f(1)=3

f(-1)=3

\(\text{f(1)=}2.1^2+1=3\)

\(\text{f(-1)=}2.\left(-1\right)^2+1=3\)

\(\text{f(2)=}2.2^2+1=9\)

\(\text{f(0)=}2.0^2+1=1\)

\(\text{f(-3)=}=2.\left(-3\right)^2+1=19\)

Bài 2:

Gọi số cây 7A,7B,7C,7D lần lượt là \(a,b,c,d\in \mathbb{N^*},cây\)

Áp dụng tc dtsbn:

\(\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{c}{5}=\dfrac{d}{6}=\dfrac{b-a}{4-3}=\dfrac{6}{1}=6\\ \Rightarrow\left\{{}\begin{matrix}a=18\\b=24\\c=30\\d=36\end{matrix}\right.\)
Vậy ...

Bài 3:

Gọi số hs 7A,7B,7C,7D lần lượt là \(a,b,c,d\in \mathbb{N^*},hs\)

Áp dụng tc dtsbn:

\(\dfrac{a}{10}=\dfrac{b}{8}=\dfrac{c}{9}=\dfrac{d}{7}=\dfrac{a-d}{10-7}=\dfrac{12}{3}=4\\ \Rightarrow\left\{{}\begin{matrix}a=40\\b=32\\c=36\\d=28\end{matrix}\right.\)

Bài 4:

Gọi số máy 3 đội theo thứ tự là \(a,b,c\in \mathbb{N^*},máy\)

Áp dụng tc dtsbn:

\(4a=6b=8c\Rightarrow\dfrac{a}{6}=\dfrac{b}{4}=\dfrac{c}{3}=\dfrac{a-b}{6-4}=\dfrac{2}{2}=1\\ \Rightarrow\left\{{}\begin{matrix}a=6\\b=4\\c=3\end{matrix}\right.\)

Vậy ...

Đề bài thấy hơi sao sao ấy

Dễ nhưng dài lắm :)) cô cho lm đầy 

12D

Bài 1:

\(a,=\left(\dfrac{11}{19}+\dfrac{8}{19}\right)+\left(\dfrac{19}{18}-\dfrac{1}{18}\right)+5,2=1+1+5,2=7,2\\ c,=\left(\dfrac{5}{12}:\dfrac{10}{3}\right)+\left(\dfrac{1}{6}\right)^2=\dfrac{1}{8}+\dfrac{1}{36}=\dfrac{11}{72}\\ d,=\dfrac{2^4\cdot2^3}{2^6}=2\)

Bài 2:

\(a,\Rightarrow\dfrac{2}{3}x=\dfrac{3}{10}\Rightarrow x=\dfrac{9}{20}\\ b,\Rightarrow x=\dfrac{-2\cdot27}{3,6}=-15\\ c,\Rightarrow\left|x-12\right|=2017\\ \Rightarrow\left[{}\begin{matrix}x-12=2017\\12-x=2017\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2029\\x=-2005\end{matrix}\right.\)

A)x=10cm

B)x=11cm