giúp mik vs mik cảm ơn nhiều ạ
Giúp mik vs ạ mik cảm ơn nhiều ạ
a) \(6x^2-8x=2x\left(3x-4\right)\)
b) \(21x^2y^7-12x^5y^3=3x^2y^3\left(7y^4-4x^3\right)\)
c) \(4x^2y-6xy^2=2xy\left(2x-3y\right)\)
d) \(24x^2y-18xy^2=6xy\left(4x-3y\right)\)
e) \(9x^2y^2+12x^2y-15xy^2=3xy\left(3xy+4x-5y\right)\)
f) \(x\left(x+y\right)+y\left(-x-y\right)=x\left(x+y\right)-y\left(x+y\right)=\left(x+y\right)\left(x-y\right)\)
g) \(3\left(x+y\right)+x\left(x+y\right)=\left(x+y\right)\left(x+3\right)\)
h) \(3x\left(x-y\right)-6y\left(y-x\right)=3x\left(x-y\right)+6y\left(x-y\right)=3\left(x-y\right)\left(x+2y\right)\)
Giúp mik vs ạ mik cảm ơn nhiều ạ
Giúp mik vs ạ mik cảm ơn nhiều lắm ạ
beautifully
excitedly
interesting
collected
arrangements
peacefully
excited
different
Giúp mik vs ạ mik cảm ơn nhiều lắm ạ
a,\(x^2-7x+6=x^2-x-6x+6\)
\(=x\left(x-1\right)-6\left(x-1\right)\)
\(=\left(x-6\right)\left(x-1\right)\)
a) x2-7x+6=(x2-x)-(6x-6)=x(x-1)-6(x-1)=(x-6)(x-1)
b) x2-6x+3=(x2-6x+9)-6=(x-3)2-\(\sqrt{6^2}\)=(x-3-\(\sqrt{6}\))(x-3+\(\sqrt{6}\))
c) x2-4x+3=(x2-x)-(3x-3)=x(x-1)-3(x-1)=(x-3)(x-1)
d) 3x2-5x+2=(3x2-3x)-(2x-2)=3x(x-1)-2(x-1)=(3x-2)(x-1)
e) 7x2-x-6=(7x2-7x)+(6x-6)=7x(x-1)+6(x-1)=(7x+6)(x-1)
f) 3x2-5x-8=(3x2+3x)-(8x+8)=3x(x+1)-8(x+1)=(3x-8)(x+1)
g) x2-6x+5=(x2-x)-(5x-5)=x(x-1)-5(x-1)=(x-5)(x-1)
h) x2-2x-3=(x2-2x+1)-4=(x-1)2-22=(x-1-2)(x-1+2)=(x-3)(x+1)
i) x2-x-12=(x2+3x)-(4x+12)=x(x+3)-4(x+3)=(x-4)(x+3)
giúp mik vs ạ, mik cần gấp !!! cảm ơn nhiều ạ
Lời giải:
ĐKĐB $\Rightarrow \frac{2}{c}=\frac{a+b}{ab}\Rightarrow c(a+b)=2ab$
Khi đó:
$\frac{a}{b}-\frac{a-c}{c-b}=\frac{a(c-b)-b(a-c)}{b(c-b)}=\frac{ac-ab-ab+bc}{b(c-b)}=\frac{c(a+b)-2ab}{b(c-b)}=\frac{2ab-2ab}{b(c-b)}=0$
$\Rightarrow \frac{a}{b}=\frac{a-c}{c-b}$ (đpcm)
Giúp mik lm bài tập vs ạ mik cảm ơn nhiều ạ
1 interested in travelling by plane
2 15 minutes riding his bike to school
3 is made by my mother everymorning
4 take care of her little brother
5 able to speak 2 languages when he was young
6 able to play the piano
7 is played all over VN
8 to play voleyball very well when he was young
9 to go fishing when he was young
10 way to the shopping mall
mn giúp mik vs ạ mik cảm ơn nhiều :)
a: \(x^3+8=\left(x+2\right)\left(x^2-2x+4\right)\)
b: \(27y^3+1=\left(3y+1\right)\left(9y^2-3y+1\right)\)
c: \(x^3-27=\left(x-3\right)\left(x^2+3x+9\right)\)
d: \(x^3-1=\left(x-1\right)\left(x^2+x+1\right)\)
e: \(8x^3+1=\left(2x+1\right)\left(4x^2-2x+1\right)\)
f: \(27x^3+64y^3=\left(3x+4y\right)\left(9x^2-12xy+16y^2\right)\)
g: \(x^3-\dfrac{1}{8}=\left(x-\dfrac{1}{2}\right)\left(x^2+\dfrac{1}{2}x+\dfrac{1}{4}\right)\)
mn giúp mik vs ạ mik cảm ơn nhiều :)
a: \(A=x^3+6x^2+12x+8=\left(x+2\right)^3\)
\(=50^3=125000\)
b: \(B=27x^3-54x^2y+36xy^2-8y^3=\left(3x-2y\right)^3\)
\(=\left(3\cdot4-2\cdot6\right)^3=0\)
c: \(C=x^3-3x^2+3x-1=\left(x-1\right)^3\)
\(=1000^3=1000000000\)
mn giúp mik vs ạ, mik cảm ơn nhiều
1B 2B 3D 4C 5B 6B 7A 8D 9A 10C 11D 12A