\(A=\frac{35^3+13^3}{48}-35\cdot13\)
\(B=\frac{68^3-52^3}{16}+68\cdot52\)
Những câu hỏi liên quan
a)A=\(\frac{35^3+13^3}{48}-35.13\)
b)B=\(\frac{68^3-52^3}{16}+68.52\)
a) Ta có: A= \(\frac{35^3+13^3}{48}-35\cdot13\)=\(\frac{\left(35+13\right)\left(35^2-35\cdot13+13^2\right)}{48}-35\cdot13\)
=\(35^2-35\cdot13+13^2+35\cdot13\)=\(35^2+13^2=1394\)
b) Ta có: B=\(\frac{68^3-52^3}{16}+68\cdot52\)=\(\frac{\left(68-52\right)\left(68^2+68\cdot52+52^2\right)}{16}+68\cdot52\)
=\(68^2+2\cdot68\cdot52+52^2\)= \(\left(68+52\right)^2=120^2=14400\)
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Tính
B=\(\frac{68^3-52^3}{16}+68.52\)
A=\(\frac{35^3+13^3}{48}-35.13\)
\(B=\frac{\left(68-52\right)\left(68^2+68.52+52^2\right)}{16}+68.52=\frac{16\left(68^2+68.52+52^2\right)}{16}+68.52\)
\(B=68^2+2.68.52+52^2=\left(68+52\right)^2=120^2\)
Câu tiếp theo làm tương tự
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tính nhanh
\(A=\frac{35^3+13^3}{48}-35.13\)
\(B=\frac{68^3-52^3}{16}+68.52\)
TÍNH
a) A=\(\dfrac{35^3+13^3}{48}\)-35.13
b) B=\(\dfrac{68^3-52^3}{16}\)+68.52
a: Ta có: \(A=\dfrac{35^3+13^3}{48}-35\cdot13\)
\(=35^2-35\cdot13+13^2-35\cdot13\)
\(=\left(35-13\right)^2\)
\(=22^2=484\)
b: Ta có: \(B=\dfrac{68^3-52^3}{16}+68\cdot52\)
\(=68^2+68\cdot52+52^2+68\cdot52\)
\(=\left(68+52\right)^2=14400\)
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Help me!!!
Tính :
\(A=\frac{35^3+13^3}{48}-35.3\)
\(B=\frac{68^3-52^3}{16}+68.52\)
\(A=\frac{\left(35+13\right)\left(35^2-35.13+13^2\right)}{48}-35.13\)
\(=\frac{48.\left(35^2-35.13+13^2\right)}{48}-35.13\)
\(=35^2-35.13+13^2-35.13\)
\(=\left(35-13\right)^2\)
\(=484\)
\(B=\frac{\left(68-52\right)\left(68^2+68.52+52^2\right)}{16}+68.52\)
\(=\frac{16\left(68^2+68.52+52^2\right)}{16}+68.52\)
\(=68^2+68.52+52^2+68.52\)
\(=\left(68+52\right)^2\)
\(=14400\)
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Tính nhanh
a) A = \(\frac{35^3+15^3}{48}-35.13\)
b) B = \(\frac{68^3-52^3}{16}+68.52\)
A= 355+135/48-35.13 B= 683-523/16+68.52
a: Sửa đề: \(A=\dfrac{35^3+13^3}{48}-35\cdot13\)
\(=\dfrac{\left(35+13\right)\left(35^2-35\cdot13+13^2\right)}{48}-35\cdot13\)
\(=35^2-2\cdot35\cdot13+13^2=22^2\)
b: \(B=\dfrac{\left(68-52\right)\left(68^2+68\cdot52+52^2\right)}{16}+68\cdot52\)
\(=68^2+2\cdot68\cdot52+52^2\)
\(=110^2\)
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A= 355+135/48-35.13 B= 683-523/16+68.52
a: Sửa đề: \(A=\dfrac{35^3+13^3}{48}-35\cdot13\)
\(=\dfrac{\left(35+13\right)\left(35^2-35\cdot13+13^2\right)}{48}-35\cdot13\)
\(=35^2-2\cdot35\cdot13+13^2=22^2\)
b: \(B=\dfrac{\left(68-52\right)\left(68^2+68\cdot52+52^2\right)}{16}+68\cdot52\)
\(=68^2+2\cdot68\cdot52+52^2\)
\(=110^2\)
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Tính :
A = \(\dfrac{35^3+13^3}{48}\) - 35.13
B = \(\dfrac{68^3-52^3}{16}\) + 68.52
A= \(\dfrac{42875+2197}{48}-35.13\)
A=\(\dfrac{42875+2197}{48}-455\)
A=\(\dfrac{45072}{48}-455\)
A= 939-455
Vậy A= 484
B=\(\dfrac{68^3-52^3}{16}+\dfrac{6852}{100}\)
B= \(\dfrac{68^3-52^3}{16}+\dfrac{1713}{25}\)
Vậy B= 10932,52
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