4/9.14/1/2-4/9.9/2
Những câu hỏi liên quan
Bài 1: Cho: A 13+23+33+...+103
Tính B 23+43+63+...+203 theo A
Bài 2: Tính
A dfrac{2^{12}.3^5-4^6.9^3}{left(2^2.3right)^6+left(8^4.3^5right)} - dfrac{5^{10}.7^3-25^2.49^2}{left(125.7right)^3+5^9.14^3}
B dfrac{2^9.27^3+15.4^9.9^4}{6^9.2^0+12^{10}}
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Đọc tiếp
Bài 1: Cho: A= 13+23+33+...+103
Tính B= 23+43+63+...+203 theo A
Bài 2: Tính
A= \(\dfrac{2^{12}.3^5-4^6.9^3}{\left(2^2.3\right)^6+\left(8^4.3^5\right)}\) - \(\dfrac{5^{10}.7^3-25^2.49^2}{\left(125.7\right)^3+5^9.14^3}\)
B= \(\dfrac{2^9.27^3+15.4^9.9^4}{6^9.2^0+12^{10}}\)
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bài 1
B=23+43+63+...+203=2*(13+23+33+...+103)
=>B=2A
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Tính nhanh : \(\frac{4^5.9^3-12^5}{2^{10}.8^1-2^9.9^2}\)
\(\frac{4^5.9^3-12^5}{2^{10}.8^1-2^9.9^2}=\frac{\left(2^2\right)^5.\left(3^2\right)^3-\left(2^2.3\right)^5}{2^{10}.2^3-2^9.81}\)
\(=\frac{2^{10}.3^6-2^{10}.3^5}{2^{13}-2^9.81}=\frac{2^{10}.3^5\left(3-1\right)}{2^9\left(2^4-81\right)}=\frac{2.3^5.2}{-65}=\frac{-972}{65}\)
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A=2^19.2^7^3-15.(-4)^9.9^4/6^9.2^10+(-12)^10
B=\(\dfrac{2^{19}.27^3+15.4^9.9^4}{6^9+2^{10}.3^{10}}\)
\(B=\dfrac{2^{19}\cdot27^3+15.4^9\cdot9^4}{6^9+2^{10}\cdot3^{10}}\)
\(\Rightarrow B=\dfrac{2^{19}\cdot\left(3^3\right)^3+3\cdot5\cdot4^9\cdot\left(3^2\right)^4}{2^3\cdot3^3+\left(2\cdot3\right)^{10}}\)
\(\Rightarrow B=\dfrac{2^{19}\cdot3^9+3\cdot5\cdot4^9\cdot3^8}{\left(2\cdot3\right)^3+\left(2\cdot3\right)^{10}}\)
\(\Rightarrow B=\dfrac{2^{19}\cdot3^9+5\cdot\left(2^2\right)^9\cdot3^9}{\left(2\cdot3\right)^{13}}\)
\(\Rightarrow B=\dfrac{2^{19}\cdot3^9+5\cdot2^{18}\cdot3^9}{2^{13}\cdot3^{13}}\)
\(\Rightarrow B=\dfrac{2\cdot\left(2^{18}\cdot3^9\right)+5\cdot\left(2^{18}\cdot3^9\right)}{2^{13}\cdot3^{13}}\)
\(\Rightarrow B=\dfrac{\left(2^{18}\cdot3^9\right)\cdot\left(2+5\right)}{2^{13}\cdot3^{13}}\)
\(\Rightarrow B=\dfrac{2^{18}\cdot3^9\cdot7}{2^{13}\cdot3^{13}}=\dfrac{2^{13}\cdot2^5\cdot3^9\cdot7}{2^{13}\cdot3^9\cdot3^4}\)
\(\Rightarrow B=\dfrac{2^5\cdot7}{3^4}\)
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Bài 1 :So sánh
A= 2^19 .27^3+15.4^9.9^4/6^9.2^10+12^10 va B = 4/35+4/63+4/99+4/143+4/195
Bài 2 : tìm x biết :
60%.x+0,4.x +x:3=2
BÀI 2
60%.x + 0,4.x + x:3= 2
\(\frac{60}{100}\)x + \(\frac{4}{10}\).x + x. \(\frac{1}{3}\)=2
\(\frac{3}{5}\).x + \(\frac{2}{5}\).x + x.\(\frac{1}{3}\)=2
(\(\frac{3}{5}\)+ \(\frac{2}{5}\)+ \(\frac{1}{3}\)) .x =2
\(\frac{4}{3}\).x =2
x = 2: \(\frac{4}{3}\)
x = \(\frac{3}{2}\)
Vậy x=\(\frac{3}{2}\)
k cho mik nha các bạn
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Bài 2 :
60%x + 0.4x + x : 3 = 2
\(x.\left(\frac{60}{100}+\frac{2}{5}+\frac{1}{3}\right)\)= 2
\(x.\frac{4}{3}\)= 2
\(x=2.\frac{3}{4}\)
\(x=1.5\)
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n thuộc số tự nhiên, n lớn hơn hoặc bằng 2: 3/9.14+3/14.19+...+3/(5n-1).(5n+4)<1/15.
(2^12.3^5-4^6.9^2)/((2^3.3)^6)-5^10.7^3-25^5.49^2/(125.7)^3+5^9.14^3
\(\dfrac{2^{19}.27^3-15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
\(=\dfrac{2^{19}.\left(3^3\right)^3-3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(3.2^2\right)^{10}}=\dfrac{2^{19}.3^9-5.2^{18}.3^9}{2^{19}.3^9+2^{20}.3^{10}}=\dfrac{2^{18}.3^9\left(2-5\right)}{2^{19}.3^9\left(1+6\right)}=\dfrac{-3}{2.7}=-\dfrac{3}{14}\)
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Giúp mk với:Tính
(6^9.2^10+2^12):(2^19.273+15.4^9.9^4)