Nguyễn Thị Ngọc Thơ

ĐK: \(x\ge-\frac{1}{3}\)

\(PT\Leftrightarrow\sqrt{x+3}-2+\sqrt{3x+1}-2=0\)

\(\Leftrightarrow\frac{x-1}{\sqrt{x+3}+1}+\frac{3\left(x-1\right)}{\sqrt{3x+1}+2}=0\)

\(\Leftrightarrow\left(x-1\right)\left(\frac{1}{\sqrt{x+3}+2}+\frac{3}{\sqrt{3x+1}+2}\right)=0\)

\(\Leftrightarrow x=1\left(tm\right)\)