Tìm x biết:
x/-28=42/49
tìm x biết:x = 35 - 27 + 28 x = ?
Tìm x biết:
x(x+5)(x-5)-(x+2)(x^2-2x+4)=42
\(x\left(x+5\right)\left(x-5\right)-\left(x+2\right)\left(x^2-2x+4\right)=42\)
\(\Leftrightarrow x\left(x^2-25\right)-\left(x^3+8\right)=42\)
\(\Leftrightarrow x^3-25x-x^3-8=42\)
\(\Leftrightarrow-25x-8=42\)
\(\Leftrightarrow-25x=42+8\)
\(\Leftrightarrow-25x=50\)
\(\Leftrightarrow x=-\dfrac{50}{25}=-2\)
Tìm x biết:x 12 x x = 42:1/10
ta có :
\(12\times x=42:\frac{1}{10}\)
ha y \(12\times x=42\times10=420\) nên : \(x=420:12=35\)
Vậy x = 35
\(\frac{x}{27}=\frac{2}{3}\)
Ta có:
\(\frac{2}{3}=\frac{18}{27}\)
\(\Leftrightarrow\frac{x}{27}=\frac{18}{27}\)
\(\Leftrightarrow x=18\)
\(\frac{35}{49}=\frac{10}{y}\)
Ta có:
\(\frac{35}{49}=\frac{5}{7}=\frac{10}{14}\)
\(\Leftrightarrow\frac{10}{14}=\frac{10}{y}\)
\(\Leftrightarrow y=14\)
Tìm x, biết:x+5 phần 48 = 7 phần 42
Tìm x,y là số tự nhiên biết:x(y-3)+5y=28
Đặt tính rồi tính:
a) 28 + 35 63 – 28 63 – 35
b) 42 + 49 91 – 42 91 – 49
\(\begin{array}{*{20}{c}}{a)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{28}\\{35}\end{array}}\\\hline{\,\,\,\,63}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{63}\\{28}\end{array}}\\\hline{\,\,\,\,35}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{63}\\{35}\end{array}}\\\hline{\,\,\,28}\end{array}\)
\(\begin{array}{*{20}{c}}{b)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{42}\\{49}\end{array}}\\\hline{\,\,\,\,91}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{91}\\{42}\end{array}}\\\hline{\,\,\,49}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{91}\\{49}\end{array}}\\\hline{\,\,\,\,42}\end{array}\)
Tìm các số x và y biết
1) 4/x= y/21=28/49. 2) x/2=3/y. 3)42/54=7/x
4) 2/3 =y/15. 5)6/10 = 3/x =y/20
\(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{28}{49}=\dfrac{28:7}{49:7}=\dfrac{4}{9}\\ Vậy:x=\dfrac{4.9}{4}=9\\ y=\dfrac{4.21}{9}=\dfrac{28}{3}\)
\(\dfrac{x}{2}=\dfrac{3}{y}\\ \Leftrightarrow x.y=2.3=6\\ Vậy:\left[{}\begin{matrix}\left(x;y\right)=\left(1;6\right)=\left(6;1\right)\\\left(x;y\right)=\left(2;3\right)=\left(3;2\right)\end{matrix}\right.\)
\(3,\\ \dfrac{42}{54}=\dfrac{42:6}{54:6}=\dfrac{7}{9}\\ \dfrac{42}{54}=\dfrac{7}{x}=\dfrac{7}{9}\\ Vậy:x=\dfrac{7.9}{7}=9\)
a) 7 x 5 = ..... 7 x 6 = ..... 7 x 8 = ..... 7 x 4 = .....
35 : 7 = ..... 42 : 7 = ..... 56 : 7 = ..... 28 : 7 = .....
b) 42 : 7 = ..... 35 : 7 = ..... 63 : 7 = ..... 16 : 2 = .....
14 : 7 = ..... 49 : 7 = ..... 7 : 7 = ..... 48 : 6 = .....
28 : 7 = ..... 70 : = ..... 21 : 7 = ..... 56 : 7 = .....
a) 7 x 5 = 35 7 x 6 = 42 7 x 8 = 56 7 x 4 = 28
35 : 7 = 5 42 : 7 = 6 56 : 7 = 8 28 : 7 = 4
b) 42 : 7 = 6 35 : 7 = 5 63 : 7 = 9 16 : 2 = 8
14 : 7 = 2 49 : 7 = 7 7 : 7 = 1 48 : 6 = 8
28 : 7 = 4 70 : =10 21 : 7 = 3 56 : 7 = 8