mong mn trả lời nhanh giúp mình nhé mnnnn

\(\dfrac{5}{8}+\dfrac{7}{24}\) = \(\dfrac{15}{24}\) + \(\dfrac{7}{24}\) = \(\dfrac{22}{24}\) = \(\dfrac{11}{12}\)

\(\dfrac{6}{5}+\dfrac{9}{30}=\dfrac{36}{30}+\dfrac{9}{30}=\dfrac{45}{30}=\dfrac{3}{2}\)

\(\dfrac{7}{12}\) + \(\dfrac{5}{2}\) = \(\dfrac{7}{12}+\dfrac{30}{12}=\dfrac{37}{12}\)

\(\dfrac{9}{21}\) + \(\dfrac{6}{49}\) = \(\dfrac{3}{7}\) + \(\dfrac{6}{49}\) = \(\dfrac{21}{49}\) + \(\dfrac{6}{49}\) = \(\dfrac{27}{49}\)

mnnnnnnnnnnnnnn

Tìm x:

\(\dfrac{4-x}{6-x}\)=\(\dfrac{x-3}{x-8}\)\(\Rightarrow\)(4-x)(x-8)=(6-x)(x-3)

\(\Rightarrow\)12x-x²-32=9x-x²-18

\(\Rightarrow\)3x=14\(\Rightarrow\)x=\(\dfrac{14}{3}\).

\(\dfrac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{48}}\)

=\(\dfrac{7^{48}.5^{30}.2^8-5^{30}.7^{49}.2^{10}}{5^{29}.2^8.7^{48}}\)

=\(\dfrac{7^{48}.5^{30}.2^8.\left(1-7.2^2\right)}{5^{29}.2^8.7^{48}}\)

=5.(1-7.2²) = 5.(1-28) = 5.(-27) = -135

Những khẳng định sau đây là đúng 

26 không chia hết cho 5 ( tận cùng là 6 không chia hết cho 5 )

 30 ⋮ 5  ( tận cùng là 0 chia hết cho năm )

Khẳng định đúng là 

25 ⋮ 5

30 ⋮ 5

Các khẳng định đúng là: 

25 ⋮ 5

30 ⋮ 5

1) \(125^5:25^7\)

\(=\left(5^3\right)^5:\left(5^2\right)^7\)

\(=5^{15}:5^{14}\)

= 5

2) \(27^8:9^9\)

\(=\left(3^3\right)^8:\left(3^2\right)^9\)

\(=3^{24}:3^{18}\)

\(=3^6\)

3) \(36^5:6^8\)

\(=\left(6^2\right)^5:6^8\)

\(=6^{10}:6^8\)

\(=6^2\)

4) \(49^6:7^{10}\)

\(=\left(7^2\right)^6:7^{10}\)

\(=7^{12}:7^{10}=7^2\)

5) \(7^{20}:49^9\)

\(=7^{20}:\left(7^2\right)^9\)

\(=7^{20}:7^{18}=7^2\)

6) \(\frac{1}{2^{10}}:\frac{1}{8^3}\)

\(=\frac{1}{2^{10}}:\frac{1}{\left(2^3\right)^3}\)

\(=\frac{1}{2^{10}}:\frac{1}{2^9}=\frac{1}{2^{10}}.\frac{2^9}{1}=\frac{1}{2}\)

7) \(\left(-\frac{1}{2}\right)^{21}:\frac{1}{4^{10}}\)

\(=\frac{\left(-1\right)^{21}}{2^{21}}:\frac{1}{\left(2^2\right)^{10}}\)

\(=-\frac{1}{2^{21}}:\frac{1}{2^{20}}=-\frac{1}{2^{21}}.\frac{2^{20}}{1}\)

\(=-\frac{1}{2}\)

8) \(\frac{1}{16^5}:\left(-\frac{1}{2}\right)^{18}\)

\(=\frac{1}{\left(2^4\right)^5}:\frac{\left(-1\right)^{18}}{2^{18}}\)

\(=\frac{1}{2^{20}}:\frac{1}{2^{18}}\)

\(=\frac{1}{2^{20}}.\frac{2^{18}}{1}=\frac{1}{4}\)

9) \(\frac{1}{5^{30}}:\frac{1}{25^{14}}\)

\(=\frac{1}{5^{30}}:\frac{1}{\left(5^2\right)^{14}}\)

\(=\frac{1}{5^{30}}:\frac{1}{5^{28}}=\frac{1}{25}\)

Bài 2: 

a: A=(12,87+14,13)+(-14,7-37,3)

=27-52=-25

b: B=-1/3+2/5-2/3-3/5+1/5

=-1

a)\(x-\frac{1}{4}=\frac{5}{8}\)

\(x=\frac{5}{8}+\frac{1}{4}\)

\(x=\frac{7}{8}\)

b)\(\frac{x}{12}=\frac{-1}{24}-\frac{1}{8}\)

\(\frac{x}{12}=\frac{-1}{24}+\frac{-1}{8}\)

\(\frac{x}{12}=\frac{-1}{6}\)

\(x=\frac{-1}{6}\times12\)

\(x=-2\)

a)x-1/4=5/8

=>x=5/8+1/4

x=7/8

b) x/12=-1/24-1/8

=>x/12=-1/6

=>x=-2

c).......... Tự làm

c)

\(\left(\frac{1}{4}-\frac{3}{10}x\right)\times\frac{1}{3}=\frac{-51}{6}+\frac{1}{4}\)

\(\left(\frac{1}{4}-\frac{3}{10}x\right)\times\frac{1}{3}=\frac{-33}{4}\)

\(\frac{1}{4}-\frac{3}{10}x=\frac{-33}{4}\div\frac{1}{3}\)

\(\frac{1}{4}-\frac{3}{10}x=\frac{-33}{4}\times3\)

\(\frac{1}{4}-\frac{3}{10}x=\frac{-99}{4}\)

\(\frac{3}{10}x=\frac{1}{4}-\left(\frac{-99}{4}\right)\)

\(\frac{3}{10}x=\frac{1}{4}+\frac{99}{4}\)

\(\frac{3}{10}x=25\)

\(x=\frac{250}{3}\)