Tìm x, biết : x x 125 – x x 25 = 37 800
1) Tính nhanh :
a) 8 x 17 x 125
c) 4 x 37 x 25
d) 43 x 27 + 93 x 43 + 57 x 81 + 69 x 57
e) 123456789 x 45 biết 12345679 x 9 = 111 111 111
7 x 17 x 125 = (8 x 125) x 17 = 1000 x 17 = 17000
4 x 37 x 25 = (25 x 4 ) x 7 = 100 x 7 = 700
43 x 27 + 93 x 43 + 57 x 81 + 69 x 57 = 43 x (27 + 93) + 57 x (81 +69) = 43 x 120 + 57 x 120 + 57x30 = 120 x (43 + 57) + 1710 = 12000 + 1710 = 13710
8. Bỏ dấu ngoặc rồi tính:
a) ( 17 – 229) + ( 17 - 25 + 229) ; b) ( 125 – 679 + 145) – ( 125 – 679 )
9. Tìm x biết: a) 15 – ( 4 – x) = 6 ; b) - 30 + ( 25 – x) = - 1 ;
c) x – ( 12 – 25) = -8 ; d) ( x – 29 ) – ( 17 – 38 ) = - 9
10. Tìm số nguyên x biết: a) x – 5 = - 1 ; b) x + 30 = - 4; c) x – ( - 24) = 3 ; d) 22 – ( - x ) = 12; e) ( x + 5 ) + ( x – 9 ) = x + 2 ; f) ( 27 – x ) + ( 15 + x ) = x – 24 .
a) 25 . 8 - 12 . 5 + 272 : 17 - 8
b) 125 : 25 + 14 - 142 : 71
c) 13 . 17 - 256 : 16 + 14 :7 -1
d) 15 . 24 - 14 . 5 ( 145 : 5 - 27 )
2, Tìm X, biết:
a) 37 + x = 55
b) x - 31 = 24
c) 21 ( x - 11 ) = 21
d) 9 . ( x - 29 ) = 0
e) ( x - 1954 ) . 5 = 50
f) 30 . 60 - x = 30
1a) 25 .8 - 12.5 + 272 :17 - 8
= 200 - 60 + 16 - 8
= 140+16-8
= 156 - 8
= 148
b) 125: 25 +14 - 142 : 71
= 5 + 14 - 2
= 19 - 2 = 17
c) 13. 17 - 256: 16 + 14 : 7 - 1
= 221 - 16 + 2 - 1
= 205 + 2 - 1
= 207 - 1 = 206
d) 15 . 24 - 14 . 5 (145 : 5 - 27)
= 360 - 70 (29- 27)
= 360 - 70 . 2
= 360 - 140
= 220
2a) 37 + x = 55
x= 55 - 37
x = 18
b) x- 31 = 24
x = 24 + 31
x = 55
c) 21 (x-11) = 21
x - 11 = 21 : 21
x = 1 +11
x = 12
d ) 9. (x - 29)= 0
x - 29 = 0 :9
x = 29
e) (x - 1954) . 5 = 50
x - 1954 = 50 : 5
x = 1964
f ) 30 . 60 - x = 30
1800 - x = 30
x = 1800 - 30
x = 1770
Viết mỏi tay quá huhuh
Tìm x biết
0<x<800 thỏa x thuộc N* va x chia hết cho 12; 25 ; 30
/hoi-dap/question/68702.html
bn vào đây tham khảo nha
Vì :
x⋮12,25,30 ( x ∈ N )
=> x ∈ BCNN ( 12 ; 25 ; 30 )
Ta có : 12 = 3.22
25 = 52
30 = 2.3.5
=> BCNN ( 12 ; 25 ; 30 ) = 3.22.52= 300
=> B ( 12 ; 25 ; 30 ) = { 0 ; 300 ; 600 ; 900 ....}
Vì : 0 < x < 800
=> x = 600 .
Vì :
\(x⋮12,25,30\left(x\in N\right)\)
\(\Rightarrow x\in BCNN\left(12,25,30\right)\)
Ta có : \(12=3.2^2\)
\(25=5^2\)
\(30=2.3.5\)
\(\Rightarrow BCNN\left(12,25,30\right)=3.2^2.5^2=300.\)
\(\Rightarrow B\left(12,25,30\right)=\left\{0;300;600;900...\right\}\)
Vì : \(0< x< 800\)
\(\Rightarrow x=600.\)
Tìm x, biết: x + 37 + 25 = 73
A. x = 62
B. x = 11
C. x = 21
D. x = 22
tìm x biết
1) 9-25=(7-x)-(25+7)
2) (27-514) -(486-73)+x=7
3) 25+5+37-25+6-29-x=37
4) 14+(-12)+x =10-/-15/+ /-3/
1) 9-25=(7-x)-(25+7)
(7-x)-(25+7)=9-25
(7-x)-(25+7)=-16
(7-x)-32=-16
7-x=-16+32
7-x=16
x=7-16
x=-9
2) (27-514) -(486-73)+x=7
(27-514) -(486-73)+x=7
-487-413+x=7
-1011+x=7
x=7-(-1011)
x=7+1011
x=1018
3) 25+5+37-25+6-29-x=37
25+5+37-25+6-29-x=37
67-25+6-29-x=37
42+6-29-x=37
48-29-x=37
19-x=37
x=19-37
x=-18
4) 14+(-12)+x =10-/-15/+ /-3/
14+(-12)+x =10-15+3
14+(-12)+x =-5+3
14+(-12)+x =-2
2+x=-2
x=-2-2
x=-4
1, Thực hiện phép tính:
a, -40 + (-37) - (-29)
b, 27 + (-36) - (-45)
c, -125 - [(-18) - 125]
d, 140 + [(-184) - 140]
2, Tìm x biết
a, x - (-15) = -8
b, -40 - x = -35
c, x + (-50) = -27
_Giúp mình vs, mình đang cần gấp lắm í_
Giải
Bài 1
\(1,a,-40-37-\left(-29\right)\\ =-40-37+29\\ =-77+29=-48\\ b,27+\left(-36\right)-\left(-45\right)=27-36+45\\ =-9+45\\ =36\\ c,-125-\left[\left(-18\right)-125\right]\\ =-125+18+125\\ =\left(-125+125\right)+18\\ =18\\ d,140+\left[\left(-184\right)-140\right]\\ =140-184-140\\ =\left(140-140\right)-184\\ =0-184\\ =-184\)
Bài 2
\(a,x-\left(-15\right)=-8\\ =>x+15=-8\\ =>x=-8-15\\ =>x=-23\\ b,-40-x=-35\\ =>x=\left(-40\right)-\left(-35\right)\\ =>x=-40+35\\ =>x=-5\\ c,x+\left(-50\right)=-27\\ =>x-50=-27\\ =>x=-27+50\\ =>x=23\)
1, Thực hiện phép tính:
\(a,-40+\left(-37\right)-\left(-29\right)=-77-\left(-29\right)=-48\)
\(b,27+\left(-36\right)-\left(-45\right)=-9-\left(-45\right)=36\)
\(c,-125-\left[\left(-18\right)-125\right]=-125-\left(-143\right)=18\)
\(d,140+\left[\left(-184\right)-140\right]=140+\left(-324\right)=-184\)
2, Tìm x biết:
\(a,x-\left(-15\right)=-8\)
\(x=-8+\left(-15\right)\)
\(x=-23\)
\(b,-40-x=-35\)
\(x=-40-\left(-35\right)\)
\(x=-5\)
\(c,x+\left(-50\right)=-27\)
\(x=-27-\left(-50\right)\)
\(x=23\)
Bài 1:
a, − 40 − 37 − (− 29)
= − 40 − 37 + 29
= − 77 + 29
= − 48
b, 27 + (− 36) − (− 45)
= 27 − 36 + 45
= − 9 + 45
= 36
c, − 125 − [(− 18) − 125 ]
= − 125 + 18 + 125
= (− 125 + 125) + 18
= 18
d, 140 + [(− 184) − 140]
= 140 − 184 − 140
x.125-x.37=1196
tìm x
37 x 5^4 trên 25 ^ 2
2 ^4 x 2^6 x 3^8 x 9^2 trên 4^4 x 3^11
3 x 9^4 x 9^3 trên 3^2 x 9
125 x 5 x 64 - 25^3 x10 x 4 trên 5^7 x 8
\(\dfrac{37\cdot5^4}{25^2}=\dfrac{37\cdot5^4}{5^4}=37\\ \dfrac{2^4\cdot2^6\cdot3^8\cdot9^2}{4^4\cdot3^{11}}=\dfrac{2^{10}\cdot3^8\cdot3^4}{2^8\cdot3^{11}}=2^2\cdot3=12\\ \dfrac{3\cdot9^4\cdot9^3}{3^2\cdot9}=\dfrac{3\cdot3^8\cdot3^6}{3^2\cdot3^2}=3^{11}\\ \dfrac{125\cdot5\cdot64-25^3\cdot10\cdot4}{5^7\cdot8}=\dfrac{5^3\cdot5\cdot2^6-5^6\cdot2\cdot5\cdot2^2}{5^7\cdot2^3}=\dfrac{5^4\cdot2^3\left(2^3-5^3\right)}{5^7\cdot2^3}=\dfrac{8-125}{5^3}=\dfrac{-117}{125}\)