Tìm x, biết:
a) ( 3x - 6 ) . 3 = 32
b) x - 7 = -5
c) 123 - 5 . ( x + 4 ) = 38
Những câu hỏi liên quan
tìm số nguyên x,biết:
A,-4/7=x/21
B.(x-3)/15=1/-5
C.(3x+8)/-12=-5/30
a,-4/7=x/21
-12/21 = x/21
x= -12
b,(x-3)/15=1/-5
x - 3 = -1/5 * 15
x - 3 = -3
x = 0
c,.(3x+8)/-12=-5/30
=> 3x + 8 = 2
=> 3x=-6
=>x=-2
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tìm x
123 - 5. ( x+4 ) = 38
( 3x - 2^4 ) . 7^3 = 2 . 7^4
123 - 5 . ( x + 4 ) = 38
5 . ( x + 4 ) = 123 - 38
5 . ( x + 4 ) = 85
x + 4 = 85 : 5
x + 4 = 17
x = 17 - 4
x = 13
( 3x - 24 ) . 73 = 2 . 74
( 3x - 16 ) . 343 = 2 . 2401
( 3x - 16 ) . 343 = 4802
3x - 16 = 4802 : 343
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
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123 - 5( x + 4 ) = 38
=> 5( x + 4 ) = 123 - 38
=> x + 4 = 85 ÷ 5
=> x = 17 - 4
=> x = 13
(3x - 24 ) · 73 = 2·74
=> ( 3x - 16 ) = 2 . 74 ÷ 73
=> 3x - 16 = 14
=> 3x = 16 + 14
=> x = 30 ÷ 3
=> x = 10
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[ 8 x - 120 ÷ 4 ] ×3^3=3^6
123-5 (x+4)=38
(3x- 2^4)×7^3=2×7^4
\(\left[8x-120:4\right]\times3^3=3^6.\)
\(8x-120:4=3^3\)
\(8x-30=27\)
\(8x=27+30\)
\(8x=57\)
\(x=19\)
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123 - 5.(x + 4) = 38
123 - 5x - 20 = 38
-5x = 38 - 123 + 20
-5x = -65
x = -65 : -5
x = 13
Vậy x = 13
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\(123-5\left(x+4\right)=38\)
\(5\left(x+4\right)=123-38\)
\(5\left(x+4\right)=85\)
\(\left(x+4\right)=17\)
\(x=17-4\)
\(x=13\)
\(\left(3x-2^4\right)\times7^3=2\times7^4\)
\(\left(3x-2^4\right)=2\times7^4:7^3\)
\(\left(3x-2^4\right)=2\times7\)
\(3x-2^4=14\)
\(3x-16=14\)
\(3x=30\)
\(x=30:3\)
\(x=10\)
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Xem thêm câu trả lời
Tìm x,y,z biết:
a) 3x=2y, 7y=5z và x-y+z=32
b) \(\dfrac{x}{2}\)=\(\dfrac{y}{3}\) và x.y=24
c)\(\dfrac{x-1}{2}\)=\(\dfrac{y-2}{3}\)=\(\dfrac{z-3}{4}\) và 2x+3y-z=50
d)\(\dfrac{x}{2}\)=\(\dfrac{y}{3}\)=\(\dfrac{z}{5}\) và x.y.z=810
tìm x thuộc N biết
a 219-7(x+1)=100
b 123-5.(x+40)=38
c (3x-6).3=34
d 42.x=39.42-37.42
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a,219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1= 119:7
x+1= 17
x= 17-1
x=16
Vậy x=16
b,123-5.(x+40)=38
5.(x+40)=123-38
5.(x+40)=85
x+40= 85:5
x+40=17
x= 17-40
x=-23
Vậy x=-23
c,(3x-6).3=34
3x-6 =34:3
3x-6 =33
3x-6 =27
3x =27+6
3x =33
x =33:3
x =11
Vậy x=11
d, 42.x=39.42-37.42
42.x=1638-1554
42.x=84
x =84:42
x =2
Vậy x=2
Nhớ nhé, học giỏi ^^
Tìm x
a, 123 - 5 . ( x + 4 ) = 38
b, ( 3x - 24 ) . 73 = 2 . 74
c, ( x : 3 - 4 ) . 5 = 15
a) 123 - 5 (x + 4) = 38
5 (x + 4) = 123 - 38
5 (x + 4) = 85
x + 4 = 85 : 5
x + 4 = 17
x = 17 - 4
x = 13
b) (3x - 24) . 73 = 2 . 74
3x - 24 = 2 . 74 : 73
3x - 24 = 2 . 7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
c) (x : 3 - 4) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 7 . 3
x = 21
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\(a,123-5.\left(x+4\right)=38\)
\(5.\left(x+4\right)=123-38=85\)
\(x+4=85:5=17\)
\(x=17-4=13\)
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tìm số tự nhiên x, biết:
a) 21 - 4x = 13
b) 30 : (x - 3) + 1 = \(4^5\) : \(4^3\)
c) (x - 1)\(^3\) + 5 . 6 = 38
8 tháng 9 2021 lúc 14:22
Bài 4: Tìm x, biết:
a) 3(2x – 3) + 2(2 – x) = –3 ; b) x(5 – 2x) + 2x(x – 1) = 13 ;
c) 5x(x – 1) – (x + 2)(5x – 7) = 6 ; d) 3x(2x + 3) – (2x + 5)(3x – 2) = 8 ;
e) 2(5x – 8) – 3(4x – 5) = 4(3x – 4) + 11; f) 2x(6x – 2x 2 ) + 3x 2 (x – 4) = 8.
\(a,3\left(2x-3\right)+2\left(2-x\right)=-3\\ \Leftrightarrow6x-9+4-2x=-3\\ \Leftrightarrow4x=2\\ \Leftrightarrow x=\dfrac{1}{2}\\ b,x\left(5-2x\right)+2x\left(x-1\right)=13\\ \Leftrightarrow5x-2x^2+2x^2-2x=13\\ \Leftrightarrow3x=13\\ \Leftrightarrow x=\dfrac{13}{3}\\ c,5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\\ \Leftrightarrow5x^2-5x-5x^2-3x+14=6\\ \Leftrightarrow-8x=-8\\ \Leftrightarrow x=1\\ d,3x\left(2x+3\right)-\left(2x+5\right)\left(3x-2\right)=8\\ \Leftrightarrow6x^2+9x-6x^2-11x+10=8\\ \Leftrightarrow-2x=-2\\ \Leftrightarrow x=1\)
\(e,2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\\ \Leftrightarrow10x-16-12x+15=12x-16+11\\ \Leftrightarrow-14x=-4\\ \Leftrightarrow x=\dfrac{2}{7}\\ f,2x\left(6x-2x^2\right)+3x^2\left(x-4\right)=8\\ \Leftrightarrow12x^2-4x^3+3x^3-12x^2=8\\ \Leftrightarrow-x^3-8=0\\ \Leftrightarrow-\left(x^3+8\right)=0\\ \Leftrightarrow-\left(x+2\right)\left(x^2-2x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\\x\in\varnothing\left(x^2-2x+4=\left(x-1\right)^2+3>0\right)\end{matrix}\right.\)
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Bài 4:
a: Ta có: \(3\left(2x-3\right)-2\left(x-2\right)=-3\)
\(\Leftrightarrow6x-9-2x+4=-3\)
\(\Leftrightarrow4x=2\)
hay \(x=\dfrac{1}{2}\)
b: Ta có: \(x\left(5-2x\right)+2x\left(x-1\right)=13\)
\(\Leftrightarrow5x-2x^2+2x^2-2x=13\)
\(\Leftrightarrow3x=13\)
hay \(x=\dfrac{13}{3}\)
c: Ta có: \(5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\)
\(\Leftrightarrow5x^2-5x-5x^2+7x-10x+14=6\)
\(\Leftrightarrow-8x=-8\)
hay x=1
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a/ \(3\left(2x-3\right)+2\left(2-x\right)=-3\)
\(\Leftrightarrow6x-9+4-2x=-3\)
\(\Leftrightarrow4x=2\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
Vậy: \(x=\dfrac{1}{2}\)
===========
b/ \(x\left(5-2x\right)+2x\left(x-1\right)=13\)
\(\Leftrightarrow5x-2x^2+2x^2-2x=13\)
\(\Leftrightarrow3x=13\)
\(\Leftrightarrow x=\dfrac{13}{3}\)
Vậy: \(x=\dfrac{13}{3}\)
==========
c/ \(5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\)
\(\Leftrightarrow5x^2-5x-5x^2+7x-10x+14=6\)
\(\Leftrightarrow-8x=-8\)
\(\Leftrightarrow x=1\)
Vậy: \(x=1\)
==========
d/ \(3x\left(2x+3\right)-\left(2x+5\right)\left(3x-2\right)=8\)
\(\Leftrightarrow6x^2+9x-6x^2+4x-15x+10=8\)
\(\Leftrightarrow-2x=-2\)
\(\Leftrightarrow x=1\)
Vậy: \(x=1\)
==========
e/ \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x-16+11\)
\(\Leftrightarrow-14x=-4\)
\(\Leftrightarrow x=\dfrac{2}{7}\)
Vậy: \(x=\dfrac{2}{7}\)
==========
f/ \(2x\left(6x-2x^2\right)+3x^2\left(x-4\right)=8\)
\(\Leftrightarrow12x^2-4x^3+3x^3-12x^2=8\)
\(\Leftrightarrow-x^3=8\)
\(\Leftrightarrow x=-2\)
Vậy: \(x=-2\)
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1)(2x+1)-7=14
2)15-(3x-1)+11=59
3)70-5(x-3)=45
4)412-15.(nhân)(27-x)=97
5)2008(2x+7)=112
6)126-17(3x-5)=7
7)(2600+6400)-3x=1200
8)123-5(x+4)=38
GIÚP MIK GIẢI NHÉ !!! @.@