tim x E Z biet
\(a,\frac{2x-12}{x-3}=\frac{x-3}{2x-12}\)
\(b,\frac{3x+4}{x-16}=\frac{x-16}{3x+4}\)
1,Giải Pt
a,\(\frac{3x-7}{2}+\frac{x+1}{3}=-16\)
b,\(x-\frac{x+1}{3}=\frac{2x+1}{5}\)
c,\(\frac{7-3x}{12}+\frac{3}{4}=2\left(x-2\right)+\frac{5\left(5-2x\right)}{6}\)
e,\(\frac{3\left(x+3\right)}{4}+\frac{1}{2}=\frac{5x+9}{3}-\frac{7x-9}{4}\)
1 . \(\frac{x-1}{12}-\frac{2x-12}{14}=\frac{3x-14}{25}-\frac{3x-12}{27}\)
2 . \(\frac{2x-1}{2}+\frac{2x+1}{3}=\frac{2x+7}{6}+\frac{2x+9}{7}\)
3 . \(\frac{x^2+x+4}{2}+\frac{x^2+x+7}{3}=\frac{x^2+x+13}{5}+\frac{x^2+x+16}{6}\)
4 . \(\frac{201-x}{99}+\frac{203-x}{97}+\frac{205-x}{95}+3=0\)
1.
a) \(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x+4}\)
b) \(\left|12-5x\right|=4-x\)
c) \(\frac{3x+5}{2}-1\le\frac{x+2}{3}+x\)
Bài 1: Thực hiện phép tính
a. \(\frac{11x+10}{3x-3}+\frac{15x+13}{4-4x}\)
b. \(\frac{5x+3}{x^2-3x}+\frac{9-x}{9-3x}\)
c. \(\frac{4xy-1}{5x^2y}-\frac{2xy-1}{5x^2y}\)
d. \(\frac{x+8}{x^2-16}-\frac{2}{x^2+4x}\)
e. \(\frac{x^2-49}{2x+1}.\frac{3}{7-x}\)
f. \(\frac{3x^2-2x}{x^2-1}.\frac{1-x^4}{\left(2-3x\right)^3}\)
g. \(\frac{5xy}{2x-3}:\frac{15xy^3}{12-8x}\)
h. \(\frac{x^2+2x}{3x^2-6x+3}:\frac{2x+4}{5x-5}\)
Các ĐKXĐ: bạn tự tìm
a)
\(\frac{11x+10}{3x-3}+\frac{15x+13}{4-4x}=\frac{11x+10}{3(x-1)}-\frac{15x+13}{4(x-1)}=\frac{4(11x+10)-3(15x+13)}{12(x-1)}\)
\(=\frac{-x+1}{12(x-1)}=\frac{-(x-1)}{12(x-1)}=\frac{-1}{12}\)
b)
\(\frac{5x+3}{x^2-3x}+\frac{9-x}{9-3x}=\frac{5x+3}{x(x-3)}+\frac{x-9}{3x-9}=\frac{5x+3}{x(x-3)}+\frac{x-9}{3(x-3)}\)
\(=\frac{3(5x+3)}{3x(x-3)}+\frac{x(x-9)}{3x(x-3)}=\frac{x^2+6x+9}{3x(x-3)}=\frac{(x+3)^2}{3x(x-3)}\)
c)
\(\frac{4xy-1}{5x^2y}-\frac{2xy-1}{5x^2y}=\frac{(4xy-1)-(2xy-1)}{5x^2y}=\frac{2xy}{5x^2y}=\frac{2}{5x}\)
d)
$\frac{x+8}{x^2-16}-\frac{2}{x^2+4x}=\frac{x+8}{(x-4)(x+4)}-\frac{2}{x(x+4)}$
$=\frac{x(x+8)}{x(x-4)(x+4)}-\frac{2(x-4)}{x(x+4)(x-4)}$
$=\frac{x^2+8x-2(x-4)}{x(x+4)(x-4)}=\frac{x^2+6x+8}{x(x+4)(x-4)}$
$=\frac{(x+2)(x+4)}{x(x+4)(x-4)}=\frac{x+2}{x(x-4)}$
e)
$\frac{x^2-49}{2x+1}.\frac{3}{7-x}=\frac{(x-7)(x+7)}{2x+1}.\frac{-3}{x-7}$
$=\frac{-3(x+7)}{2x+1}$
f)
$\frac{3x^2-2x}{x^2-1}.\frac{1-x^4}{(2-3x)^3}$
$=\frac{2x-3x^2}{x^2-1}.\frac{x^4-1}{(2-3x)^3}=\frac{x(2-3x)(x^2-1)(x^2+1)}{(x^2-1)(2-3x)^3}$
$=\frac{x(x^2+1)}{(2-3x)^2}$
g)
$\frac{5xy}{2x-3}:\frac{15xy^3}{12-8x}=\frac{5xy}{2x-3}.\frac{12-8x}{15xy^3}$
$=\frac{5xy}{2x-3}.\frac{-4(2x-3)}{15xy^3}=\frac{-4}{3y^2}$
h)
$\frac{x^2+2x}{3x^2-6x+3}:\frac{2x+4}{5x-5}=\frac{x(x+2)}{3(x-1)^2}:\frac{2(x+2)}{5(x-1)}$
$=\frac{x(x+2)}{3(x-1)^2}.\frac{5(x-1)}{2(x+2)}$
$=\frac{5x}{6(x-1)}$
Bài 1: Thực hiện các phép tính sau
a.\(\frac{11x+10}{3x-3}+\frac{15x+13}{4-4x}\)
b.\(\frac{5x+3}{x^2-3x}+\frac{9-x}{9-3x}\)
c.\(\frac{4xy-1}{5x^2y}-\frac{2xy-1}{5x^2y}\)
d.\(\frac{x+8}{x^2-16}-\frac{2}{x^2+4x}\)
e.\(\frac{x^2-49}{2x+1}.\frac{3}{7-x}\)
f.\(\frac{3x^2-2x}{x^2-1}.\frac{1-x^4}{\left(2-3x\right)^3}\)
g.\(\frac{5xy}{2x-3}:\frac{15xy^3}{12-8x}\)
h.\(\frac{x^2+2x}{3x^2-6x+3}:\frac{2x+4}{5x-5}\)
rút gọn các phân thức sau:
a) \(A=\frac{x^2-9}{x^2-6x+9}\)
b) \(B=\frac{9x^2-16}{3x^2-4x}\)
c) \(C=\frac{x^2+4x+4}{2x+4}\)
d) \(D=\frac{2x-x^2}{x^2-4}\)
e)\(E=\frac{3x^2+6x+12}{x^3-8}\)
giải hộ e vs ạ
Trả lời:
a, \(A=\frac{x^2-9}{x^2-6x+9}=\frac{\left(x-3\right)\left(x+3\right)}{\left(x-3\right)^2}=\frac{x+3}{x-3}\)
b, \(B=\frac{9x^2-16}{3x^2-4x}=\frac{\left(3x-4\right)\left(3x+4\right)}{x\left(3x-4\right)}=\frac{3x+4}{x}\)
c, \(C=\frac{x^2+4x+4}{2x+4}=\frac{\left(x+2\right)^2}{2\left(x+2\right)}=\frac{x+2}{2}\)
d, \(D=\frac{2x-x^2}{x^2-4}=\frac{x\left(2-x\right)}{\left(x-2\right)\left(x+2\right)}=-\frac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=-\frac{x}{x+2}\)
e, \(E=\frac{3x^2+6x+12}{x^3-8}=\frac{3\left(x^2+2x+4\right)}{\left(x-2\right)\left(x^2+2x+4\right)}=\frac{3}{x-2}\)
Giải phương trình:
a) \(\frac{x+5}{4}\) - \(\frac{2x-5}{3}\) = \(\frac{6x-1}{3}\) + \(\frac{2x-3}{12}\)
b) \(\frac{2x+3}{3}\) = \(\frac{5-4x}{2}\)
c) \(\frac{3x-2}{6}\) - 5 = \(\frac{3-2\left(x+7\right)}{4}\)
d) 5x - 4 (6 - x) (x + 3) = (4 - 2x) (3 - 2x) + 2
e) \(\frac{5x+6}{7}-\frac{3x+1}{4}\) = \(\frac{x+16}{5}\)
a) \(\frac{x+5}{4}\)-\(\frac{2x-5}{3}\)=\(\frac{6x-1}{3}\)+\(\frac{2x-3}{12}\)
⇔\(\frac{3\left(x+5\right)}{12}\)-\(\frac{4\left(2x-5\right)}{12}\)=\(\frac{4\left(6x-1\right)}{12}\)+\(\frac{2x-3}{12}\)
⇒ 3x+15-8x+20=24x-4+2x-3
⇔3x+15-8x+20-24x+4-2x+3=0
⇔-31x+42=0
⇔x=\(\frac{42}{31}\)
Vậy tập nghiệm của phương trình đã cho là:S={\(\frac{42}{31}\)}
b) \(\frac{2x+3}{3}\)=\(\frac{5-4x}{2}\)
⇔\(\frac{2\left(2x+3\right)}{6}\)=\(\frac{3\left(5-4x\right)}{6}\)
⇒4x+6=15-12x
⇔16x=9
⇔ x=\(\frac{9}{16}\)
Vậy tập nghiệm của phương trình đã cho là:S={\(\frac{9}{16}\)}
Phạm Thái Hải hay lm 2 câu trog 4 hay 5 câu thôi nhỉ
\(c,\frac{3x-2}{6}-5=\frac{3-2\left(x+7\right)}{4}\)
\(2\left(3x-2\right)-60=3\left(-2x-11\right)\)
\(6x-4-60=-6x-33\)
\(6x-4-60+6x+33=0\)
\(12x-31=0\)
\(x=\frac{31}{12}\)
1 . \(\frac{x-1}{12}-\frac{2x-12}{14}=\frac{3x-14}{25}-\frac{4x-25}{27}\)
2 . \(\frac{3}{x-1}+\frac{4}{x-2}=\frac{5}{x-3}+\frac{6}{x-4}\)
3 . \(\frac{2x-1}{2}+\frac{2x+1}{3}=\frac{2x+7}{6}+\frac{2x+9}{7}\)
4 . \(\frac{x^2+x+4}{2}+\frac{x^2+x+7}{3}=\frac{x^2+x+13}{5}+\frac{x^2+x+16}{6}\)
a)\(\frac{3x-2}{16}=\frac{-4}{2x-3}\)
b)2/x-1/-3x=7
c)/5x-3/=/7-x/
d)\(\frac{x}{y}=\frac{9}{7};\frac{y}{z}=\frac{7}{3};x+y-z=-15\)
e)\(\frac{x}{-3}=\frac{y}{-8};x^2-y^2=\frac{-44}{5}\)
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