Cho (P): y=x^2/2 va duong thang (d): y=mx+1/2 a) Ve (P) b) CM: voi moi m duong thang (d) luon di qua mot diem co dinh c) CM: voi moi m (d) luon cat (P) tai hai diem phan biet
Cau 5: Trong cac khang dinh sau, khang dinh nao dung, khang dinh nao sai?
1.Ba diem phan biet la ba diem thang hang.
2.Voi ba diem phan biet luon co hai diem nam ve cung phia doi voi diem con lai.
3.Voi ba diem thang hang phan biet luon co hai diem nam khac phia voi diem con lai.
4.Voi ba diem A,B,C thang hang thi diem B luon nam giua hai diem A,C.
5.Co mot va chi mot duong thang di qua hai diem (phan biet) cho truoc.
6.Hai duong thang phan biet thi song song voi nhau.
7.Hai tia chung goc thi cung nam tren mot duong thang.
8.Hai tia chung goc thi doi nhau
9.Neu diem M nam giua diem A,B thi no la trung diem cua doan thang AB.
10.Neu MA=MB thi M la trung diem cua doan thang AB.
11.Neu MA+MB= AB va MA=MB thi M la trung diem cua doan thang AB.
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cho hai duong thang : (d1) : y = 4mx -(m+5) (d2): y =(3m^2 +1)x + (m^2 +9) a,voi gia tri naocua m thi (d1)//(d2) , b,voi gia tri nao cua m thi (d1) cat (d2) tim toa do giao diem khi m =2 , c, C /m rang khi m thay doi thi duong thang (d1) luon di qua diem co dinh A ,(d2) d qua diem co di B .Tinh AB ?
cho tam giac ABC co AB = AC . Tren canh BC lay D va tren tia doi cua BC lay E sao cho BD = BE . Cac duong thang vuong goc voi BC ke tu D va E cat AB ; AC lan luot tai M va N . Chung minh :
a/ DM=ED
b/duong thang BC cat MN tai diem I la trung diem cua MN
c/duong thang vuong goc voi MN tai I luon luon di qua mot diem co dinh khi D thay doi tren BC .
help me !!!
bạn kiểm tra lại đề đi ? mình thấy hơi sai sai
cho tam giac ABC can tai A.tren canh bc lay diem D trên tiadoi cua CB lay diem E sao cho BD = CE tu D va E ke cac duong thang vuong goc voi BC lan luot cat AB o M cat AC o N. I la trung diem cua MN.CMR duong thang vuong goc voi MN tai I luon di qua 1 diem co dinh khi D thay đoi trên canh BC
Cho (O) duong kinh AB. Ve duong thang d vuong goc voi AB tai B, ve duong kinh MN bat ky khong trung voi AB. Cac tia AM va AN cat d theo thu tu tai cac diem E va F
1, Tu giac AMBN la hinh gi?
2, Chung minh Tu giac MNFE noi tiep
3, Chung minh AM . EF = AF.MN
4, Chung minh: Khi duong kinh MN quay quanh O nhung khong trung voi AB thi tam duong tron di qua 4 diem M,N,F,E luon nam tren 1 duong thang co dinh
Cho (O) duong kinh AB. Ve duong thang d vuong goc voi AB tai B, ve duong kinh MN bat ky khong trung voi AB. Cac tia AM va AN cat d theo thu tu tai cac diem E va F
1, Tu giac AMBN la hinh gi?
2, Chung minh Tu giac MNFE noi tiep
3, Chung minh AM . EF = AF.MN
4, Chung minh: Khi duong kinh MN quay quanh O nhung khong trung voi AB thi tam duong tron di qua 4 diem M,N,F,E luon nam tren 1 duong thang co dinh
Cho (O) duong kinh AB. Ve duong thang d vuong goc voi AB tai B, ve duong kinh MN bat ky khong trung voi AB. Cac tia AM va AN cat d theo thu tu tai cac diem E va F
1, Tu giac AMBN la hinh gi?
2, Chung minh Tu giac MNFE noi tiep
3, Chung minh AM . EF = AF.MN
4, Chung minh: Khi duong kinh MN quay quanh O nhung khong trung voi AB thi tam duong tron di qua 4 diem M,N,F,E luon nam tren 1 duong thang co dinh
a)Xét (O) có, ^AMB=^ANB=^NBM=^NAM=90 độ ( góc nội tiếp chắn nửa đt)
Xét tứ giác ANBM có : ^AMB=^ANB=^NBM=90 độ (cmt)
=> TG ANBM là hcn
Giúp mình với!
cho tam giac ABC noi tiep duong tron tam O, mot diem I chuyen dong tren cung BC khong chua diem A(I khac B,C).Duong thang vuong goc voi IB tai I cat duong thang AC tai E, duong thang vuong goc voi IC cat duong thang AB tai F.Chung minh rang duong thang EF luon di qua 1 diem co dinh
1) viet phuong trinh duong thang di qua M(-1;1) va vuong goc voi duong thang y=2x-1
2)viet phuong trinh duong thang (d) song song duong thang y=3x+1 cat truc tung tai diem co tung do la 4
3) tim m de y=mx+1 va y=2x-1 cat nhau tai diem thuoc y=-x
1) gọi đường thẳng cần tìm là y=ax+b(d1)
vì đt d1 vuông góc vs đt y=2x-1 nên:
a.2=-1 <=> a= \(\dfrac{-1}{2}\)
vì đt d1 đi qua điểm M (-1;1) nên ta có pt:
1=\(\dfrac{-1}{2}\) .(-1)+b <=> b=\(\dfrac{1}{2}\)
Vậy h/s cần tìm là y=\(\dfrac{-1}{2}\) x+\(\dfrac{1}{2}\)
2) gọi đường thẳng cần tìm là y=ax+b(d)
vì đt d // đt y=3x+1 nên:
a=3
vì đt d cắt trục tung tại điểm có tung độ bằng 4 nên : b=4
vậy h/s cần tìm là y=3x+4
3) đk :m\(\ne\)2
vì đt y=2x-1 cắt tại tung độ tại điểm có tung độ bằng -x nên ta có pt :
-x=2x-1 <=> x=\(\dfrac{1}{3}\)
Ta có đt y=mx+1 cắt tại tung độ tại điểm có tung độ bằng -x nên ta có pt :
-\(\dfrac{1}{3}\) =m.\(\dfrac{1}{3}\) +1 <=> m=-4 (tmđk )
Vậy để y=mx+1 va y=2x-1 cắt nhau tại điểm thuộc y=-x thì m= -4