\(\frac{4^5.9^3-12^5}{2^{10}.8^1-2^9.9^2}=\frac{\left(2^2\right)^5.\left(3^2\right)^3-\left(2^2.3\right)^5}{2^{10}.2^3-2^9.81}\)
\(=\frac{2^{10}.3^6-2^{10}.3^5}{2^{13}-2^9.81}=\frac{2^{10}.3^5\left(3-1\right)}{2^9\left(2^4-81\right)}=\frac{2.3^5.2}{-65}=\frac{-972}{65}\)