Tính - 7 31 . 0
kết quả của phép tính
(7/15 - 3/14 +1/5) - (-31/14 + 22/15)
A. 1/5
b. 6/5
C. 1
D. 0
Cho M = (17/31 + -16/7) + (46/57 + 14/31) + 11/57 , thì giá trị của biểu thức là
A.M = -2/7 B. M = 0 C.M=2/7 D.M = -16/7
Tính
a) -84 : 4 + 3 mũ 9 : 3 mũ 7 + 5 mũ 0
b) 295 - ( 31 - 2 mũ 5. 5) mũ 2
a)-84:4+3^9:3^7+5^0
=-21+(3^9:3^7)+1
=-21+3^2+1
=-21+9+1
=-12+1
=-11
b)295-(31-2^5.5)^2
=295-(31-32.5)^2
=295-(-129)^2
=295+129^2
=295-16641
=-16346
tick cho mk nha bạn
a) -84 : 4 + 3^ 9 : 3 ^ 7 + 5 ^0
=-84:4+3^2+1
=-84:4+9+1
=-21+9+1
=-12+1
=-11
b) 295 - ( 31 - 2^ 5. 5) ^2
= 295 - ( 31 -32. 5)^2
= 295 - (-129)^2
=295-16641
=-16346
tim x biet
1)0,(31)+x=0,(7)
2)0,(4)nhan x=3/7
tính bằng cách thuận tiện nhất a, 2/7:27/31+4/7:27/31+1/7:27/31
b, 23/45x 17/51:23/45
giúp mik với
a) = \(\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right):\dfrac{27}{31}\)
= \(\dfrac{7}{7}\) x \(\dfrac{31}{27}\)
= 1 x \(\dfrac{31}{27}\) = \(\dfrac{31}{27}\)
b) = \(\left(\dfrac{23}{45}:\dfrac{23}{45}\right)\)x \(\dfrac{17}{51}\)
= 1 x \(\dfrac{17}{51}\)= \(\dfrac{17}{51}\)
Tính :
( 21/31 + -16/7 ) + ( 44/53 + 10/31 ) + 9/53
\(\left(\dfrac{21}{31}+\dfrac{-16}{7}\right)+\left(\dfrac{44}{53}+\dfrac{10}{31}\right)+\dfrac{9}{53}.\)
\(\dfrac{21}{31}-\dfrac{16}{7}+\dfrac{44}{53}+\dfrac{10}{31}+\dfrac{9}{53}=\left(\dfrac{21}{31}+\dfrac{10}{31}\right)+\left(\dfrac{44}{53}+\dfrac{9}{53}\right)-\dfrac{16}{7}=1+1-\dfrac{16}{7}=\dfrac{-2}{7}.\)
tìm x,biết
a)0,(31)+x=0,3(7) b)0,(4).x=\(\dfrac{5}{6}\)
a) \(0,\left(31\right)+x=0,3\left(7\right)\\ \Rightarrow\dfrac{31}{99}+x=\dfrac{17}{45}\\ \Rightarrow x=\dfrac{17}{45}-\dfrac{31}{99}=\dfrac{32}{495}=0,0\left(64\right)\)
Vậy \(x=0,0\left(64\right)\)
b) \(0,\left(4\right)\cdot x=\dfrac{5}{6}\\ \Rightarrow\dfrac{4}{9}\cdot x=\dfrac{5}{6}\\ \Rightarrow x=\dfrac{5}{6}:\dfrac{4}{9}\\ \Rightarrow x=\dfrac{5}{6}\cdot\dfrac{9}{4}\\ \Rightarrow x=\dfrac{15}{8}=1,875\)
Vậy \(x=1,875\)
Tính nhanh
1/3*5 + 1/5*7 + 1/7*9 + .....+ 1/29*31 + 1/31*33
Đặt A = \(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+....+\frac{1}{31.33}\)
=> 2A = \(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+.....+\frac{2}{31.33}\)
=> 2A = \(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{31}-\frac{1}{33}\)
=> 2A = \(\frac{1}{3}-\frac{1}{33}\)
=> A = \(\left(\frac{1}{3}-\frac{1}{33}\right):2\)
Chứng tỏ rằng A = 7^0 + 7^1 + 7^2 + 7^3 + ........................+ 7^30+ 7^31 chia hết cho 25
7A=7+7^2+7^3+....+7^32
=(7+7^2+7^3+7^4)+....+(7^29+7^30+7^31+7^32)
=(7+7^2+7^3+7^4)+.....+7^28x(7+7^2+7^3+7^4)
=2800+......+7^28x2800
=2800x(1+7^4+....+7^28)chia hết cho 25(vì 2800 chia hết cho 25)
chứng tỏ rằng A = 7^0+7^1+7^2+7^3+7^4+...+7^30+7^31 chia hết cho 25