a: ƯCLN(40;24)=8

ƯC(40;24)=Ư(8)={1;2;4;8}

b: UCLN(80;144)=16

UCLN(80;144)={1;2;4;8;16}

c: UCLN(9;18;72)=9

ƯC(9;18;72)={1;3;9}

d: ƯCLN(25;55;75)=5

ƯC(25;55;75)={1;5}

\(a,40=2^3.5\\ 24=2^3.3\\ \Rightarrow UCLN_{\left(24;40\right)}=2^3=8\\ \RightarrowƯC_{\left(40;24\right)}=Ư_{\left(8\right)}=\left\{1;2;4;8\right\}\\ b,80=2^4.5\\ 144=2^4.3^2\\ \Rightarrow UCLN_{\left(80;144\right)}=2^4=16\\ \RightarrowƯC_{\left(80;144\right)}=Ư_{\left(16\right)}=\left\{1;2;4;8;16\right\}\\ c,9=3^2\\ 18=2.3^2\\ 72=3^2.2^3\\ \Rightarrow UCLN_{\left(8;18;72\right)}=3^2=9\\ \RightarrowƯC_{\left(9;18;72\right)}=Ư_{\left(9\right)}=\left\{1;3;9\right\}\\ d,25=5^2\\ 55=5.11\\ 75=5^2.3\\ \Rightarrow UCLN_{\left(25;55;75\right)}=5\\ \RightarrowƯC_{\left(25;55;75\right)}=Ư_{\left(5\right)}=\left\{1;5\right\}\)

cho 1 vé báo cáo

\(a,ƯC\left(40,24\right)=Ư\left(8\right)=\left\{...\right\}\\ b,ƯC\left(12,52\right)=Ư\left(4\right)=\left\{...\right\}\\ c,ƯC\left(36,990\right)=Ư\left(18\right)=\left\{...\right\}\\ d,ƯC\left(54,36\right)=Ư\left(9\right)=\left\{...\right\}\\ e,ƯC\left(10,20,70\right)=Ư\left(10\right)=\left\{...\right\}\\ f,ƯC\left(25,55,75\right)=Ư\left(5\right)=\left\{...\right\}\\ g,ƯC\left(80,144\right)=Ư\left(16\right)=\left\{...\right\}\\ h,ƯC\left(63,2970\right)=Ư\left(9\right)=\left\{...\right\}\\ i,ƯC\left(65,125\right)=Ư\left(5\right)=\left\{...\right\}\\ j,ƯC\left(9,18,72\right)=Ư\left(9\right)=\left\{...\right\}\\ k,ƯC\left(24,36,60\right)=Ư\left(12\right)=\left\{...\right\}\\ l,ƯC\left(16,42,86\right)=Ư\left(2\right)=\left\{..\right\}\)

a:UC(40;24)=Ư(8)

b: UC(12;52)=Ư(4)

a) 40 và 24

Ta có: 40 = 2³ . 5

          24 = 2³ . 3

=> ƯCLN(40; 24) = 2³ = 8

=> ƯC(40; 24) \(\in\) Ư(8)

=> ƯC(40; 24) \(\in\) Ư(8) = { 1; 2; 4; 8 }

   Các câu còn lại tương tự nha bạn

ƯCLN(24,40)=8

=>ƯC(24,40)=Ư(8)=(1,2,4,8)

các cau khac tuong tu nhe ban

tìm ƯC(24, 40)

Ta có:

40 = 2³.5

24 = 2³.3

=> ƯCLN(40;24) = 2³ = 8

=> ƯC(40;24) = Ư(8) = {1 ; -1 ; 2 ; -2 ; 4 ; -4 ; 8 ; -8}

Nếu bn chưa học tập hợp Z thì ƯC(40;24) = Ư(8) = {1 ; 2 ; 4 ; 8}

40 = 2³ . 5

24 = 2³ . 3

ƯCLN(40, 24) = 2³ = 8

Ư(8) = {1;2;4;8}

Vậy ƯC(40, 24) = {1;2;4;8}

\(40=2^3.5\)

\(24=2^3.3\)

\(\Rightarrow UwCLN\left(40;24\right)=2^3=8\)

\(Ư\left(8\right)=\left\{1;2;4;8\right\}\)

Vậy :............

Lời giải:
a.

$12=2^2.3$; $18=2.3^2$
$\Rightarrow ƯCLN(12,18)=2.3=6$

$\Rightarrow ƯC\in Ư(6)\in \left\{1; 2;3;6\right\}$

b.

$48\vdots 24$ nên $ƯCLN(24,48)=24$

$\Rightarrow ƯC(24,48)\in Ư(24)\in \left\{1; 2; 3; 4; 6; 8;12;24\right\}$

c.

$300=2^2.3.5^2$

$280=2^3.5.7$

$\Rightarrow ƯCLN(300,280)=2^2.5=20$

$\Rightarrow ƯC(300,280)\in Ư(20)\in \left\{1;2;4;5;10;20\right\}$

a) 20 = 2² . 5

48 = 2⁴ . 3

ƯCLN(20,40) = 2² = 4

ƯC(20,40) = Ư(4) = 1,2,4

Mà theo đề bài 0 < x < 4 nên x = { 1 , 2 }

b) 30 = 2 . 5 . 3

24 = 2³ . 3

ƯCLN(30,24) = 2 . 3 = 6

ƯC(30,24) = Ư(6) = 1,2,3,6

Mà theo y/c đề bài 2 < x < 6 nên x = 3

a) Ta có :

40 = 2³ . 5

24 = 2³ . 3

=> ƯCLN ( 40 ; 24 ) = 2³ = 8

=> ƯC ( 40 ; 24 ) = Ư ( 8 ) = { 1 ; 2 ; 4 ; 8 }

b) Ta có :

12 = 2² . 3

52 = 2² . 13

=> ƯCLN ( 12 ; 52 ) = 2² = 4

=> ƯCLN ( 12 ; 52 ) = Ư ( 4 ) = { 1 ; 2 ; 4 }

c) Ta có :

36 = 2² . 3²

990 = 2 . 3² . 5 . 11

=> ƯCLN ( 36 ; 990 ) = 2 . 3² = 18

=> ƯC ( 36 ; 990 ) = Ư ( 18 ) = { 1 ; 2 ; 3 ; 6 ; 9 ; 18 }

d) Ta có :

54 = 2 . 3³

36 = 2² . 3²

=> ƯCLN ( 54 ; 36 ) = 2² . 3³ = 18

=> ƯC ( 54 ; 36 ) = Ư ( 18 ) = { 1 ; 2 ; 3 ; 6 ; 9 ; 18 }

a)40 và 24

ta có:

40=2^3*5

24=2^3*3

=> ƯCLN(40;24) =2^3=8

=>ƯC(40;24)=Ư(8)={1;2;4;8}

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