giúp mình với
Tính nhanh:
a, (-38)x47+(-38)x52+(-38)
b,29x(-35)+(-29)x64+(-29)
Tính nhanh:
A.38/40x50/57 B.35/32x27/20+35/32x5/20
a: =38/57x40/50=2/3x4/5=8/15
b: =35/32(27/20+5/20)=35/32x32/20=35/20=7/4
Tính nhanh :
a, 29+132+237+868+763
b, 35 * 34 + 35 * 38 + 65 * 75 +45
c, 3 * 25 *8 +4*37*6 +2*38*12
a) 29 + 132 + 237 + 868 + 763
= ( 132 + 868 ) + ( 237 + 763 ) + 29
= 1000 + 1000 + 29
= 1000 x 2 + 29
= 2000 + 29
= 2029
b) 35 x 34 + 35 x 38 + 65 x 75 + 45
= 35 x ( 34 + 38 ) + 65 x 75 + 45
= 35 x 72 + 65 x 75 + 45
= 2520 + 4875 + 45
= 2520 + 4920
= 7440
c) 3 x 25 x 8 + 4 x 37 x 6 + 2 x 38 x 12
= ( 3 x 8 ) x 25 + ( 4 x 6 ) x 37 + ( 2 x 12 ) x 38
= 24 x 25 + 24 x 37 + 24 x 38
= 24 x ( 25 + 37 + 38 )
= 24 x 100
= 2400
a)29+132+237+868+763
=(132+868)+(237+763)+29
= 1000 + 1000 +29
= 2029
a,29+132+237+868+763
=29+(132+868)+(237+763)
=29+1000+1000
=2029
Tính theo cách hợp lí :
a, 90 / 37 - 38/ 25 – 8/25 – 4/25 b, 24/ 29 + 32 / 41 + 34/29 + 50/41
c, 73/24 - 22/29 - 25/24 + 51 / 29
giải giúp mình bài này với
a, \(\dfrac{90}{37}-\dfrac{38}{25}-\dfrac{8}{25}-\dfrac{4}{25}\)
= \(\dfrac{90}{37}\) - \(\dfrac{38+8+4}{25}\)
= \(\dfrac{90}{37}\) - 2
= \(\dfrac{16}{37}\)
\(\dfrac{24}{29}\) + \(\dfrac{32}{41}\) + \(\dfrac{34}{29}\) + \(\dfrac{50}{41}\)
=(\(\dfrac{24}{29}\) + \(\dfrac{34}{29}\)) + (\(\dfrac{32}{41}\) + \(\dfrac{50}{41}\))
= \(\dfrac{58}{29}\) + \(\dfrac{82}{41}\)
= 2 + 2
= 4
c, \(\dfrac{73}{24}\) - \(\dfrac{22}{29}\) - \(\dfrac{25}{24}\) + \(\dfrac{51}{29}\)
= ( \(\dfrac{73}{24}\) - \(\dfrac{25}{24}\)) +( \(\dfrac{51}{29}\) - \(\dfrac{22}{29}\))
= \(\dfrac{48}{24}\) + \(\dfrac{29}{29}\)
= 2 + 1
= 3
a) (-145) – (18 – 145)
b) 111 + (-11 + 27)
c) (27 + 514) – (486 – 73)
d) 10 – [12 – (-9 – 1)]
e) (38 – 29 + 43) – (43 + 38)
f) 271 – [(-43) + 271 – (-17)]
mn giúp mình vs mình đang gấp
bỏ ngoặc rùi tính ạ
giúp vs mai nộp rồi
Bài 1.
a) -x+8=-17
b) 35-x=37
c) x-45=-17
d) |x+1|=20
e) |x-3|-16=-4
Bài 2.
a) (144-97)-144
b) (-145)-(18-145)
c) (27+514)-(486-73
d) (38-29+43)-(43+38)
Bài 1:
a) −x + 8 = −17
−x = −17 − 8
−x = −25
⇒ x = 25
Vậy x = 25
b) 35 − x = 37
x = 35 − 37
x = −2
Vậy x = −2
c) x − 45 = −17
x = −17 + 45
x = 28
Vậy x = 28
d) |x + 1| = 20 (>0)
TH1: x + 1 = 20 TH2: x + 1 = −20
x = 20 − 1 x = −20 − 1
x = 19 x = −21
Vậy x∈\(\left\{-21;19\right\}\)
e) |x − 3| − 16 = −4
|x − 3| = −4 + 16
|x − 3| = 12 (>0)
TH1: x − 3 = 12 TH2: x − 3 = −12
x = 12+3 x = −12 + 3
x = 15 x = −9
Vậy x∈\(\left\{-9;15\right\}\)
b) 35 − x = 37
x = 35 − 37
x = −2
Vậy x = −2
Bài 2:
a) (144 − 97) − 144
= 144 − 97 − 144
= (144 − 144) − 97
= − 97
b) (−145) − (18 − 145)
= −145 − 18 + 145
= (−145 + 145) − 18
= −18
c) (27 + 514) − (486 − 73)
= 27 + 514 − 486 + 73
= (27 + 73) + (514 − 486)
= 100 + 28
= 128
d) (38 − 29 + 43) − (43 + 38)
= 38 − 29 + 43 − 43 − 38
= (−38 + 38) + (−43 + 43) − 29
= 0 + 0 − 29
= −29
24/29 + 7/38 + 31/38 + 5/38
Lời giải:
$\frac{24}{19}+\frac{7}{38}+\frac{31}{38}+\frac{5}{38}$
$=\frac{48}{38}+\frac{7}{38}+\frac{31}{38}+\frac{5}{38}$
$=\frac{48+7+31+5}{38}=\frac{91}{38}$
Tìm X biết
a) x - ( 12 - 25 ) = - 8
b) ( x - 29 ) - ( 17 - 38 ) = - 9
giúp mình.
a) x-(12-25)=-8
<=> x+13=-8
<=> x=-21
b) (x-29)-(17-38)=-9
<=> x-29+21=-9
<=> x-8=-9
<=> x=-1
a, x-(-13)=-8
<=> x+13=-8
<=> x=-8-13
<=>x=-21
Vậy x=-21
b, (x-29)-(17-38)=-9
<=> x-29-(-19)=-9
<=>x-29+19=-9
<=>x-10=-9
<=>x=-9+10
<=> x=1
vậy x=1
a)x-(12-25)=-8
=>x-12+25=-8
=>x-12=-8-25
=>x-12=-33
=>x=-33+12
=>x=-21
Vậy....
b)(x-29)-(17-38)=-9
=>x-29-17+38=-9
=>x-29-17=-47
=>x-29=-30
=>x=-1
Vậy ....
Giải chi tiết giúp mình câu 23, 28, 29, 38, 57, 58, 59, 60, 61, 62, 63, 64 với ạ
mình làm vài câu cho bạn tham khảo,các câu còn lại thì bạn làm tương tự thôi
23.\(\sqrt{14-2\sqrt{33}}=\sqrt{\left(\sqrt{11}\right)^2-2.\sqrt{11}.\sqrt{3}+\left(\sqrt{3}\right)^2}\)
\(=\sqrt{\left(\sqrt{11}-\sqrt{3}\right)^2}=\left|\sqrt{11}-\sqrt{3}\right|=\sqrt{11}-\sqrt{3}\)
28. \(\sqrt{25-4\sqrt{6}}=\sqrt{\left(2\sqrt{6}\right)^2-2.2\sqrt{6}.1+1^2}=\sqrt{\left(2\sqrt{6}-1\right)^2}\)
\(=\left|2\sqrt{6}-1\right|=2\sqrt{6}-1\)
29.\(\sqrt{14-8\sqrt{3}}=\sqrt{14-2\sqrt{48}}=\sqrt{\left(\sqrt{8}\right)^2-2\sqrt{6}.\sqrt{8}+\left(\sqrt{6}\right)^2}\)
\(=\sqrt{\left(\sqrt{8}-\sqrt{6}\right)^2}=\left|\sqrt{8}-\sqrt{6}\right|=\sqrt{8}-\sqrt{6}\)
39 + 38 +37 + 36 + 35 + 34 + 33 + ( - 29 ) + ( - 28 ) + ( - 27 ) + ( - 26 ) + ( - 25 ) + ( - 24 )
= 119
tk mk nha bn
thanks @@@@@@@@@@@@@@@@
119 ( k mik đi ạ )