2 + 4 + 6 + ...... + 98 + 100
Những câu hỏi liên quan
100+98+96+94+...+8+6+4+2
_______________________
100-98+96-94+...+8-6+4-2
\(\frac{100+98+96+94+...+4+2}{100-98+96-94+...+4-2}\)
\(=\frac{\text{[}\left(100-2\right):1+1\text{]}.102:2}{2+2+2+...+2\left(51s\text{ố}2\right)}\)
\(=\frac{5049}{102}=49\frac{1}{2}\)
Đúng 0
Bình luận (2)
A = 1-2+3-4+5-6+.....+97-98+99-100+101
B = 1+2-3-4+5+6-7-8+......+98-99-100+101
B=1+2-(3+4)+5+6-..-100+101
B=(3+11+19+...+195)-(7+15+...+199)+101
B=25.99-25.103+101
B=-100+101=1
Vậy B=1
a=151
B=1 nha
Xem thêm câu trả lời
Tính
a)A=101+100+99+98+…+3+2+
101-100+99+98+…+3-2+1
b)B=3737.43-4343.37
2+4+6+…+100
\(A =\)\(\dfrac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
\(B=\) \(\dfrac{3737.43-4343.37}{2+4+6+...+100}\)
Làm cách lớp 6 thôi ah
\(A=\dfrac{101\cdot\dfrac{102}{2}}{\left(101-100\right)+99-98+...+3-2+1}\)
\(=\dfrac{101\cdot51}{1+1+...+1}=\dfrac{101\cdot51}{51}=101\)
\(B=\dfrac{37\cdot43\left(101-101\right)}{2+4+...+100}=0\)
Đúng 4
Bình luận (1)
a, \(A=\dfrac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
Ta có: \(T=101+100+99+98+...+3+2+1\) \(=\dfrac{\left(101+1\right).101}{2}\)
\(=\dfrac{102.101}{2}\Leftrightarrow51.101\)
\(M=101-100+99-98+...+3-2+1\)
Ta có: \(101:2=50\) (dư \(1\))
\(\Rightarrow M=\left(101-100\right)+\left(99-98\right)+...+\left(3-2\right)+1\)
Có \(50\) dấu ngoặc tròn "\(\left(\right)\)"
\(\Rightarrow M=1+1+...+1+1=51.1=51\)
\(M\) có \(51\) số \(1\)
\(\Rightarrow A=\dfrac{T}{M}=\dfrac{51.101}{51}=101\)
Vậy \(A=101\)
b, \(B=\dfrac{3737.43-4343.37}{2+4+6+...100}\)
Ta có: \(T=3737.43-4343.37\)
\(T=37.101.43-43.101.37\)
\(T=0\)
\(\Rightarrow\) \(B=\dfrac{T}{2+4+6+...+100}=\dfrac{0}{2+4+6+...+100}\) \(=0\)
Vậy \(B=0\)
Đúng 2
Bình luận (3)
2*4+4*6+6*8+...+98*100+100*102
Tính nhanh 2/2·4+2/4·6+2/6·8+.........+2/96·98+2/98·100
Đặt \(A=\frac{2}{2\cdot4}+\frac{2}{4\cdot6}+\frac{2}{6\cdot8}+...+\frac{2}{96\cdot98}+\frac{2}{98\cdot100}\)
\(A=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{98}-\frac{1}{100}\)
\(A=\frac{1}{2}-\frac{1}{100}\)
\(A=\frac{50}{100}-\frac{1}{100}=\frac{49}{100}\)
Đúng 1
Bình luận (0)
Tính nhanh:
a) 4.13.6+12.76.2+11.8.3
b) 2-4+6+8+10-12+...+98-100
c) (2+4+6+...+100) . (36.333-108-111)
d) 1-2-3+4+5-6-7+...+97-98-99+100
a) = 13 x 24 + 24 x 76 + 11 x 24 d)= (1-2-3+4)+(5-6-7+8)+...+(97-98-99+100)
= 24 x ( 13 + 76 + 11 ) = 0 + 0 +...+ 0
= 24 x 100 =0
= 2400
CÓ VIỆC BẬN NÊN MÌNH CHỈ LÀM ĐC ĐẾN ĐÓ THÔI !
d) 1-2-3+4+5-6-7+...+97-98-99+100
=(1-2-3+4)+(5-6-7+8)+(9-10-11+12)+......+(97-98-99+100)
=0+0+0+0+.....+0
=0
Vay bang 0
c) (2+4+6+...+100) . (36.333-108-111)
Ta chia hai tich tren la A va B, ta co:
A=(2+4+6+...+100)
B=(36.333-108-111)
A co ssh la:(100-2):2+1=45(ssh)
B=36.333-108-111
=>
A=(100+2)x45:2=2295
B=36.(111.3)-108-111=111.(36.3)-108-111=111.108-108.1-111=(111.8-108.1)-111=11880-111=11769
=>
A.B =2295.11769=( bam may tinh )27009855
tính
B=2*4*6+4*6*8+6*8*10+...+94*96*98+96*98*100
2-1+4-3+6-5+.............+1000-999
1/2*4+1/4*6+.............+1/98*1000
5/2*4+5/4*6+...........+5/98*100
tính nhanh (2/3+3/4+5/6+...+99/100).(1/2+2/3+3/4+...+98/99)-(1/2+1/3+...+99/100).(2/3+2/4+...+98/99)