Bài 2,3 ik

Bài 2:

\(a,1\dfrac{9}{10}=1,9;2\dfrac{66}{100}=2,66;3\dfrac{72}{100}=3,72;4\dfrac{999}{1000}=4,999\\ b,8\dfrac{2}{10}=8,2;36\dfrac{23}{100}=36,23;54\dfrac{7}{100}=54,07;12\dfrac{254}{1000}=12,254\)

Bài 3:

\(a,0,5=\dfrac{5}{10};0,03=\dfrac{3}{100};7,5=\dfrac{75}{10}\\ b,0,92=\dfrac{92}{100};0,006=\dfrac{6}{1000};8,92=\dfrac{892}{100}\)

Tham thảo:P
Bài 2
a) 19/10; 266/100; 372/100; 4999/100

b) 82/10; 3623/100; 12254/1000

Bài 3
a) 5/10; 3/100; 75/10

b) 92/100; 6/1000; 892/1000

3. A (trọng âm rơi vào âm 2, A và C âm 1 - D mờ quá em à)

4. B (trọng âm rơi vào âm 3, A và C âm 2 - D thì không nhìn rõ được là từ gì)

a: =>x=13/52+8/52=21/52

b: =>x=1/36-27/36=-26/36=-13/18

c: =>x=24/60+15/60-20/60=19/60

d: =>x/15=9/15-10/15=-1/15

=>x=-1

a, x = 21/52 ; b x = -13/18 

c, x = 19/60 ; d, x = -1 

\(\dfrac{-1}{3}+\dfrac{7}{6}+\dfrac{3}{2}=\dfrac{-2}{6}+\dfrac{7}{6}+\dfrac{9}{6}=\dfrac{5}{6}+\dfrac{9}{6}=\dfrac{14}{6}=\dfrac{7}{3}\)

`-1/3 + 7/6 + 3/2 = -2/6 + 7/6 + 9/6 =14/6 = 7/3 `

= - 2/6 + 7/6 + 9/6

= 5/6 + 9/6

=14/6 => 7/3

tui mới lớp 4

a, ta có A(x)=2x³+7x²+ax+b

                   =(2x³+2x²+2x)+(5x²+5x+5)+ax-7x+b-5

                   =2x(x²+x+1)+5(x²+x+1)+(a-7)x+(b-5)

                   =(x²+x+1)(2x+5)+(a-7)x+(b-5)

ta có: (x²+x+1)(2x+5)⋮B(x)

→để A(x)⋮B(x) thì (a-7)x+(b-5)=0

→\(\left\{{}\begin{matrix}a-7=0\\b-5=0\end{matrix}\right.\) ⇔\(\left\{{}\begin{matrix}a=7\\b=5\end{matrix}\right.\)

vậy ....

mk trình bày hơi tắt xíu 

bn cố gắng dịch nhé

a) \(A\left(x\right)=2x^3+7x^2+ax+b=\left(x^2+x-1\right)\left(2x+5\right)+\left(a-3\right)x+b+5\)

\(=\left(2x+5\right)B\left(x\right)+\left(a-3\right)x+b+5\)

Để \(A\left(x\right)\) chia hết cho \(B\left(x\right)\) thì 

\(\left(a-3\right)x+b+5=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}a-3=0\\b+5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=3\\b=-5\end{matrix}\right.\)

b) \(A\left(x\right)=ax^3+bx-24=\left(ax-4a\right)\left(x^2+4x+3\right)+\left(b+13a\right)x+12a-24\)

\(=\left(ax-4a\right)\left(x^2+4x+3\right)+\left(b+13a\right)x+12a-24\)

Để \(A\left(x\right)\) chia hết cho \(B\left(x\right)\) thì 

\(\left(b+13a\right)x+12a-24=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}b+13a=0\\12a-24=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=2\\b=-26\end{matrix}\right.\)

c) Tương tự. 

Trắc nghiệm 

1/A

2/A

3/B

4/D

5/C

6/B

7/A

8/C

9/B

10/A

11/B

12/A

21 lít

Đ/S: 21 lít
chúc bn hk tốt

21 l

 (26 + 53 ) +(42 -26-55-53)

=79 + ( 16 -55 - 53 )

=79 + (-39-53)

=79 -39 - 53

=40 - 53 = -13

( 26 + 53 ) + ( 42 -26 - 55 - 53 )

= 79 + ( 16 - 55 - 53 )

= 79 + ( -39 - 53 )

= 79 + ( -92 )

= -13.

\(\left(26+53\right)+\left(42-26-55-53\right)\)

\(=26+53+42-26-55-53\)

\(=\left(26-26\right)+\left(53-53\right)+\left(42-55\right)\)

\(=0+0+\left(-13\right)\)

\(=-13\)

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The harder you study, the easier you’ll find exams

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The more sport I practised, the fitter I got

The more I explained it to him, the less he understood

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The sooner you come, the better

The more attention you pay to him, the worse

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The longer I listened to his story, the more surprise I was

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