Tìm x biết
7200 _ 7
7 x 7 x 7 x 7 x..........x 380 chữ số 7
Tìm chữ số tận cùng
a, tìm GTLN A= x(5-3x)
b, cho x+y=7. tìm GTLN xy
c, tìm GTNN của F= x(x-3)(x-4)(x-7)
a) A = x( 5 - 3x ) = -3x2 + 5x = -3( x2 - 5/3x + 25/36 ) + 25/12
= -3( x - 5/6 )2 + 25/12 ≤ +25/12 ∀ x
Dấu "=" xảy ra khi x = 5/6
Vậy MaxA = 25/12 <=> x = 5/6
b) Từ x + y = 7 => x = 7 - y
Ta có : xy = ( 7 - y ).y = 7y - y2 = -( y2 - 7y + 49/4 ) + 49/4 = -( y - 7/2 )2 + 49/4 ≤ 49/4 ∀ y
Dấu "=" xảy ra <=> y = 7/2 => x = 7/2
Vậy Max(xy) = 49/4 <=> x = y = 7/2
( nếu cho x,y dương thì Cauchy nhanh gọn luôn :)) )
c) F = x( x - 3 )( x - 4 )( x - 7 )
= [ x( x - 7 ) ][ ( x - 3 )( x - 4 ) ]
= ( x2 - 7x )( x2 - 7x + 12 )
Đặt t = x2 - 7x
F = t( t + 12 ) = t2 + 12t = ( t2 + 12t + 36 ) - 36 = ( t + 6 )2 - 36
= ( x2 - 7x + 6 )2 - 36 ≥ -36 ∀ x
Dấu "=" xảy ra khi x2 - 7x + 6 = 0 <=> x = 1 hoặc x = 6
Vậy MinF = -36 <=> x = 1 hoặc x = 6
Tìm x, biết:
|x+7|-x=7
\(\Leftrightarrow\left|x+7\right|=x+7\)
\(\Leftrightarrow x+7\ge0\)
hay \(x\ge-7\)
Dạng 2 : Tìm x Bài 1: Tìm x biết :
a) ( x – 16 ) – 74 = 0 b) (3 x – 5) .7 mũ 3 = 7 mũ 4
c) 560 – 13x = 365 d) 275 – 7( x + 1) = 100
e) 3 x 7 14 3.2 mũ 3 f) 7x – 49 = 105
g) 5x – 16 = 14 h) 3x – 138 = 23 . 2 2
tìm x biết
x.(2x+7)=0
x.(2x+7)>0
x.(2x+7)<0
a , x.(2x+7)=0
(=) x = 0
2x + 7 = 0
(=) x = 0
2x = -7
(=) x = 0
x = -7/2
Mấy câu bạn hỏi có người hỏi rồi bạn tự tham khảo nhé
`x(2x+7)=0`
`<=>x=0` hoặc `2x+7=0`
`<=>x=0` hoặc `x=-7/2`
`x(2x+7)>0`
\(< =>\left[{}\begin{matrix}\left\{{}\begin{matrix}x>0\\2x+7>0\end{matrix}\right.\\\left\{{}\begin{matrix}x< 0\\2x+7< 0\end{matrix}\right.\end{matrix}\right.\\ < =>\left[{}\begin{matrix}\left\{{}\begin{matrix}x>0\\x>-\dfrac{7}{2}\end{matrix}\right.\\\left\{{}\begin{matrix}x< 0\\x< -\dfrac{7}{2}\end{matrix}\right.\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x>0\\x< -\dfrac{7}{2}\end{matrix}\right.\)
`x(2x+7)<0`
\(< =>\left[{}\begin{matrix}\left\{{}\begin{matrix}x>0\\2x+7< 0\end{matrix}\right.\\\left\{{}\begin{matrix}x< 0\\2x+7>0\end{matrix}\right.\end{matrix}\right.\\ < =>\left[{}\begin{matrix}\left\{{}\begin{matrix}x>0\\x< -\dfrac{7}{2}\end{matrix}\right.\left(voli\right)}\\\left\{{}\begin{matrix}x< 0\\x>-\dfrac{7}{2}\end{matrix}\right.\end{matrix}\right.\\ < =>-\dfrac{7}{2}< x< 0\)
Tìm x
(x+7)(3x-15)=0
4x(x+7)=2(x+7)
(x-3)2 - x(x - 4) = 5
\(\left(x+7\right)\left(3x-15\right)=0\\ \Rightarrow3\left(x-5\right)\left(x+7\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=-7\end{matrix}\right.\\ 4x\left(x+7\right)=2\left(x+7\right)\\ \Rightarrow4x\left(x+7\right)-2\left(x+7\right)=0\\ \Rightarrow2\left(2x-1\right)\left(x+7\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-7\end{matrix}\right.\\ \left(x-3\right)^2-x\left(x-4\right)=5\\ \Rightarrow x^2-6x+9-x^2+4x-5=0\\ \Rightarrow-2x+4=0\\ \Rightarrow-2x=-4\Rightarrow x=2\)
hưng phúc đầy đủ chưa bạn nhỉ?
1) \(\left(x+7\right)\left(3x-15\right)=0\)
⇔\(\left[{}\begin{matrix}x+7=0\\3x-15=0\end{matrix}\right.\)
⇔\(\left[{}\begin{matrix}x=-7\\x=5\end{matrix}\right.\)
2) \(4x\left(x+7\right)=2\left(x+7\right)\)
\(2\left(2x+1\right)\left(x+7\right)=0\)
⇔\(\left[{}\begin{matrix}2x+1=0\\x+7=0\end{matrix}\right.\)
⇔\(\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=-7\end{matrix}\right.\)
c: Ta có: \(\left(x-3\right)^2-x\left(x-4\right)=5\)
\(\Leftrightarrow x^2-6x+9-x^2+4x=5\)
\(\Leftrightarrow-2x=-4\)
hay x=2
Tìm x biết: x - 1 = \(\dfrac{6}{7}\) + \(\dfrac{1}{7}\) x\(\dfrac{2}{7}\) + \(\dfrac{1}{7}\) x \(\dfrac{5}{7}\)
\(\Rightarrow x-1=\dfrac{6}{7}+\dfrac{1}{7}\times\left(\dfrac{2}{7}+\dfrac{5}{7}\right)=\dfrac{6}{7}+\dfrac{1}{7}\times1\\ \Rightarrow x-1=\dfrac{6}{7}+\dfrac{1}{7}=1\\ \Rightarrow x=1+1=2\)
tìm x:
(x - 7)x+1 - (x - 7)x-11=0
\(\Leftrightarrow\left(x-7\right)^{x-11}\left[\left(x-7\right)^{12}-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-7\right)^{x-11}=0\\\left(x-7\right)^{12}=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-7=0\\x-7=1\\x-7=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=8\\x=6\end{matrix}\right.\)
\(\Leftrightarrow\left(x-7\right)^{x+1}\left[\left(x-7\right)-\left(x-7\right)^{12}\right]=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-7=0\\x-7=1\\x-7=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=8\\x=6\end{matrix}\right.\)
ae hok thật là giỏi nhưng chắc ko còn ai có thể đọc được tin nhắn này của mik đâu ai mà vẫn đọc được thì cho mik để mik bít nhá
Tìm x X x 3/7 + X x 4/7 = 4
` x xx 3/7 + x xx 4/7 = 4 `
`=> x xx (3/7 + 4/7) =4`
`=> x xx 7/7=4`
`=>x xx 1=4`
`=>x= 4:1`
`=>x=4`
`x xx 3/7 + x xx 4/7=4`
`=> x xx (3/7+4/7)=4`
`=> x xx 7/7=4`
`=> x xx 1=4`
`=> x=4`
Tìm x X+7/11+X+7/12