(112/200+0,415):0,01
1/12-37,25+3+1/6
$B=\frac{\left(\frac{11^2}{200}+0,415\right):0.01}{\frac{1}{12}-37,25+3\frac{1}{6}}$B=
(
112
200 +0,415):0.01
1
12 −37,25+3
1
6
giúp em với !!
Tinh :
{112/200+0,415}:0,01
1/2-37,25+3-1/6
{\(\frac{112}{200}\)+ 0,415} : 0,01
= {\(\frac{112}{200}+\frac{415}{1000}\)} : \(\frac{1}{100}\)
={\(\frac{560}{1000}\)+\(\frac{415}{1000}\)} : \(\frac{1}{100}\)
=\(\frac{975}{1000}\): \(\frac{1}{100}\)
=\(\frac{975}{1000}\)x\(\frac{100}{1}\)
=\(\frac{97500}{1000}\)=\(97,5\)
\(\frac{1}{2}-37,5+3-\frac{1}{6}\)
=\(\frac{1}{2}-\frac{375}{10}+\frac{3}{1}-\frac{1}{6}\)
=\(\frac{15}{30}-\frac{1125}{30}+\frac{90}{30}-\frac{5}{30}\)
=\(\frac{15-1125+90-5}{30}\)
=\(\frac{\left(-1110\right)+85}{30}\)
=\(\frac{-1025}{30}\)
Mik ko chắc!!!
(11/200+0,415):0,01/1/12-37,25+31/6
\(\left(\frac{11}{200}+\frac{83}{200}\right):\frac{7}{75}-\frac{149}{4}+\frac{31}{6}\)
\(\frac{94}{200}:\frac{7}{75}-\frac{149}{4}+\frac{31}{6}\)
\(\frac{141}{28}-\frac{149}{4}+\frac{31}{6}\)
\(\frac{-451}{14}+\frac{31}{6}=-27\frac{1}{21}\)
(112/200 +0,415);0,01 = ?
1/12-37,25+3 + 1/6 = ?
Tính:
\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{83}{200}\right):\frac{1}{100}}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}=\frac{\frac{51}{50}.100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)
=\(\frac{102}{-34}=-3\)
Tính :
\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(B=\frac{\left(\frac{11^2}{200}+0,415\right):0.01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(B=\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
Giúp mik nha!!!
Ta có : \(B=\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(=>B=\frac{\left(\frac{121}{200}+\frac{415}{1000}\right):\frac{1}{100}}{\frac{1}{12}-\frac{3725}{100}+\frac{19}{6}}\)
\(=>B=\frac{\left(\frac{121}{200}+\frac{83}{200}\right)\cdot100}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}\)
\(=>B=\frac{\frac{204}{200}\cdot100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)
\(=>B=\frac{\frac{204\cdot100}{200}}{-\frac{408}{12}}=\frac{\frac{204}{2}}{-34}=\frac{102}{-34}=-3\)
bạn biết bấm máy tính không :v
nó bằng : -3
(112+ 0,415) : 0,01
200
1 - 37,25+3+1
12 6