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Nguyễn Minh Đạt
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NeverGiveUp
27 tháng 6 lúc 21:04

1.I think you ought to give up playing video games. (should)

-->I think you should give up playing video games.

2.It's necessary for me to finish the work on time. (have to)

--->I have to finish the work on time.

3.It wasn't necessary for you to clean that car. (have to)

--->You didn't have to clean that car.

4.It was quite unnecessary for you to adopt a green lifestyle. (have to)

---->You didn't have to adopt a green lifestyle.

5.It was careless of you to leave the windows open last night. (shouldn't)

----->You shouldn't have left the windows open last night.

6.It is advisable for each member in the family to share the housework equally. (should)

---->Each member in the family should share the housework equally.

7.You are required to come back home before 10 p.m. (must)

--->You must come back home before 10 p.m.

8.Lina is advised to prepare carefully in the morning. (should)

----->Lina should prepare carefully in the morning.

9.Tu is responsible for picking up litter. (have to)

------>Tu has to pick up litter.

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NeverGiveUp
27 tháng 6 lúc 21:07

1.You are required to ask your parents for permission before staying out late. (must)

You must ask your parents for permission before staying out late.

2.I think you ought to give up smoking immediately. (should)

I think you should give up smoking immediately.

3.It is not a good idea for me to stay up late. (shouldn't)

I shouldn't stay up late.

4.It wasn't necessary for you to send these letters. (have to)

You didn't have to send these letters.

5.It was unnecessary for Tim to finish the work. (have to)

Tim didn't have to finish the work.

6.It was careless of you to leave your children alone at home. (shouldn't)

You shouldn't have left your children alone at home.

Bằng 1 cách nào đó 1 câu hỏi từ 2023 ở đây và tôi vẫn trả lời nó sau 1 năm :v

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Nguyễn Minh Đạt
12 tháng 11 2023 lúc 20:29

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Nguyen BaoChau
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Kiều Vũ Linh
5 tháng 5 2023 lúc 14:08

A = 1/(5.6) + 1/(6.7) + ... + 1/(24.25)

= 1/5 - 1/6 + 1/6 - 1/7 + ... + 1/24 - 1/25

= 1/5 - 1/25

= 4/25

B = 2/(1.3) + 2/(3.5) + 2/(5.7) + ... + 2/(99.101)

= 1 - 1/3 + 1/3 - 1/5 + 1/5 - 1/7 + ... + 1/99 - 1/101

= 1 - 1/101

= 100/101

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Trịnh Minh Hoàng
5 tháng 5 2023 lúc 18:36

`a) A = 1/(5.6) + 1/(6.7)+...+1/(24.25)`

`= 1/5 - 1/6 + 1/6 - 1/7 +...+1/24-1/25`

`= 1/5-1/25`

`= 5/25 - 1/25`

`= 4/25`

Vậy:`A = 4/25`

`b) B = 2/(1.3)+2/(3.5)+...+2/(99.101)`

`= 1- 1/3 + 1/3 - .... +1/99-1/101`

`= 1 - 1/101`

`= 100/101`

Vậy: `B = 100/101`

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thuỳ trang Phan thị
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Nguyễn Lê Phước Thịnh
29 tháng 7 2021 lúc 14:21

f) Ta có: \(F=\left(\dfrac{15}{\sqrt{6}+1}+\dfrac{4}{\sqrt{6}-2}-\dfrac{12}{3-\sqrt{6}}\right)\left(\sqrt{6}+11\right)\)

\(=\left(\dfrac{15\left(\sqrt{6}-1\right)}{5}+\dfrac{4\left(\sqrt{6}+2\right)}{2}-\dfrac{12\left(3+\sqrt{6}\right)}{3}\right)\left(\sqrt{6}+11\right)\)

\(=\left[3\left(\sqrt{6}-1\right)+2\left(\sqrt{6}+2\right)-4\left(3+\sqrt{6}\right)\right]\cdot\left(11+\sqrt{6}\right)\)

\(=\left(3\sqrt{6}-3+2\sqrt{6}+4-12-4\sqrt{6}\right)\left(11+\sqrt{6}\right)\)

\(=\left(\sqrt{6}-11\right)\left(11+\sqrt{6}\right)\)

=6-121=-115

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Xinh Dy
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Nguyễn Thị Thùy Trang
7 tháng 1 2022 lúc 9:43

a.2Al + 6HCl -> 2AlCl3 + 3H2

    2a      6a                        3a

Fe + 2HCl -> FeCl2 + H2

b         2b                      b

b.\(nH2=\dfrac{1.344}{22.4}=0.06mol\)

Ta có hệ phương trình: \(\left\{{}\begin{matrix}54a+56b=2.22\\3a+b=0.06\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=0.01mol\\b=0.03mol\end{matrix}\right.\)

\(\%mAl=\dfrac{0.01\times2\times27\times100}{2.22}=24.3\%\)

%mFe = 100 - 24.3 =75.7%

c.nHCl = 6a + 2b = 0.12 mol

\(CM_{HCl}=\dfrac{0.12}{0.2}=0.6M\)

 

 

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Thanh Nguyễn
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Phương Trâm
16 tháng 1 2022 lúc 18:49

a) \(I_1=\int\dfrac{dx}{x^2+2x+3}\)

\(=\int\dfrac{dx}{\left(x+1\right)^2+2}=\int\dfrac{d\left(x+1\right)}{\left(x+1\right)^2+\left(\sqrt{2}\right)^2}\)

\(=\dfrac{1}{\sqrt{2}}arctan\left(\dfrac{x+1}{\sqrt{2}}\right)+C\)

b) \(I_2=\int\dfrac{dx}{4x^2+4x+2}\)

\(=\int\dfrac{dx}{\left(2x+1\right)^2+1}=\dfrac{1}{2}\int\dfrac{d\left(2x+1\right)}{\left(2x+1\right)^2+1^2}\)

\(=\dfrac{1}{2}arctan\left(2x+1\right)+C\)

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Hải Đức
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Mèocute
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Nganhvy
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thuỳ trang Phan thị
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Đỗ Thanh Hải
2 tháng 9 2021 lúc 21:07

1 didn't go => hadn't gone

2 your => yours

3 was going => went

4 going => go

5 do => doing

6 told => tell

7 build => built

8 live => living

9 with => by

10 were => was

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