a: \(-317+402-583+98\)

\(=\left(-317-583\right)+\left(402+98\right)\)

\(=-900+500=-400\)

b: \(-200-\left(1861-655\right)+61-2655\)

\(=-200-1861+655+61-2655\)

\(=-200-\left(1861-61\right)+\left(655-2655\right)\)

\(=-200-1800-2000\)

=-4000

-4000

bằng \(-4000\)

=-200-1861+655+61-2655

=-200-(1861-61)-(-2655+655)

=-200-1800-2000

=-4000

-200-(1861-655)+61-2655

= -200-1861+655+61-2655

= -200+(-1861+61)+(-2655+655)

= -200+(-1800)+(-2000)

= -2000+(-2000)=-4000

a) (-124) + 24 = -100
b) 37. 78 + 37. 22
=  37 . ( 78 + 22 )
=  37 . 100
= 3700

\(a) (-124) + 24 = -100 b) 37. 78 + 37. 22 = 37 . ( 78 + 22 ) = 37 . 100 = 3700\)

a) (- 124) + 24                                          b) 37 . 78 + 37 . 22

= - ( 124 - 24)                                              =37 . ( 78 + 22)

= - 100                                                        =37 . 100 

                                                                    3700

\(=-\dfrac{1}{3}+\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{3}{4}=1\)

\(\dfrac{-4}{12}-\left(-\dfrac{13}{39}-0.25\right)+0.75\)

\(=\dfrac{-1}{3}+\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{3}{4}\)

=1

a) \(583+27+417+73\)

\(=\left(583+417\right)+\left(73+27\right)\)

\(=1000+100\)

\(=1100\)

b) \(125\cdot25\cdot4\cdot8\cdot7\)

\(=\left(125\cdot8\right)\cdot\left(25\cdot4\right)\cdot7\)

\(=1000\cdot100\cdot7\)

\(=700000\)

c) \(87-\left[61+\left(7-4\right)^2\right]\)

\(=87-\left(61+3^2\right)\)

\(=87-\left(61+9\right)\)

\(=87-70\)

\(=17\)

d) \(135\cdot47+135\cdot52+135\cdot2021^0\)

\(=135\cdot\left(47+52+2021^0\right)\)

\(=135\cdot\left(99+1\right)\)

\(=135\cdot100\)

\(=13500\)

a. (583+417)+(27+73)

=  1000  +  100

=  1100

b. (125.8).(25.4.7)

=  1000 . 700

=  700 000

c. 87-(61+3 mũ 2) mình ko có ngoặc vuông nên dùng ngoặc tròn cậu vẫn ghi là ngoặc vuông nhé

=  87-(61+9)

=  87-70

=  17

d. 135.47+135.52+135.1

= 135.(47+52+1)

= 135.100

= 13 500

a,1100

b,700,000

c,17

d,2480

d) -37 . (-19) + 37 . (-119)

= -37.(-19 + 119)

= -37 . 100

= -3700