a)=49x(27+61+12)+100x51

  =49x100+5100

  =4900+5100

  =10000

b)=7236:36

   =201

k nha p

238,61

201

a, 27 . 49 + 61 . 49 + 49 . 12 + 100 . 51

= 27 . 49 + 61 .49 + 12 . 49 + 100 . 51

= ( 27 + 61 + 12 ) . 49 + 100 . 51

= 100 . 49 + 100 . 51

= 100 . ( 49 + 51 )

= 100 . 100

= 10000 

b, ( 7200 + 36 ) : 36

= 7200 + 36 : 36 + 1

= 7200 + 1 + 1

= 7202

a)\(=12\times3+4\times12+12\times3=12\times\left(3+4+3\right)=12\times10=120\)

b)\(=25\times7-25\times2-3\times25-2\times25=25\times\left(7-2-3-2\right)=0\)

A) 12x3+4x12+36

=12x3+4x12+12x3

=12x(3+4+3)

=120

`1 - 2 + 3 - 4 + 5 - 6 +...+ 2021 - 2022`

`= (1 - 2) + (3 - 4) + (5 - 6) +...+ (2021 - 2022)`

`= (-1) + (-1) + (-1) + ... + (-1) `  [có `2022 : 2 = 1011` nhóm]

`= (-1) xx 1011 = -1011`

a, \(\dfrac{3}{5}.\left(-\dfrac{8}{3}\right)-\dfrac{3}{5}:\left(-\dfrac{3}{2}\right)=\dfrac{3}{5}.\left(-\dfrac{8}{3}\right)-\dfrac{3}{5}.\left(-\dfrac{2}{3}\right)==\dfrac{3}{5}\left(-\dfrac{8}{3}-\dfrac{2}{3}\right)=\dfrac{3}{5}.\left(-\dfrac{10}{3}\right)=-2\)

b, \(-\dfrac{5}{6}.\left(-\dfrac{12}{7}\right)-\left(-\dfrac{21}{15}\right)=-\dfrac{5}{6}.\left(-\dfrac{12}{7}\right)+\dfrac{7}{5}=\dfrac{10}{7}+\dfrac{7}{5}=\dfrac{50+49}{35}=\dfrac{99}{35}\)

a: \(=\dfrac{3}{5}\cdot\left(-\dfrac{8}{3}+\dfrac{-2}{3}\right)=\dfrac{3}{5}\cdot\dfrac{-10}{3}=-2\)

c: \(=\left(0.125\right)^{650}\cdot8^{102}\)

\(=\left(0.125\cdot8\right)^{102}\cdot\left(0.125\right)^{548}\)

\(=\dfrac{1}{8^{548}}\)

\(\dfrac{1}{2}\cdot1\cdot\dfrac{1}{3}\cdot10\cdot\dfrac{7}{35}\cdot\dfrac{3}{4}\)

\(=\dfrac{1}{2}\cdot10\cdot\dfrac{1}{5}\cdot1\cdot\dfrac{1}{3}\cdot\dfrac{3}{4}\)

\(=\dfrac{10}{10}\cdot\dfrac{1}{4}=\dfrac{1}{4}\)

3/5

3/5

\(\dfrac{3}{5}\)

a) 80-(4x5^2-3x2^3)

   = 80-(4x25-3x8)

   = 80-(100-24)

   = 80-76

   = 4

b) 125-2x[56-48:(15-7)]

  = 125-2x[56-48:8]

  = 125-2x[56-6]

   =125-2x50

   =125-100

   =25.

a: \(7\cdot\left(-2\right)^3-12\cdot\left(-5\right)+\left(-17\right)\)

\(=7\cdot\left(-8\right)+60-17\)

=-56+43

=-13

b: \(1632-37-\left(-157\right)-163-1532\)

\(=\left(1632-1532\right)-37-163+157\)

=100-200+157

=57

c: \(47\cdot\left(-918\right)+\left(-53\right)\cdot918\)

\(=918\left(-47\right)+\left(-53\right)\cdot918\)

\(=918\cdot\left(-47-53\right)\)

\(=918\left(-100\right)=-91800\)

d: \(\left(-52\right)\cdot\left(-281\right)+\left(-52\right)\cdot181\)

\(=\left(-52\right)\left(-281+181\right)\)

\(=\left(-52\right)\cdot\left(-100\right)=5200\)

a: 

=-56+43

=-13

b: 

=100-200+157

=57

c: 

d: 

2:

a: \(=\dfrac{1}{3}\left(-\dfrac{4}{5}-\dfrac{6}{5}\right)=-\dfrac{1}{3}\cdot2=-\dfrac{2}{3}\)

1:

\(A=7-\dfrac{3}{4}+\dfrac{1}{3}-6-\dfrac{5}{4}+\dfrac{4}{3}-5+\dfrac{7}{4}-\dfrac{5}{3}\)

\(=-4-\dfrac{1}{4}=-\dfrac{17}{4}\)

Bài 1:

\(A=\left(7-\dfrac{3}{4}+\dfrac{1}{3}\right)-\left(6+\dfrac{5}{4}-\dfrac{4}{3}\right)-\left(5-\dfrac{7}{4}+\dfrac{5}{3}\right)\)

\(A=7-\dfrac{3}{4}+\dfrac{1}{3}-6-\dfrac{5}{4}+\dfrac{4}{3}-5+\dfrac{7}{4}-\dfrac{5}{3}\)

\(A=\left(7-6-5\right)-\left(\dfrac{3}{4}+\dfrac{5}{4}-\dfrac{7}{4}\right)+\left(\dfrac{1}{3}+\dfrac{4}{3}-\dfrac{5}{3}\right)\)

\(A=-4-\dfrac{3+5-7}{4}+\dfrac{1+4-5}{3}\)

\(A=-4-\dfrac{1}{4}+\dfrac{0}{3}\)

\(A=-\dfrac{16}{4}-\dfrac{1}{4}+0\)

\(A=\dfrac{-16-1}{4}\)

\(A=-\dfrac{17}{4}\)

Bài 2:

\(\dfrac{1}{3}\cdot-\dfrac{4}{5}+\dfrac{1}{3}\cdot-\dfrac{6}{5}\)

\(=\dfrac{1}{3}\cdot\left(-\dfrac{4}{5}-\dfrac{6}{5}\right)\)

\(=\dfrac{1}{3}\cdot\dfrac{-4-6}{5}\)

\(=\dfrac{1}{3}\cdot\dfrac{-10}{5}\)

\(=\dfrac{1}{3}\cdot-2\)

\(=-\dfrac{2}{3}\)