Tìm X
a/ X : 3 = 21628
b/ X x 5 = 15250
Đặt tính rồi tính
a/ 21628 x 3
b/ 15250 : 5
Đặt tính rồi tính:
21628 x 3
45603 + 12908
15250 : 5
67013- 23114
21628 x 3 = 64884 15250: 5 = 3050 45603 + 12908 = 32695 67013- 23114 = 43899
Đặt tính rồi tính:
21628 x 3
45603 + 12908
15250 : 5
67013- 23114
bài 3:tìm x
a)x(x+4)+(5+x)(5-x)=3
b)(2x-3)^2=(4x+3)^2
a) \(\Rightarrow x^2+4x+25-x^2=3\Rightarrow4x=-22\Rightarrow x=-\dfrac{11}{2}\)
b) \(\Rightarrow\left(4x+3-2x+3\right)\left(4x+3+2x-3\right)=0\)
\(\Rightarrow2\left(x+3\right).6x=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
Tìm x
a, x(x-3)+(x-3)=0
b, 7x(x-5)-x+5=0
ai nhanh mk sẽ vote ạ
a) x(x-3)+(x-3)=0
<=>(x-3)(x+1)=0
<=>x-3=0 hoặc x+1=0
<=>x=3 hoặc x=-1
b) 7x(x-5)-x+5=0
<=>(7x-1)(x-5)=0
<=>7x-1=0 hoặc x-5=0
<=>x=1/7 hoặc x=5
a: Ta có: \(x\left(x-3\right)+\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
b: Ta có: \(7x\left(x-5\right)-x+5=0\)
\(\Leftrightarrow\left(x-5\right)\left(7x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{1}{7}\end{matrix}\right.\)
tìm X
a) 2/3 + 1/3 :3 x X= 20%
b)3-X/5-X = 6/11
Lời giải:
a.
$\frac{2}{3}+\frac{1}{3}:3\times x=20\text{%}$
$\frac{2}{3}+\frac{1}{9}\times x=\frac{1}{5}$
$\frac{1}{9}\times x=\frac{1}{5}-\frac{2}{3}=\frac{-7}{15}$
$x=\frac{-7}{15}: \frac{1}{9}=\frac{-21}{5}$
b.
$\frac{3-x}{5-x}=\frac{6}{11}$
$\Rightarrow 6(5-x)=11(3-x)$
$\Rightarrow 30-6x=33-11x$
$\Rightarrow 5x=3$
$\Rightarrow x=\frac{3}{5}$
1.Tìm x
a) 9/2 - x = 3/7 b) x : 5/7 = 7/5 c) x x 3/8 = 11/3
a: x=9/2-3/7=57/14
b: =>x=7/5x5/7=1
c: =>x=11/3:3/8=11/3x8/3=88/9
a : x = \(\dfrac{9}{2}\) - \(\dfrac{3}{7}\) = \(\dfrac{57}{14}\)
b : = > x = \(\dfrac{7}{5}\) x\(\dfrac{5}{7}\) = 1
c : = > \(\dfrac{11}{3}\) : \(\dfrac{3}{8}\) = \(\dfrac{11}{3}\) x \(\dfrac{8}{3}\) = \(\dfrac{88}{9}\)
Tìm x
a) x + 2/5 = 1/2
b) x + 3/7 = 2/5 + 3/10
c) 19 - x = 8/5 - 3/4
\(a,x=\dfrac{1}{2}-\dfrac{2}{5}\)
\(x=\dfrac{1}{10}\)
\(b,x+\dfrac{3}{7}=\dfrac{7}{10}\)
\(x=\dfrac{7}{10}-\dfrac{3}{7}\)
\(x=\dfrac{19}{70}\)
\(c,19-x=\dfrac{17}{20}\)
\(x=19-\dfrac{17}{20}\)
\(x=\dfrac{363}{20}\)
tìm x
a,(x+5)(x-5)-x(x+3)=10 b,(2x+3)(2x-3)-4(x+2)^2=5
c,9x(x+5)-(3x+2)(3x-2)=7 d,(x+1)^3-x(x^2+3x-5)=8
a: =>x^2-25-x^2-3x=10
=>-3x=35
=>x=-35/3
b: =>4x^2-9-4(x^2+4x+4)=5
=>4x^2-9-4x^2-16x-16-5=0
=>-16x-30=0
=>x=-15/8
c: =>9x^2+45x-9x^2+4=7
=>45x=3
=>x=1/15
d: =>x^3+3x^2+3x+1-x^3-3x^2+5x=8
=>8x=7
=>x=7/8