\(\frac{2.6^9.2^5.18^4}{2^2.6^8}=\frac{2.\left(2.3\right)^9.2^5.\left(2.3^2\right)^4}{2^2.\left(2.3\right)^8}=\frac{2.2^9.3^9.2^5.2^4.3^8}{2^2.2^8.3^8}=\frac{2^{19}.3^{17}}{2^{10}.3^8}=2^9.3^9\)

\(=\left(2.3\right)^9=6^9\)

Tính hợp lý

\(\frac{2.6^9.2^5.18^4}{2^2.6^8}=\frac{2^6.2^9.3^9.2^4.3^8}{2^2.2^8.3^8}=\frac{2^{19}.3^{17}}{2^{10}.3^8}=2^9.3^9=6^9\)

học tốt nhé bn

#Tịnh

\(\frac{2.6^9.2^5.18^4}{2^2.6^8}\)=\(\frac{2.\left(3.2\right)^9.2^5\left(2.3^2\right)^4}{2^2.\left(2.3\right)^8}\)=\(\frac{2.3^9.2^9.2^52^4.3^8}{2^2.2^8.3^8}\)=\(\frac{2^{1+9+5+4}.3^9}{2^{2+8}}\)=\(\frac{2^{19}.3^9}{2^{10}}\)=2⁹.3⁹=(2.3)⁹=6⁹

Chúc bn học tốt

\(\frac{2.6^9-2^5.18^4}{2^6.6^8}=\frac{2^{10}.3^9-2^9.3^8}{2^{14}.3^8}=\frac{2^9.3^8.\left(6-1\right)}{2^{14}.3^8}=\frac{5}{2^5}=\frac{5}{32}\)

= 2.2⁹.3⁹-2⁵.2⁴.3⁴.3⁴/ 2⁶.3⁸.2⁸

=2¹⁰.3⁹-2⁹.3⁸/ 2¹⁴.3⁸

=2⁹.3⁸.(2.3-1.1)/2¹⁴.3⁸

=5/32

\(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\\ =\dfrac{2\cdot\left(2\cdot3\right)^9-2^5\cdot\left(2\cdot3^2\right)^4}{2^2\cdot\left(2\cdot3\right)^8}\\ =\dfrac{2\cdot2^9\cdot3^9-2^5\cdot2^4\cdot3^8}{2^2\cdot2^8\cdot3^8}\\ =\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}\\ =\dfrac{5}{2}\)

\(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}=\dfrac{2.\left(2.3\right)^9-2^5.\left(2.3^2\right)^4}{2^2.\left(2.3\right)^8}=\dfrac{2.2^9.3^9-2^5.2^4.3^8}{2^2.2^8.3^8}=\dfrac{2^9.3^8\left(2.3-1\right)}{2^{10}.3^8}=\dfrac{5}{2}\)

Ta có:\(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}=\dfrac{2^{10}.3^9-2^9.3^8}{2^{10}.3^8}=\dfrac{2^9.3^8.\left(2.3-1\right)}{2^{10}.3^8}=\dfrac{2^9.3^8.5}{2^{10}.3^8}=\dfrac{5}{2}\)

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

=\(\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.5.3^8}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=-\frac{2}{6}=-\frac{1}{3}\)

Bằng 1/6

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