+27+24+21+18+15+12+9+6+3 = 630

= 60 + ( 57 + 3 ) + ( 54 + 6 ) + ( 51 + 9 ) + ( 48 + 12 ) + ( 45 + 15 ) + ( 42 + 18 ) + ( 39 + 21 ) + ( 36 + 24 ) + ( 33 + 27 )+ 30

=  60 +   60 + 60 + 60 + 60 + 60 + 60 + 60 + 60 + 60 + 30

=                     60 * 10 + 30

=                           630

HỌC TỐT NHA !

15 +18+21+....+36+39+43

=(15 + 18+21+...+36+39) +43

áp dụng công thức tính dãy số ta có

(39-15):3+1     .    (39 +15):2  +  43

=  9   .   27 + 43

= 81 + 43 = 124

\(\frac{4,29.1230-429.2,3}{30-15+36-18+...+102-51}=\frac{4,29.1230-4,29.230}{10+18+...+51}=\frac{4,29.\left(1230-230\right)}{\left(51+10\right).\left(51-10+1\right):2}\)

\(=\frac{4290}{429}=10\)