10 . \(\sqrt{x}\) -5=25
1. Tính : \(\dfrac{12}{4-\sqrt{10}}\)-6\(\sqrt{\dfrac{5}{2}}\)+\(\dfrac{5\sqrt{2}+\sqrt{10}}{\sqrt{5}+1}\)
2,Rút gọn:A=(\(\dfrac{\sqrt{x}}{\sqrt{x}-5}\)-\(\dfrac{5}{\sqrt{x}+5}\)+\(\dfrac{10\sqrt{x}}{25-x}\)):\(\dfrac{3}{\sqrt{x}+5}\)
1: \(=8+2\sqrt{10}-3\sqrt{10}+\sqrt{10}=8\)
1,Tính \(\dfrac{12}{4-\sqrt{10}}-6\sqrt{\dfrac{5}{2}}+\dfrac{5\sqrt{2}+\sqrt{10}}{\sqrt{5}+1}\)
2,Rút gọn:A=\(\left(\dfrac{\sqrt{x}}{\sqrt{x}-5}-\dfrac{5}{\sqrt{x}+5}+\dfrac{10\sqrt{x}}{25-x}\right):\dfrac{3}{\sqrt{x}+5}\)
1: \(=8+2\sqrt{10}-3\sqrt{10}+\sqrt{10}=8\)
Rút gọn
\(\dfrac{\sqrt{x}}{\sqrt[]{x}-5}+\dfrac{10\sqrt{x}}{x-25}-\dfrac{5}{\sqrt{x}+5}\)
\(=\dfrac{x+5\sqrt{x}+10\sqrt{x}-5\sqrt{x}+25}{x-25}\)
\(=\dfrac{\left(\sqrt{x}+5\right)^2}{x-25}=\dfrac{\sqrt{x}+5}{\sqrt{x}-5}\)
Rút gọn: \(\dfrac{x-10\sqrt{x}+25}{\left(\sqrt{x}-5\right)\left(\sqrt{x}+5\right)}\)
\(\dfrac{\left(\sqrt{x}+5\right)^2}{\left(\sqrt{x}-5\right)\left(\sqrt{x}+5\right)}\)
\(\dfrac{\sqrt{x}+5}{\sqrt{x}-5}\)
\(\dfrac{\left(\sqrt{x}-5\right)^2}{\left(\sqrt{x}-5\right)\left(\sqrt{x}+5\right)}\)
\(\dfrac{\sqrt{x}-5}{\sqrt{x}+5}\)
Rút gọn : \(\frac{\sqrt{x}}{\sqrt{x}+5}+\frac{10\sqrt{x}}{25-x}-\frac{5}{\sqrt{x}+5}\)
\(=\dfrac{x-10\sqrt{x}+25-10\sqrt{x}}{x-25}=\dfrac{x-20\sqrt{x}+25}{x-25}\)
Rút gọn các biểu thức sau:
a, \(5\sqrt{x}-{(x+10\sqrt{x}+25)(\sqrt{x}-5)\over x-25}\) với 0 ≤ x ≠ 25
b, \({\sqrt{x^2-4x+4}\over x-2}\) với x ≠ 2
/x-25 và /x-2 đấy ạ,máy em bị đánh lỗi. :((
\(5\sqrt{x}-\frac{\left(x+10\sqrt{x}+25\right)\left(\sqrt{x}-5\right)}{x-25}=5\sqrt{x}-\frac{\left(\sqrt{x}+5\right)^2\left(\sqrt{x}-5\right)}{\left(\sqrt{x}-5\right)\left(\sqrt{x}+5\right)}\)
\(=5\sqrt{x}-\left(\sqrt{x}+5\right)=4\sqrt{x}-5\)
\(\frac{\sqrt{x^2-4x+4}}{x-2}=\frac{\sqrt{\left(x-2\right)^2}}{x-2}=\frac{\left|x-2\right|}{x-2}=\orbr{\begin{cases}\frac{x-2}{x-2}\left(x>2\right)\\\frac{2-x}{x-2}\left(x< 2\right)\end{cases}=\orbr{\begin{cases}1\left(x>2\right)\\-1\left(x< 2\right)\end{cases}}}\)
Rút gọn A=\(\left(\frac{5\sqrt{x}+50}{x+5\sqrt{x}}+\frac{2\sqrt{x}-10}{\sqrt{x}}+\frac{x}{5\sqrt{x}+25}\right).\frac{7}{15+3\sqrt{x}}\)
giải phương trình:
1,\(\sqrt{3x-8}\)-\(\sqrt{x+1}\)=\(\dfrac{2x-11}{5}\)
2,3x2-3x+18=10\(\sqrt{x^3+8}\)
3,\(\sqrt{5+2x}\)+\(\sqrt{5-2x}\)+5=3\(\sqrt{25-4x^2}\)
A=\(\frac{\sqrt{x}}{\sqrt{x}-1}-\frac{10\sqrt{x}}{x-25}-\frac{5}{\sqrt{x}+5}\)
Tìm đkxd và rút gọn