Giải
Bài 1
\(1,a,-40-37-\left(-29\right)\\ =-40-37+29\\ =-77+29=-48\\ b,27+\left(-36\right)-\left(-45\right)=27-36+45\\ =-9+45\\ =36\\ c,-125-\left[\left(-18\right)-125\right]\\ =-125+18+125\\ =\left(-125+125\right)+18\\ =18\\ d,140+\left[\left(-184\right)-140\right]\\ =140-184-140\\ =\left(140-140\right)-184\\ =0-184\\ =-184\)
Bài 2
\(a,x-\left(-15\right)=-8\\ =>x+15=-8\\ =>x=-8-15\\ =>x=-23\\ b,-40-x=-35\\ =>x=\left(-40\right)-\left(-35\right)\\ =>x=-40+35\\ =>x=-5\\ c,x+\left(-50\right)=-27\\ =>x-50=-27\\ =>x=-27+50\\ =>x=23\)
1, Thực hiện phép tính:
\(a,-40+\left(-37\right)-\left(-29\right)=-77-\left(-29\right)=-48\)
\(b,27+\left(-36\right)-\left(-45\right)=-9-\left(-45\right)=36\)
\(c,-125-\left[\left(-18\right)-125\right]=-125-\left(-143\right)=18\)
\(d,140+\left[\left(-184\right)-140\right]=140+\left(-324\right)=-184\)
2, Tìm x biết:
\(a,x-\left(-15\right)=-8\)
\(x=-8+\left(-15\right)\)
\(x=-23\)
\(b,-40-x=-35\)
\(x=-40-\left(-35\right)\)
\(x=-5\)
\(c,x+\left(-50\right)=-27\)
\(x=-27-\left(-50\right)\)
\(x=23\)
Bài 1:
a, − 40 − 37 − (− 29)
= − 40 − 37 + 29
= − 77 + 29
= − 48
b, 27 + (− 36) − (− 45)
= 27 − 36 + 45
= − 9 + 45
= 36
c, − 125 − [(− 18) − 125 ]
= − 125 + 18 + 125
= (− 125 + 125) + 18
= 18
d, 140 + [(− 184) − 140]
= 140 − 184 − 140
Bài 1
a)-40+(-37)-(-29)
=-40+(-37)+29
=-77+29
=-48
b)27+(-36)-(-45)
=27+(-36)+45
=-9+45
=36
c)-125-[(-18)-125]
=-125+18+125
=18+[(-125)+125]
=18+0
=18
d)140+[(-184)-140]
=140+(-184)-140
=(-184)+(140-140)
=(-184)+0
=(-184)
Bài 2
a)x-(-15)=-8
x + 15 =-8
x = -8 -15
x = -23
b)-40-x=-35
x=-40-(-35)
x=-5
c)x+(-50)=-27
x =-27-(-50)
x =23
