2x-2016=24*4
Câu 3 (1,5 điểm). Tìm x, biết:
a) x + 2006 = 2021
b) 2x – 2016 = 24 x 4
c) 3(2x + 1)3 = 81
a: x=15
c: \(\Leftrightarrow2x+1=3\)
hay x=1
a) \(\Rightarrow x=2021-2006=15\)
b) \(\Rightarrow2x-2016=64\Rightarrow2x=2016+64=2080\Rightarrow x=1040\)
c) \(\Rightarrow\left(2x+1\right)^3=81:3=27\Rightarrow2x+1=3\)
\(\Rightarrow2x=3-1=2\Rightarrow x=1\)
`a) x= 15`
`b) 2x-2016=16\(\times\)4`
`⇔ 2x-2016=64`
`⇔ 2x= 2080`
`⇔ x= 1040`
`c) 3(2x+1)^3 =81`
`⇔ (2x+1)^3 =27`
`⇔ (2x+1)^3 =3^3`
`⇔ 2x+1=3`
`⇔ x= 1`
tính C=(201626+201624+201622+...+20162+1)/(201624+201622+...+20164+1)
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mình cảm ơn nhiều
\(\frac{2016^{26}+2016^{24}+...+2016^4+2016^2}{2016^{24}+2016^{22}+...+2016^2+1}\) \(=\frac{2016^2.\left(2016^{24}+2016^{22}+...+2016^2+1\right)}{2016^{24}+2016^{22}+...+2016^2+1}\)
\(=\frac{2016^2}{1}=2016^2\)
(2x^+x-2015)^2+4(2x^+x-2016)^2=4(2x^+x-2015)(2x^+x-2016) giai phuong trinh
Sửa đề:
\((2x^2+x-2015)^2+4(x^2-5x-2016)^2=4(2x^2+x-2015)(x^2-5x-2016)\)
\(\Rightarrow\left(2x^2+x-2015\right)^2-2.\left(2x^2+x-2015\right).2.\left(x^2-5x-2016\right)+[2.\left(x^2-5x-2016\right)]^2=0\)
\(\Rightarrow[2x^2+x-2015-2.\left(x^2-5x-2016\right)]^2=0\)
\(\Rightarrow11x+2017=0\)
\(\Rightarrow x=\frac{-2017}{11}\)
so sánh A và B biết
A = 242015 + 4 / 242016 + 4
B = 242016 + 4 / 242017 + 4
giúp mình với, mình sẽ tick cho ai nhanh nhất nè
Tìm x thuộc Z, biết:
a) I-3I.I2x-1I-(-13)=40
b) (24-3x).(x2-16)=0.1^2016
c) 32x+4-9x+1=648
a: =>3|2x-1|=40-13=27
=>|2x-1|=9
=>2x-1=9 hoặc 2x-1=-9
=>x=-4 hoặc x=5
b: =>(24-3x)(x-4)(x+4)=0
=>x-4=0; x+4=0; 3x-24=0
=>x=4; x=-4; x=8
c: =>\(3^{2x+4}-3^{2x+2}=648\)
=>\(3^{2x+2}\cdot8=648\)
=>2x+2=4
=>x=1
giải pt
`(2x^2 +x-2016)^2 +4(x^2 -3x-1000)^2 = 4(2x^2 +x-2016)(x^2 -3x-1000)`
Đặt: \(\left\{{}\begin{matrix}a=2x^2+x-2016\\b=x^2-3x-1000\end{matrix}\right.\). Phương trình trở thành:
\(a^2+4b^2=4ab\)
\(\Leftrightarrow a^2-4ab+4b^2=0\)
\(\Leftrightarrow\left(a-2b\right)^2=0\Leftrightarrow a=2b\)
\(\Rightarrow2x^2+x-2016=2\left(x^2-3x-1000\right)\)
\(\Leftrightarrow7x=16\Leftrightarrow x=\dfrac{16}{7}\)
Vậy: \(x=\dfrac{16}{7}\)
Giải phương trình (2x^2 +x -2017)^2 + 4(x^2 -5x-2016)^2=4(2x^2+x-2017)(x^2-5x-2016)
\(\Leftrightarrow\left(2x^2+x-2017\right)^2-4\left(2x^2+x-2017\right)\left(x^2-5x-2016\right)+4\left(x^2-5x-2016\right)^2=0\)
\(\Leftrightarrow\left(2x^2+x-2017-2\left(x^2-5x-2016\right)\right)^2=0\)
\(\Leftrightarrow11x-6049=0\)
\(\Rightarrow x=\frac{6049}{11}\)
tìm x,y biết :
a, 3 - 2x = 3.(5-x) + 4
b, 4 - ( 7x + 2017 ) = 6 . ( 5-x) - 2017
c, 15 - x (x+1) = 4 - x^2 + 2x
d, -4.(x-5) + 2016 = 3.(8-x)-(2x - 2016)
a, 3 - 2x = 3 . (5 - x) + 4
3 - 2x = 15 - 3x + 4
-2x + 3x = 15 + 4 - 3
x = 16
b, 4 - (7x + 2017) = 6 . (5 - x) - 2017
4 - 7x - 2017 = 30 - 6x - 2017
-7x + 6x = 30 - 2017 - 4 + 2017
-x = 26
x = -26
c, 15 - x . (x + 1) = 4 - x^2 + 2x
15 - x^2 - x = 4 - x^2 + 2x
-x^2 - x + x^2 - 2x = 4 - 15
-3x = -11
x = 11/3
d, -4 . (x - 5) + 2016 = 3 . (8 - x) - (2x - 2016)
-4x + 20 + 2016 = 24 - 3x - 2x + 2016
-4x + 3x +2x = 24 + 2016 - 20 - 2016
x = 4
đúng 100%
Tính 2016 * 105 - 2016 * 4 - 2016=
Tìm x biết : x * 24 + x * 6 = 240
Tìm x biết : x -167 * 15 = 167 * 185
Tính 173* 105 + 173 * 96 - 173 =
\(2016\times105-2016\times4-2016\)
\(=2016\times\left(105-4-1\right)\)
\(=2016\times100\)
\(=201600\)
\(x\times24+x\times6=240\)
\(x\times\left(24+6\right)=240\)
\(x\times30=240\)
\(x=240:30\)
\(x=8\)
\(x-167\times15=167\times185\)
\(x-2505=30895\)
\(x=30895+2505\)
\(x=33400\)
\(173\times105+173\times96-173\)
\(=173\times\left(105+96-1\right)\)
\(=173\times200\)
\(=34600\)
1. 2016 x 105 - 2016 x 4 - 2016
= 211680 - 8064 - 2016
= 203616 - 2016
= 201600
2. X x 24 + X x 6 = 240
X x (24 + 6) = 240
X x 30 = 240
X = 240 : 30
X = 8
3. X - 167 x 15 = 167 x 185
X - 2505 = 30895
X = 30895 - 2505
X = 28390
4. 173 x 105 + 173 x 96 - 173
= 18165 + 16608 - 173
= 34773 - 173
= 34600