57 \(\times\) 46 + 57 \(\times\) 54

= 57    \(\times\) ( 46 + 54)

= 57 \(\times\) 100

= 5700

137 + 355 + 63 + 45

= ( 137 + 63) + ( 355 + 45)

= 200 + 400

= 600

215 \(\times\) 48 - 215 \(\times\) 38

= 215 \(\times\) ( 48 - 38)

= 215 \(\times\) 10

= 2150 

4 \(\times\) 50 \(\times\) 25 

= ( 4 \(\times\) 25) \(\times\) 50

= 100 \(\times\) 50

= 5 000

57×(46+54) =57×100=5700

137+355+63+45=(137+63) +(355+45) =200+400=600

215×48-215×38=215×(48-38) =215×10=2150

4×50×25=(4×25) ×50=100×50=5000

    57 $\times$ 46 + 57 $\times$ 54

= 57    $\times$ ( 46 + 54)

= 57 $\times$ 100

= 5700

137 + 355 + 63 + 45

= ( 137 + 63) + ( 355 + 45)

= 200 + 400

= 600

215 $\times$ 48 - 215 $\times$ 38

= 215 $\times$ ( 48 - 38)

= 215 $\times$ 10

= 2150 

4 $\times$ 50 $\times$ 25 

= ( 4 $\times$ 25) $\times$ 50

= 100 $\times$ 50

= 5 000

\(\dfrac{19.2.22.9.2.3}{19.3.22.9.5}=\dfrac{4}{5}\)

\(B=\left(4^5\cdot10\cdot5^6+25^5\cdot2^8\right):\left(2^8\cdot5^4+5^7\cdot2^5\right)\)

\(B=\dfrac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{\left(2^2\right)^5\cdot2\cdot5\cdot5^6+\left(5^2\right)^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{2^{11}\cdot5^7+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)

\(B=\dfrac{2^8\cdot5^7\cdot\left(2^3\cdot1+5^3\cdot1\right)}{2^5\cdot5^4\cdot\left(2^3\cdot1+5^3\cdot1\right)}\)

\(B=\dfrac{2^8\cdot5^7}{2^5\cdot5^4}\)

\(B=\dfrac{2^3\cdot5^3}{1\cdot1}\)

\(B=\left(2\cdot5\right)^3\)

\(B=10^3\)

\(B=1000\)

\(4.5^{57}:\left(x-15\right)=5^{54}\)

\(4.\left(x-15\right)=5^{57}:5^{54}\)

\(4x-4.15=5^3\)

\(4x-60=125\)

\(4x=125+60\)

\(4x=185\)

\(x=185:4\)

\(x=46,25\)

- Tính giá trị ở mỗi vế.

- So sánh rồi điền dấu thích hợp vào chỗ trống.

a) 32 + 7 < 40     b) 32 + 14 = 14 + 32

45 + 4 < 54 + 5     69 - 9 < 96 - 6

55 - 5 > 40 + 5     57 - 1 < 57 + 1

\(\frac{x+43}{57}+\frac{x+46}{54}+\frac{x+49}{51}+\frac{x+235}{45}=0\)

\(\Leftrightarrow\text{​​}\text{​​}\)\(\frac{x+43}{57}+1+\frac{x+46}{54}+1+\frac{x+49}{51}+1+\frac{x+235}{45}-3=0\)

\(\Leftrightarrow\frac{x+100}{57}+\frac{x+100}{54}+\frac{x+100}{51}+\frac{x+100}{45}=0\)

\(\Leftrightarrow\left(x+100\right)\left(\frac{1}{57}+\frac{1}{54}+\frac{1}{51}+\frac{1}{45}\right)=0\)

\(\Leftrightarrow x+100=0\)

\(\Leftrightarrow x=-100\)

Vậy x = -100

Ta có: \(\dfrac{x-1}{59}+\dfrac{x-2}{58}+\dfrac{x-3}{57}=\dfrac{x-4}{56}+\dfrac{x-5}{55}+\dfrac{x-6}{54}\)

\(\Leftrightarrow\dfrac{x-60}{59}+\dfrac{x-60}{58}+\dfrac{x-60}{57}-\dfrac{x-60}{56}-\dfrac{x-60}{55}-\dfrac{x-60}{54}=0\)

\(\Leftrightarrow x-60=0\)

hay x=60

a) x = -11

b) x = 2

c) x = -5

d) x = 5

e) x = 3 hoặc x = 7        

f) x = -1 hoặc x = 9

\(\dfrac{x-1}{59}+\dfrac{x-2}{58}+\dfrac{x-3}{57}=\dfrac{x-4}{56}+\dfrac{x-5}{55}+\dfrac{x-6}{54}\)

\(\Leftrightarrow\dfrac{x-1}{59}-1+\dfrac{x-2}{58}-1+\dfrac{x-3}{57}=\dfrac{x-4}{56}-1+\dfrac{x-5}{55}-1+\dfrac{x-6}{54}-1\)

\(\Leftrightarrow\dfrac{x-60}{59}+\dfrac{x-60}{58}+\dfrac{x-60}{57}=\dfrac{x-60}{56}+\dfrac{x-60}{55}+\dfrac{x-60}{54}\)

\(\Leftrightarrow\left(x-60\right)\left(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}-\dfrac{1}{56}-\dfrac{1}{55}-\dfrac{1}{54}\right)=0\)

\(\Leftrightarrow x-60=0\)

\(\Rightarrow x=60\)

vậy \(S=\left\{60\right\}\)