`x xx 5 + x :5 =x+3/5`

`=> x xx 5 + x  xx 1/5=x+3/5`

`=> x xx (5+1/5) =x+3/5`

`=  x =x+3/5`

`=> x-x=3/5`

`=> 0=3/5(ko. t/m)`

53/35 : x = 33/35

            x = 53/35 : 33/35

            x =53/35

 5/7 : x = 33/35 - 4/5

 5/7 : x = 1/7

         x = 5/7:1/7

         x = 5

(+) \(x+12\)\(⋮\)\(x+5\)

\(\left(x+5\right)+7⋮x+5\)

Vì\(x+5⋮x+5\)nên \(7⋮x+5\)

hay \(x+5\in U\left(7\right)=\pm1,\pm7\)sau đó tìm ra tất cả x

(+)\(x+12⋮x-5\)

\(\left(x-5\right)+15⋮x-5\)

vì \(\left(x-5\right)⋮x-5\)

nên \(15⋮x-5\)

hay \(x-5\in U\left(15\right)=\pm1,\pm3,\pm5,\pm15\)sau đó tính x ra

(+)\(3x-5⋮x-4\)

\(\left(3x-12\right)+7⋮x-4\)

Vì\(3x-12⋮x-4\)

nên \(7⋮x-4\)

hay \(x-4\in U\left(7\right)=\pm1,\pm7\)sau đó tính ra x

\(\left(x+\frac{2}{5}\right)^5=\left(x+\frac{2}{5}\right)^3\)

\(\Leftrightarrow\left(x+\frac{2}{5}\right)^3\left[\left(x+\frac{2}{5}\right)^2-1\right]=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{2}{5}=0\\x+\frac{2}{5}=\pm1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-\frac{7}{5};x=-\frac{3}{5}\end{cases}}\)

\(\dfrac{3}{x-5}=\dfrac{-4}{x+2}\left(x\ne5;-2\right).\\ \Leftrightarrow\dfrac{3}{x-5}+\dfrac{4}{x+2}=0.\\ \Leftrightarrow\dfrac{3x+6+4x-20}{\left(x-5\right)\left(x+2\right)}=0.\\ \Rightarrow7x=14.\\ \Leftrightarrow x=2\left(TM\right).\)

5.(x + 4) - 3.(x - 2) = x

5x + 20 - (3x - 6) =x

5x + 20 - 3x + 6 = x

2x + 26 = x

2x - x = (-26)

x = (-26)

Vậy x = (-26)

cảm ơn nhìu lắm

`4x(x-5)-(x-1) (4x-3)-5=0`

`=> 4x*x - 4x*5 - ( x*4x-3*x-1*4x+ 1*3) -5=0`

`=> 4x^2 - 20x-(4x^2 -3x-4x+3)-5=0`

`=>  4x^2 - 20x-4x^2+3x+4x-3-5=0`

`=>-13x-8=0`

`=> -13x=8`

`=> x=-8/13`

Vậy `x=-8/13`

`4x(x-5)-(x-1)(4x-3)-5 = 0`

`=> 4x^2 - 20x - (4x^2 -3x-4x+3)= 5`

`=> 4x^2 - 20x - 4x^2 + 3x + 4x -3 = 5`

`=> (4x^2 - 4x^2) - (20x - 3x - 4x) = 8`

`=> -13x = 8`

`=> x    = -8/13`

-25-(x+5) = 415 + 5(x-83)

=> -25-x-5=415+5x-415

=> -30-x-5x = 0

=> -30=6x

=> x = -5 

`-25-(x+5)=415+5(x-83)`

`<=> -25-x-5=415+5x-415`

`<=> -x-5x=415-415+25+5`

`<=> -6x=30`

`<=> x=-5`

-25 - ( x+5 ) = 415 + 5(x- 83)

\(-25-x-5-415-5x+415=0\)

\(-30-6x=0\)

\(6x=-30\)

\(x=-30:6=-5\)

Vậy x=-5

giúp mình với, đi mà T.T

Sao đến bài này là ko ai giúp mình vậy T.T

\(\dfrac{5}{4}\times x=\dfrac{3}{8}+\dfrac{5}{12}\)

\(\dfrac{5}{4}\times x=\dfrac{19}{24}\)

\(x=\dfrac{19}{24}:\dfrac{5}{4}\)

\(x=\dfrac{19}{30}\)