Tim x biet 11/10,5=6,32/x
11/10,5=6,32/x
\(\frac{11}{10,5}=\frac{6,32}{x}\)
\(\Rightarrow11x=10,5\times6,32\)
\(\Rightarrow11x=66,36\)
\(\Rightarrow x=6,0327\)
tìm x biết: \(\frac{11}{10,5}=\frac{6,32}{x}\)
\(\frac{11}{10,5}=\frac{6,32}{x}\Rightarrow x=\frac{6,32.10,5}{11}=\frac{1659}{275}\)
\(\frac{11}{10,5}=\frac{6,32}{x}\)
\(\Rightarrow11.x=6,32.10,5\)
\(\Rightarrow11.x=66,36\)
\(\Rightarrow x=66,36:11\)
\(\Rightarrow x=\frac{1659}{275}\)
Vậy \(x=\frac{1659}{275}.\)
Chúc bạn học tốt!
Tìm x
a, \(\frac{11}{10,5}=\frac{6,32}{-x}\) b,\(\frac{x-1}{x+5}=\frac{6}{7}\) c, \(\frac{x^2}{6}=\frac{24}{25}\) d,x:0,16 = 9:x
a) \(\frac{11}{10,5}=\frac{6,32}{-x}\)
\(6,32:\frac{11}{10,5}=x\)
\(\frac{1659}{275}=x\)
b) \(\frac{x-1}{x+5}=\frac{6}{7}\)
\(\Rightarrow7x-7=6x+30\)
\(7x-6x=30+7\)
\(x=37\)
c) \(\frac{x^2}{6}=\frac{24}{25}\)
\(x^2=\frac{144}{25}\)
\(x=\frac{12}{5}\)
d) \(x:0,16=9:x\)
\(\frac{x}{0,16}=\frac{9}{x}\)
\(x^2=1,44\)
\(x=1,2\)
bai 1:Tim x:
a,4,5-x+1,8=1,14
b,1,5-4,6+x=0,6
Bai2:Cho 2 so ,biet rang neu so lon bot 10,5 va so be thme 10,5 thi hai so bang nhau.Neu moi so cung them 0,25 thi duoc 2 so moi co ti so la 4.
Tìm các số hữu tỉ x trong các tỉ lệ thức
a) 0,4 : x = x : 0,9
b) 0,2 : 1 1/5 = 2/3 : (6x + 7)
c) 13 1/3 : 1 1/3 = 26 : (2x + 1)
d) 37 - x/x + 13= 3/7
e) 3x + 2/5x + 7= 3 x - 1/5x + 1
h) x / 3,15 = 0,15 / 7,2
i) -2,6/x = -12/42
K) 11/10,5 = 6,32
L) 41/10//9/4= x/ 7,3
Tim x biet 11*(x-6)=4x+11
\(11\cdot\left(x-6\right)=4x+11\)
\(11x-66=4x+11\)
\(11x-4x=11+66\)
\(7x=77\)
\(\Rightarrow x=11\)
\(11.\left(x-6\right)=4x+11\)
=) \(11x-66=4x+11\)
=) \(11x-4x=11+66\)
=) \(7x=77\)
=) \(x=77:7=11\)
11.(x-6)=4x+11
11.x-66=4x+11
7x=66+11
7x=77
x=11
vậy x=11
Tim x biet (x-3) + (x-2) + (x-1) + ... + 10 + 11 = 11
tim x biet : (11/12+11/12.23+11/23.24+...+11/89.100) + x = 2/3
tim x biet:
(x-3)+(x-2)+(x-1)+....+10+11=11