Bài1:Rút gọn
a,(4x-5)(3x+2)-(7-3x)(x+2)
b,(-2x+1)(x-5)-3(x-2)(x+1)
c,(x^2-7)(x-5)+(3x^2+5)(2x-4)
d,(x^2+3x-2)(x+4)-4x(x-5)
Bài2:Tìm xbiết
a,(x-4)(x+3)-(x+1)(x-5)=8
b,(3x-2)(x+1)-3x(x+7)=13
c,(x+5)(x-5)-x(x+2)=9
d,(x-1)(x^2+x+1)-x(x^2-3)=1
2:
a: =>x^2+3x-4x-12-(x^2-5x+x-5)=8
=>x^2-x-12-x^2+4x+5=8
=>3x-7=8
=>3x=15
=>x=5
b: =>3x^2+3x-2x-2-3x^2-21x=13
=>-20x=15
=>x=-3/4
c: =>x^2-25-x^2-2x=9
=>-2x=25+9=34
=>x=-17
d: =>x^3-1-x^3+3x=1
=>3x-1=1
=>3x=2
=>x=2/3
\(1, (-x+5)(x-2)+(x-7)(x+7)=(3x+1)^2-(3x-2)(3x+2)\)
\(2, (5x-1)(x+1)-2(x-3)^2=(x+2)(3x-1)-(x+4)^2+(x^2-x)\)
3, \((x-7)(x+1)-(x-3)^2=(3x-5)(3x+5)-(3x+1)^2 +(x-2)^2-x^2\)
1: \(A=\left(-x+5\right)\left(x-2\right)+\left(x-7\right)\left(x+7\right)\)
\(=-x^2+2x+5x-10+x^2-49=7x-59\)
\(B=\left(3x+1\right)^2-\left(3x-2\right)\left(3x+2\right)\)
\(=9x^2+6x+1-9x^2+4=6x+5\)
=>7x-59=6x+5
=>x=64
2: \(A=\left(5x-1\right)\left(x+1\right)-2\left(x-3\right)^2\)
\(=5x^2+5x-x-1-2x^2+12x-9\)
\(=3x^2+16x-10\)
\(B=\left(x+2\right)\left(3x-1\right)-\left(x+4\right)^2+x^2-x\)
\(=3x^2-x+6x-2-x^2-8x-16+x^2-x\)
\(=3x^2-4x-18\)
=>16x-10=-4x-18
=>20x=-8
hay x=-2/5
Dùng hằng đẳng thức rút gọn và tính giá trị biểu thức:
1) (4x-1)2-2(4x-1)(3x-7)+7-3x)2 Tại x=44
2) (2x-5)2-2(2x-5)(3x-4)+(4-3x)2 Tại x=24
3) (x-4))2-2(x-4)(5-3x)+(5-3x)2 Tại x=16
4) ( 6x-5)2-2(5x-4)+(4-5x)2 Tại x=36
5) ( 7-3x)2+2(3x-7)(7+2x)+(2x+7)2 Tại x=15
6) (x-3)2+2(x-3)(3-2x)+(2x-3)2 Tại x=95
7) (3x-7)2+2(3x-7)(7-5x)+(5x-7)2 Tại x=50
8) (3x-5)2+2(3x-5)(5-2x)+(2x-5)2 Tại x=85
9) (5x-2)2+2(5x-2)(2-3x)+(3x-2)2 Tại x=25
10) ( 7x-5)2+2(7x-5)(5-6x)+(6x-5)2 Tại x=75
Chứng tỏ biểu thức không phụ thuộc x:
6) (3x-5)(8x+4)-4x(6x-7)
7) (4-3x)(3x+4)=9x2-15
8) (x-1)(x2+x+1)-(x+1)(x2-x+1)
9) (x-3)(x+3)-x(x+1)+x
10) (2x-5)(2x+5)-4x(x+5)+20x
câu 1:giải các pt và bpt sau: a,17x - 5(x+3)= 2x + 5 b,3/x+2 - 5/x-2 = 11x + 23/(x+2)(x-2) c,5x + 7 ≥ 3(x-1) d,3x-1/x+1 = -2/5 e,(2x-1)(2x+1)= 4x2 + 3x + 2 f,x-3^3 -7+3x g,7x-5 < 2(4x-1)+7
a: =>17x-5x-15-2x-5=0
=>10x-20=0
=>x=2
b: =>\(\dfrac{3x-6-5x-10}{\left(x+2\right)\left(x-2\right)}=\dfrac{11x+23}{\left(x+2\right)\left(x-2\right)}\)
=>11x+23=-2x-16
=>13x=-39
=>x=-3(nhận)
c: =>5x+7>=3x-3
=>2x>=-10
=>x>=-5
d: =>5(3x-1)=-2(x+1)
=>15x-5=-2x-2
=>17x=3
=>x=3/17
e: =>4x^2-1-4x^2-3x-2=0
=>-3x-3=0
=>x=-1
g: =>7x-5-8x+2-7<0
=>-x-10<0
=>x+10>0
=>x>-10
câu 1:giải các pt và bpt sau:
a,17x - 5(x+3)= 2x + 5
b,3/x+2 - 5/x-2 = 11x + 23/(x+2)(x-2)
c,5x + 7 ≥ 3(x-1)
d,3x-1/x+1 = -2/5
e,(2x-1)(2x+1)= 4x2 + 3x + 2
f,x-3^3 -7+3x
g,7x-5 < 2(4x-1)+7
a: =>17x-5x-15-2x-5=0
=>10x-20=0
=>x=2
b: =>\(\dfrac{3x-6-5x-10}{\left(x+2\right)\left(x-2\right)}=\dfrac{11x+23}{\left(x+2\right)\left(x-2\right)}\)
=>11x+23=-2x-16
=>13x=-39
=>x=-3(nhận)
c: =>5x+7>=3x-3
=>2x>=-10
=>x>=-5
d: =>5(3x-1)=-2(x+1)
=>15x-5=-2x-2
=>17x=3
=>x=3/17
e: =>4x^2-1-4x^2-3x-2=0
=>-3x-3=0
=>x=-1
g: =>7x-5-8x+2-7<0
=>-x-10<0
=>x+10>0
=>x>-10
bài 2 giải các phương trình sau
b,2(x+3)-4=0
d,5(x-3)=3x-5
f,7(5-x)=11-5x
h,2(3x-1)-3x=10
j,3-2x=3.(x+1)-x-2
m,4(2x-3)-5=6(3-x)-7
b)x+3=4:2
=> x=-1
d)5x-15=3x-5
<=> 5x-3x=15-5
<=> 2x=10
<=> x=5
f) 35-7x=11-5x
<=> 35-11=-5x+7x
<=> 24=2x
<=> x=12
h) 6x-2-3x=10
<=> 3x=10+2
<=> x=4
j)3-2x=3x+3-x-2
<=> 3-2x=2x+1
<=>-4x=-2
<=> x=1/2
rút gọn biểu thức
a)(2x-3)(x-2)
b)2x(5-3x)-3(x-7)
c)3x(2-3x)+3x(3x-2)-5(x-7)
a) (2x-3)(x-2) = 2x2 - 3x - 4x +6 = 2x2 - 7x +6
b)2x(5-3x)-3(x-7) = 10x-6x2-3x+21= -6x2+7x+21
c)3x(2-3x)+3x(3x-2)-5(x-7) = 3x(2-3x) - 3x(2-3x) - 5(x-7)= -5(x-7)= -5x + 35
tìm x thuộc Z biết :
a)|3x+5|-2(x+7)-4(7-x)=|3x+5|+2x
b)|x^2-4|+(x-2)^2=0
c)|x+7|+|x+5|+|x+3|=2x
d)|3x+5|=5-3x
1.Tìm x
a) (x - 5)(x + 5) - (x + 3)^2 + 3 (x - 2)^2 = (x + 1)^2 - (x + 4)(x - 4) +3x^2
b) (2x + 3)^2 + (x - 1)(x + 1) = 5 (x + 2)^2 - (x - 5)(x + 1) + (x + 4)^2
c) (-x + 5)(x - 2) + (x - 7)(x + 7) = (3x + 1)^2 - (3x - 2)(3x + 2)
d) (5x - 1)(x + 1) - 2(x - 3)^2 = (x + 2)(3x - 1) - (x + 4)^2 + (x^2 - x)
2.Rút gọn :
a) A= 3 (x - 1)^2 - (x + 1)^2 + 2(x - 3)(x + 3) - (2x + 3)^2 - (5 - 20x)
b) B= 5x (x - 7)(x + 7) - x (2x - 1)^2 - (x^3 + 4x^2 - 246x) - 175
c) C = -2x (3x + 2)^2 + (4x + 1)^2 + 2 (x^3 + 8x + 3x - 2 ) - (5 - x)
d) (3x – 5)(7 – 5x) – (5x + 2)(2 – 3x) = 4 g) 3(2x - 1)(3x - 1) - (2x - 3)(9x - 1) =0 j) (2x – 1)(3x + 1) – (4 – 3x)(3 – 2x) = 3 k) (2x + 1)(x + 3) – (x – 5)(7 + 2x) = 8 m) 2(3x – 1)(2x + 5) – 6(2x – 1)(x + 2) = - 6
g: Ta có: \(3\left(2x-1\right)\left(3x-1\right)-\left(2x-3\right)\left(9x-1\right)=0\)
\(\Leftrightarrow3\left(6x^2-5x+1\right)-\left(18x^2-29x+3\right)=0\)
\(\Leftrightarrow18x^2-15x+3-18x^2+29x-3=0\)
\(\Leftrightarrow14x=0\)
hay x=0