Answer:

Áp dụng: \(x^n.x^m=x^{n+m}\)

\(x^2.x^5=x^{2+5}=x^7\)

a: \(3\cdot3\cdot3\cdot3\cdot3=3^5\)

b: \(y\cdot y\cdot y\cdot y=y^4\)

c: \(5\cdot p\cdot5\cdot p\cdot2\cdot q\cdot4\cdot q=25\cdot2\cdot4\cdot p^2q^2=2\cdot\left(10qp\right)^2\)

d: \(a\cdot a+b\cdot b+c\cdot c+d\cdot d\cdot d\cdot d=a^2+b^2+c^2+d^4\)

a) 3.3.3.3.3 = 3\(^5\)

b) y.y.y.y = y\(^4\)

c) 5.p.5.p.2.q.4.q = 5\(^2\).p\(^2\).q\(^2\).2\(^3\) 

(2\(^3\) ở đây là vì 2.4 = 2.2.2 = 2\(^3\))

d) a.a + b.b + c.c.c + d.d.d.d = a\(^2\)+b\(^2\)+c\(^3\)+d\(^4\)

1.
a) \(3^4\times3^5\times3^6=3^{4+5+6}=3^{15}\)

b) \(5^2\times5^4\times5^5\times25=5^2\times5^4\times5^5\times5^2=5^{2+4+5+2}=5^{13}\)

c) \(10^8\div10^3=10^{8-3}=10^5\)

d) \(a^7\div a^2=a^{7-2}=a^5\)

2.

\(987=900+80+7\\ =9\times100+8\times10+7\\ =9\times10^2+8\times10^1+7\times10^0\)

\(2021=2000+20+1\\ =2\times1000+2\times10+1\times1\\ =2\times10^3+2\times10^1+1\times10^0\)

\(abcde=a\times10000+b\times1000+c\times100+d\times10+e\times1\\ =a\times10^4+b\times10^3+c\times10^2+d\times10^1+e\times10^0\)

còn bài 2

a) 3³ . 3⁴ = 3⁷

b) 5² . 5⁷ = 5⁹

c) 7⁵ . 7 = 7⁶

a) \(3^3.3^4=3^{3+4}=3^7\)

b) \(5^2.5^7=5^{2+7}=5^9\)

c) \(7^5.7=7^{5+1}=7^6\)

\(3^3.3^4=3^{3+4}=3^7\)

\(5^2.5^7=5^{2+7}=5^9\)

\(7^5+7=7^{5+1}=7^6\)

Sao chẳng có ai T mik z bất công quá

\(16^2:4^2\)

\(=\left(4^2\right)^2:4^2\)

\(=4^4:4^2\)

\(=4^{4-2}\)

\(=4^2\)

==========

\(25^5:5^2\)

\(=\left(5^2\right)^5:5^2\)

\(=5^{10}:5^2\)

\(=5^{10-2}\)

\(=5^8\)

============

\(9^8:3^2\)

\(=\left(3^2\right)^8:3^2\)

\(=3^{16}:3^2\)

\(=3^{16-2}\)

\(=3^{14}\)

===========

\(a^6:a\)

\(=a^{6-1}\)

\(=a^5\)

\(12^2.3.12^3.4=\left(4.3\right)^2.3.4=4^2.3^2.3.4=3^3.4^3=27.64=1728\)

\(12^2.3.12^3.4=12^5.3.4=\left(3.4\right)^5.3.4=3^5.4^5.3.4=3^6.4^6=729.4096=\text{2985984}\)

\(3^6.4^6\)

Đề thiếu, bạn coi lại đề.

\(a,5\cdot p\cdot5\cdot p\cdot2q\cdot4q\)

\(=5^2\cdot p^2\cdot2\cdot q\cdot2^2\cdot q\)

\(=5^2\cdot2^3\cdot p^2\cdot q^2\)

\(b,a\cdot a+b\cdot b+c\cdot c\cdot c+d\cdot d\cdot d\cdot d\)

\(=a^2+b^2+c^3+d^4\)

#Urushi

Lưu ý: a = a1

a6:a = a6-1 = a5