\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{83}{200}\right):\frac{1}{100}}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}=\frac{\frac{51}{50}.100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)

=\(\frac{102}{-34}=-3\)

Bằng -3 nha bạn

Ta có : \(B=\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)

\(=>B=\frac{\left(\frac{121}{200}+\frac{415}{1000}\right):\frac{1}{100}}{\frac{1}{12}-\frac{3725}{100}+\frac{19}{6}}\)

\(=>B=\frac{\left(\frac{121}{200}+\frac{83}{200}\right)\cdot100}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}\)

\(=>B=\frac{\frac{204}{200}\cdot100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)

\(=>B=\frac{\frac{204\cdot100}{200}}{-\frac{408}{12}}=\frac{\frac{204}{2}}{-34}=\frac{102}{-34}=-3\)

bạn biết bấm máy tính không :v

nó bằng : -3

Làm ra cách tính luôn đó

AI GIÚP MÌNH ĐIIIII...........!MÌNH CẦN GẤP LẮM

\(-\frac{10}{17}\)

Ta có: \(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{19}{40}\right).100}{\frac{1}{12}-\frac{149}{4}+\frac{17}{6}}\)

\(=\frac{108}{-\frac{103}{3}}=-\frac{324}{103}\)

{\(\frac{112}{200}\)+ 0,415} : 0,01

= {\(\frac{112}{200}+\frac{415}{1000}\)} : \(\frac{1}{100}\)

={\(\frac{560}{1000}\)+\(\frac{415}{1000}\)} : \(\frac{1}{100}\)

=\(\frac{975}{1000}\): \(\frac{1}{100}\)

=\(\frac{975}{1000}\)x\(\frac{100}{1}\)

=\(\frac{97500}{1000}\)=\(97,5\)

\(\frac{1}{2}-37,5+3-\frac{1}{6}\)

=\(\frac{1}{2}-\frac{375}{10}+\frac{3}{1}-\frac{1}{6}\)

=\(\frac{15}{30}-\frac{1125}{30}+\frac{90}{30}-\frac{5}{30}\)

=\(\frac{15-1125+90-5}{30}\)

=\(\frac{\left(-1110\right)+85}{30}\)

=\(\frac{-1025}{30}\)

Mik ko chắc!!!

{112/200+0,415}:0,01

=39/40:0,01

=9750