\(2^3\times2+3^{15}\div3^{13}+2020^0\)

\(=2^4+3^2+1\)

\(=16+9+1=26\)

\(2^3\times15-[115-\left(12-5\right)^2]\)

\(=8\times15-\left(115-7^2\right)\)

\(=120-115+49\)

\(=5+49=54\)

\(3^2\times75+25\times3^2-2000^1\)

\(=3^2\left(75+25\right)-2000\)

\(=9\times100-2000\)

\(=900-2000\)

\(=-1100\)

a) \(-\frac{9}{13}.\frac{12}{29}-\frac{9}{13}.\frac{17}{29}+\frac{24}{13}\)

\(=-\frac{9}{13}\left(\frac{12}{29}+\frac{17}{29}\right)+\frac{24}{13}\)

\(=-\frac{9}{13}+\frac{24}{13}=\frac{15}{13}\)

b)\(\left(\frac{5}{3}-\frac{2}{11}\right):\frac{49}{33}+\left(-\frac{3}{7}\right)^2-\left|\frac{1}{7}-\frac{1}{14}\right|\)

\(=\left(\frac{5}{3}-\frac{2}{11}\right).\frac{33}{49}+\frac{9}{49}-\left|\frac{2}{14}-\frac{1}{14}\right|\)

\(=\frac{49}{33}.\frac{33}{49}+\frac{9}{49}-\frac{1}{14}\)

\(=1+\frac{9}{49}-\frac{1}{14}=\frac{49}{49}+\frac{9}{49}-\frac{1}{14}\)

\(=\frac{58}{49}-\frac{1}{14}=\frac{109}{98}\)

a, = 89+43-32 = 132-32 = 100

b, = 25:5 = 5

c, = -27 : 9 + 49.2 = -3+98 = 95

d, = 115+85+53-(-447) = 200+53+447 = 700

Tk mk nha

bấm máy tính ok

rảnh nghe 

Bài 3: 

a: \(=-8\left(72+19-1\right)=-8\cdot90-720\)

b: \(=-27\left(1011-12-1\right)=-27\cdot998=-26946\)

c: \(=17\cdot\left[29+111\right]+29\cdot\left(-17\right)\)

\(=17\left(29+111-29\right)=17\cdot111=1887\)

d: \(=43\cdot\left(-1\right)+40=-43+40=-3\)

\(\frac{16x17-5}{16x16+11}=\frac{16x16+16-5}{16x16+11}=1\)

\(\frac{4}{3x7}+\frac{5}{7x12}+\frac{1}{12x13}+....+\frac{3}{20x23}\)

=\(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{20}-\frac{1}{23}\)

=\(\frac{1}{3}-\frac{1}{23}=\frac{20}{69}\)

a) \(\frac{16\cdot17-5}{16\cdot16+11}\)

= \(\frac{16\cdot16+16-5}{16\cdot16+11}\)

= \(\frac{16\cdot16+11}{16\cdot16+11}=1\)

\(a.\)

\(\frac{15}{33}+\frac{7}{20}+\frac{18}{33}+\frac{13}{20}\)

\(=\left(\frac{15}{33}+\frac{18}{33}\right)+\left(\frac{13}{20}+\frac{7}{20}\right)\)

\(=\frac{33}{33}+\frac{20}{20}\)

\(=1+1=2\)

\(b.\)

\(2\frac{1}{2}+\frac{4}{7}:\left(-\frac{8}{21}\right)\)

\(=\frac{5}{2}+\frac{4}{7}:\left(-\frac{8}{21}\right)\)

\(=\frac{5}{2}+\frac{4}{7}.\left(-\frac{21}{8}\right)\)

\(=\frac{5}{2}+\frac{1}{1}.\left(-\frac{3}{2}\right)\)

\(=\frac{5}{2}-\frac{3}{2}\)

\(=1\)

\(c.\)

\(\left(-\frac{1}{2}\right)^3+\frac{1}{2}:5\)

\(=-\frac{1}{8}+\frac{1}{2}.\frac{1}{5}\)

\(=-\frac{1}{8}+\frac{1}{10}\)

\(=-\frac{1}{40}\)

a) \(\frac{15}{33}+\frac{7}{20}+\frac{18}{33}+\frac{13}{20}=\left(\frac{15}{33}+\frac{18}{33}\right)+\left(\frac{7}{20}+\frac{13}{20}\right)\) = 1 + 1 = 2

b) \(2\frac{1}{2}+\frac{4}{7}:\left(\frac{-8}{21}\right)=\frac{5}{2}+\frac{4}{7}:\left(\frac{-8}{21}\right)=\frac{5}{2}+\frac{-3}{2}\) = 1

c) \(\left(\frac{-1}{2}\right)\)³ + \(\frac{1}{2}\) : 5 = \(\frac{-1}{8}+\frac{1}{10}\) = \(\frac{-1}{40}\)

Chúc bạn học tốt!