a: \(2^2\cdot5-\dfrac{\left(1^{10}+8\right)}{3^2}\)

\(=4\cdot5-\dfrac{1+8}{3}\)

=20-3

=17

b: \(5^8:5^6+4\left(3^2-1\right)\)

\(=5^2+4\left(9-1\right)\)

=25+4*8

=25+32

=57

c: \(400-\left\{36-20:\left[3^3-\left(8-3\right)\right]\right\}\)

\(=400-36+20:\left[27-5\right]\)

\(=364+\dfrac{20}{22}\)

\(=364+\dfrac{10}{11}=\dfrac{4014}{11}\)

A) 2².5 - (1¹⁰ + 8) : 3²

= 4.5 - (1 + 8) : 9

= 20 - 9 : 9

= 20 - 1

= 19

B) 5⁸ : 5⁶ + 4.(3² - 1)

= 5² + 4.(9 - 1)

= 25 + 4.8

= 25 + 32

= 57

C) 400 - {36 - 20 : [3³ - (8 - 3)]}

= 400 - [36 - 20 : (27 - 5)]

= 400 -(36 - 20 : 22)

= 400 - (36 - 10/11)

= 400 - 386/11

= 4014/11

Ta có: A = 1+(-2)+3+(-4)+....+2003+(-2004) = 2005

     => A = (-1)+(-1)+(-1)+....+(-1) = (-1) x 2004 = -2004

a: \(2\cdot25\cdot4\cdot50\)

\(=\left(2\cdot50\right)\cdot\left(25\cdot4\right)\)

\(=100\cdot100=10000\)

b: \(\left(-125\right)\cdot5\cdot\left(-16\right)\cdot\left(-8\right)\)

\(=-125\cdot5\cdot16\cdot8\)

\(=-\left(125\cdot8\right)\cdot\left(5\cdot16\right)\)

\(=-80\cdot1000=-80000\)

c: \(5^2\cdot3^3\cdot2\)

\(=25\cdot27\cdot2\)

\(=\left(25\cdot2\right)\cdot27=27\cdot50=1350\)

d: \(\left(-4\right)\cdot3^2\left(-5\right)^3\)

\(=\left(-4\right)\cdot\left(-125\right)\cdot9\)

\(=500\cdot9=4500\)

a) 

=10000

b) 

=−80000

c) 

=27⋅50

=1350

d) 

=4500

xin chào anh em

A) 195 x 63 + 37 x195

195 x ( 63 + 37 ) = 195 x 100

= 19500

B) 7^12 : 7^10 - 36 : 3^2

= 7^12-10 - 36 : 9

= 7^2 - 4 = 49 - 4 = 45

C) 180 - [130-(12-10)^3] + 2023^0

= 180 -(130-2^3)+1

= 180-130+8+1

= 50 + 8+1 = 59

\(a,195.63+37.195\)

\(=195\left(63+37\right)\)

\(=195.100\)

\(=19500\)

\(b,7^{12}:7^{10}-36:3^2\)

\(=7^2-2^2.3^2:3^2\)

\(=7^2-2^2\)

\(=49-4=44\)

\(c,180-\left[130-\left(12-10\right)^3\right]+2023^0\)

\(=180-\left[130-2^3\right]+1\)

\(=180-\left(130-8\right)+1\)

\(=180-122+1\)

\(=59\)

Có gì k hiểu thì ib nhá

`a)-4/9(5/6*90%-8:0,32)`

`=-4/9(5/6*9/10-8:8/25)`

`=-4/9(3/4-25)`

`=-4/9*(-97)/4=97/9`

`b)(2/5)^2+5 1/2.(4,5-2)+(2^3)/(-4)`

`=4/25+11/2*5/2+8/(-4)`

`=4/25+55/4-2`

`=1191/100`

Trả lời:

\(A=\frac{3}{4}\cdot\frac{8}{9}\cdot\frac{15}{16}\cdot...\cdot\frac{2499}{2500}\)

\(=\frac{3\cdot8\cdot15\cdot...\cdot2499}{4\cdot9\cdot16\cdot...\cdot2500}\)

\(=\frac{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot...\cdot49\cdot51}{2\cdot2\cdot3\cdot3\cdot4\cdot4\cdot...\cdot50\cdot50}\)

\(=\frac{\left(1\cdot2\cdot3\cdot...\cdot49\right)\cdot\left(3\cdot4\cdot5\cdot...\cdot51\right)}{\left(2\cdot3\cdot4\cdot...\cdot50\right)\left(2\cdot3\cdot4\cdot...50\right)}\)

\(=\frac{1\cdot51}{50.2}=\frac{51}{100}\)

\(11\div\left\{\frac{7}{8}-3\cdot\left[0,25\div\left(1\frac{1}{3}+2\cdot\frac{1}{3}\right)\right]\right\}\)

\(=11\div\left\{\frac{7}{8}-3\cdot\left[\frac{1}{4}\div\left(\frac{4}{3}+2\cdot\frac{1}{3}\right)\right]\right\}\)

\(=11\div\left\{\frac{7}{8}-3\cdot\left[\frac{1}{4}\div\left(\frac{4}{3}+\frac{2}{3}\right)\right]\right\}\)

\(=11\div\left\{\frac{7}{8}-3\cdot\left[\frac{1}{4}\div2\right]\right\}\)

\(=11\div\left\{\frac{7}{8}-3\cdot\frac{1}{8}\right\}\)

\(=11\div\left\{\frac{7}{8}-\frac{3}{8}\right\}\)

\(=11\div\frac{1}{2}\)

\(=22\)

b) 101*789 + 456*128 - 789 + 912*436

= 789*100 + 456*128 + 912*436

= 789*100 + 912*64 + 912*436

= 789*100 + 912*500

= 100*(789 + 912*5)

= 100*5349

= 534900

\(a)\)\(11\div\left\{\frac{7}{8}-3\times\left[0,25\div\left(1\frac{1}{3}+2\times\frac{1}{3}\right)\right]\right\}\)

\(=\)\(11\div\left\{\frac{7}{8}-3\times\left[\frac{1}{4}\div\left(\frac{4}{3}+\frac{2}{3}\right)\right]\right\}\)

\(=\)\(11\div\left\{\frac{7}{8}-3\times\left[\frac{1}{4}\div2\right]\right\}\)

\(=\)\(11\div\left\{\frac{7}{8}-3\times\left[\frac{1}{4}\times\frac{1}{2}\right]\right\}\)

\(=\)\(11\div\left\{\frac{7}{8}-3\times\frac{1}{8}\right\}\)

\(=\)\(11\div\left\{\frac{7}{8}-\frac{3}{8}\right\}\)

\(=\)\(11\div\frac{1}{2}\)

\(=\)\(22\)

\(b)\)\(101\times789+456\times128-789+912\times436\)

\(=\)\(79689+58368-789+397632\)

\(=\)\(534900\)

a) = 1.1204
b) = 0.5714

a) = 1.1204
b) = 0.5714

a) = 1.1204
b) = 0.5714

ok con de

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