3x - 6y = 3( x - 2y)

=3.(x-2y)

\(x^2+2xy-3x-6y\)

\(=x\left(x+2y\right)-3\left(x+2y\right)\)

\(=\left(x+2y\right)\left(x-3\right)\)

\(=x\left(x+2y\right)-3\left(x+2y\right)=\left(x+2y\right)\left(x-3\right)\)

Ta có 4x²+8xy-3x-6y=4x(x+2y) -3(x+2y)=(x+2y)(4x-3)

4x²+8xy-3x-6y

=(4x²-3x)+(8xy-6y)

=x(4x-3)+2y(4x-3)

=(4x-3)(x+2y)

\(=\left(4x^2+8xy\right)-\left(3x+6y\right)\)
\(=4x.\left(x+2y\right)-3\left(x+2y\right)\)
\(=\left(x+2y\right).\left(4x-3\right)\)

a) 2x²-2y²-6x-6y = ( 2x²-2y²)- ( 6x+6y)

= 2(x2-y2)- 6(x+y)

2( x+y )- 6( x+y )

..........

b) x^3 +3x^2 - 3x -1= (x^3-1) +(3x^2-3x)

= (x³-1)+ 3x( x-y)

.......

Những dòng mình .... là đến đấy đơn giản rồi, đặt nhân tử chung là đc

= 

#Vũ Khánh Linh câu a/ dòg thứ 3 hình như sai sai.... @@

à ừ mình nhầm để mk sửa

a/ 2x^2-2y^2-6x-6y= ( 2x^2-2y^2)-(6x+6y)

= 2( x^2-y^2)- 6(x+y)

= 2( x+y) (x-y) -6(x+y)

a, 2x² + 10xy=2x(x+5y)
b, 3x ( y - x ) + 6y ( y - x )=(3x+6y)(y-x)
c, 3x ( x - 2 ) - x + 2 + 5x ( x - 2 )=3x(x-2)-(x-2)+5x(x-2)=(8x-1)(x-2)

giúp mik vs các bạn

D.3(x-2y)

đáp án D 

k cho mik nha

Kết quả phân tích đa thức 3x - 6y thành nhân tử là:

A. 3(x - 6y)

B. 3(3x - y)

C. 3(3x - 2y)

D. 3(x - 2y)

a)\(=3x\left(x+2y\right)\)

c)\(=\left(x-7\right)\left(x-1\right)\)

b)\(=x\left(x-2y\right)+3\left(x-2y\right)=\left(x+3\right)\left(x-2y\right)\)

d)\(=\left(2x\right)^2-y^2=\left(2x-y\right)\left(2x+y\right)\)

\(a,3x^2+6xy=3x\left(x+2y\right)\\ c,x^2-8x+7=\left(x^2-x\right)-\left(7x-7\right)=x\left(x-1\right)-7\left(x-1\right)=\left(x-1\right)\left(x-7\right)\\ b,x^2-2xy+3x-6y=\left(x^2+3x\right)-\left(2xy+6y\right)=x\left(x+3\right)-2y\left(x+3\right)=\left(x+3\right)\left(x-2y\right)\\ d,4x^2-y^2=\left(2x-y\right)\left(2x+y\right)\)

x³ - 3x²y + 3xy² - y³ - z³

= (x³ - 3x²y + 3xy² - y³) - z³

= (x - y)³ - z³

= (x - y - z)[(x - y)² + (x - y)z + z²]

= (x - y - z)(x² - 2xy + y² + xz - yz + z³)

--------------------

x² - y² + 8x + 6y + 7

= (x² + 8x + 16) - (y² - 6y + 9)

= (x + 4)² - (y - 3)²

= (x + 4 - y + 3)(x + 4 + y - 3)

= (x - y + 7)(x + y + 1)

a: \(=\left(x^3-3x^2y+3xy^2-y^3\right)-z^3\)

\(=\left(x-y\right)^3-z^3\)

\(=\left(x-y-z\right)\left[\left(x-y\right)^2+z\left(x-y\right)+z^2\right]\)

\(=\left(x-y-z\right)\left(x^2-2xy+y^2+xz-yz+z^2\right)\)

b: \(=x^2+8x+16-y^2+6y-9\)

=(x+4)^2-(y-3)^2

=(x+4+y-3)(x+4-y+3)

=(x+y+1)(x-y+7)