timf x-210=-1+-2+-3+....+(-x+1)+(-x) vay x=
timf x,y,z
35.(x+y) = 210.(x-y)=12.(x.y)
Timf `x`:
`(x - 2)/3 = (x + 1)/4`
`(x - 2) . 4 = (x + 1) . 3`
`<=> 4x - 8 = 3x + 3`
`<=> 4x - 3x = 3 + 8`
`<=> (4 - 3)x = 11`
`=> x = 11`
`(x - 2)/3 = (x + 1)/4`
`(x - 2) . 4 = (x + 1) . 3`
`<=> 4x - 8 = 3x + 3`
`<=> 4x - 3x = 3 + 8`
`<=> (4 - 3)x = 11`
`=> x = 11`
`=>` `x = 11`
Timf x biết:
(x+1)+(x+2)+(x+3)+...+(x+100)=5750
100x+(1+100).100/2=5750
100x+5050=5750
100x=700
x=7
a, (x+1) + (x+2) + (x+3) +....+ (x+9)=90
Timf x
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+9\right)=90\)
Ta có 9 SSH (từ 1 đến 9)
9.x+(1+2+3+...+9)=90
9x+(9+1).9:2=90
9x+45=90
9x=90-45=45
x=45:9
x=5
(x+1)+(x+2)+...+(x+9)=90
Ta có 9 SSH (từ 1 đến 9)
9.x+(1+2+3+...+9)=90
9x+(9+1).9:2=90
9x+45=90
9x=90-45=45
x=45:9
x=5
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+9\right)=90\)
\(\Rightarrow\left(x+x+x+...+x\right)+\left(1+2+3+...+9\right)=90\)
\(\Rightarrow9x+45=90\)
\(\Rightarrow9x=90-45\)
\(\Rightarrow9x=45\Rightarrow x=5\)
timf x,y (x-1)^2+(y+3)^2=0
\(\left(x-1\right)^2+\left(y+3\right)^2=0\left(1\right)\)
Ta thấy \(\left\{{}\begin{matrix}\left(x-1\right)^2\ge0,\forall x\\\left(y+3\right)^2\ge0,\forall y\end{matrix}\right.\)
\(\left(1\right)\Leftrightarrow\left\{{}\begin{matrix}\left(x-1\right)^2=0\\\left(y+3\right)^2=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-1=0\\y+3=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=-3\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}\left(x-1\right)^2=0\\\left(y+3\right)^2=0\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}\left(x+1\right)^2=0^2\\\left(y+3\right)^2=0^2\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x+1=0\\y+3=0\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=-1\\y=-3\end{matrix}\right.\)
Timf các số hữu tỉ thỏa mãn : /x+1/+/x+2/+/x+3/+/x+4/=5x
timf x biet 1+2+3+...+ x =55
côn thức[ số đầu + số cuối ] . các số hạng / 2 = kết quả
[1+x].b/2=55
=55.2=110
=[1+10].10/2=55
=x=10
tớ chỉ có thể giải thích thế này thôi nên thứ lỗi
timf x
a,4^x+4^x+1=80
b,4^x+1+4^x+2+4^x+3=84
a) \(4^x+4^{x+1}=80\)
\(\Rightarrow4^x+4^x.4=80\)
\(\Rightarrow4^x.\left(1+4\right)=80\)
\(\Rightarrow4^x.5=80\)
\(\Rightarrow4^x=16\)
\(\Rightarrow4^x=4^2\)
\(\Rightarrow x=2\)
Vậy x = 2
1> Timf x
a . x2 - 25 - ( x + 5 ) =0
2 > Timf GTNN cua b thuc
a . A = (x-1)(x-3) +11
b . B= (2x-1)2+ (x-2)2
3> Phan tich da thuc thanh nhan tu
a . x3 + 27 + (x-3)(x-9)
b. 4x2 - 25 - (2x-5)(2x+7)