PTĐTTNT:
a) x(x+1)2 + x(x-5) - 5(x+1)
b) 25x2 - 4y2 - 9 + 12y
Những câu hỏi liên quan
a)a2 – 4b2 b) x2 – y2 + 6y - 9
c) (2a + b)2 – a2 d) 16(x – 1)2 – 25(x + y)2
e)x2 + 10x + 25 f) 25x2 – 20xy + 4y2
g)9x4 + 24x2 + 16 h) x3 – 125
i)x6 – 1 k) x3 + 15x2 + 75x + 125
Đọc tiếp
a)a2 – 4b2 b) x2 – y2 + 6y - 9
c) (2a + b)2 – a2 d) 16(x – 1)2 – 25(x + y)2
e)x2 + 10x + 25 f) 25x2 – 20xy + 4y2
g)9x4 + 24x2 + 16 h) x3 – 125
i)x6 – 1 k) x3 + 15x2 + 75x + 125
a) (a - 2b)x(a + 2b)
b) x2-(y-3)2
=> (x-y+3)(x+y-3)
c) (2a + b - a)(2a + b + a)
=> (a+b)(3a+b)
d) (4(x - 1))2 - (5(x + y))2
⇔ (4x - 4 - 5x - 5y)(4x - 4 + 5x + 5y)
⇔ -(x + 5y + 4)(9x + 5y + -4)
e) (x + 5)2
f) (5x - 2y)2
h) (x - 5)(x2 + 5x + 25)
k) (x + 5)3
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Tính giá trị của biểu thức:
a) N= (25x2 + 10xy + 4y2)(5x - 2y) tại x=1/5:y=1/2
b) Q= (x + 3y)(x2 - 3xy + 9y2) tại x=y=1/2
Giúp mik với ạ!
a: \(N=\left(5x\right)^3-\left(2y\right)^3=1^3-1^3=0\)
b: \(Q=x^3+27y^3=\dfrac{1}{8}+\dfrac{27}{8}=\dfrac{28}{8}=\dfrac{7}{2}\)
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Tính:a) (dfrac{1}{3}x+2y).(dfrac{1}{9}x2-dfrac{2}{3}xy+4y2) b) (x2-dfrac{1}{3}).(x4+dfrac{1}{3}x2+dfrac{1}{9})c) (y-5).(25+5y+y2+2y)d) (5x+3y).(25x2-15xy+9y2)Giải chi tiết giúp mình nha.Cảm ơn
Đọc tiếp
Tính:
a) (\(\dfrac{1}{3}\)x+2y).(\(\dfrac{1}{9}\)x2-\(\dfrac{2}{3}\)xy+4y2)
b) (x2-\(\dfrac{1}{3}\)).(x4+\(\dfrac{1}{3}\)x2+\(\dfrac{1}{9}\))
c) (y-5).(25+5y+y2+2y)
d) (5x+3y).(25x2-15xy+9y2)
Giải chi tiết giúp mình nha.Cảm ơn
a: \(\left(\dfrac{1}{3}x+2y\right)\left(\dfrac{1}{9}x^2-\dfrac{2}{3}xy+4y^2\right)=\dfrac{1}{27}x^3+8y^3\)
b: \(\left(x^2-\dfrac{1}{3}\right)\left(x^4+\dfrac{1}{3}x^2+\dfrac{1}{9}\right)=x^6-\dfrac{1}{27}\)
c: \(\left(y-5\right)\left(y^2+5y+25\right)=y^3-125\)
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Thực hiện phép tính:
1)(x3-8):(x-2)
2)(x3-1):(x2+x+1)
3)(x3+3x2+3x+1):(x2+2x+1)
4)(25x2-4y2):(5x-2y)
1) \(\left(x^3-8\right):\left(x-2\right)=\left[\left(x-2\right)\left(x^2+2x+4\right)\right]:\left(x-2\right)=x^2+2x+4\)
2) \(\left(x^3-1\right):\left(x^2+x+1\right)=\left[\left(x-1\right)\left(x^2+x+1\right)\right]:\left(x^2+x+1\right)=x-1\)
3) \(\left(x^3+3x^2+3x+1\right):\left(x^2+2x+1\right)=\left(x+1\right)^3:\left(x+1\right)^2=x+1\)
4) \(\left(25x^2-4y^2\right):\left(5x-2y\right)=\left[\left(5x-2y\right)\left(5x+2y\right)\right]:\left(5x-2y\right)=5x+2y\)
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Bài 1: Làm tính nhân:
a) 2x. (x2 – 7x -3) b) ( -2x3 + y2 -7xy). 4xy2
c)(-5x3). (2x2+3x-5) d) (2x2 - xy+ y2).(-3x3)
e)(x2 -2x+3). (x-4) f) ( 2x3 -3x -1). (5x+2)
g) ( 25x2 + 10xy + 4y2). ( ( 5x – 2y) h) ( 5x3 – x2 + 2x – 3). ( 4x2 – x + 2)
a) \(2x\left(x^2-7x-3\right)=2x.x^2-2x.7x-2x.3=2x^3-14x^2-6x\)
b) \(\left(-2x^3+y^2-7xy\right)4xy^2=\left(-2x^3\right)4xy^2+y^24xy^2-7xy.4xy^2=-8x^4y^2+4xy^4-28x^2y^3\)
c) \(\left(-5x^3\right)\left(2x^2+3x-5\right)=-5x^32x^2-5x^33x-5x^3.-5=-10x^5-15x^4+25x^3\)
d) \(\left(2x^2-xy+y^2\right)\left(-3x^3\right)=-3x^32x^2-3x^3.-xy-3x^3y^2=-6x^5+3x^4y-3x^3y^2\)
e) \(\left(x^2-2x+3\right)\left(x-4\right)=x\left(x^2-2x+3\right)-4\left(x^2-2x+3\right)=x^3-2x^2+3x-4x^2+8x-12=x^3-6x^2+11x-12\)
f) \(\left(2x^3-3x-1\right)\left(5x+2\right)=5x\left(2x^3-3x-1\right)+2\left(2x^3-3x-1\right)=10x^4-15x^2-5x+4x^3-6x-2=10x^4+4x^3-15x^2-11x-2\)
g)
\(\left(25x^2+10xy+4y^2\right).\left((5x-2y\right)\)
\(=125x^3-50x^2y+20x^2y-20xy^2+20xy^2-8y^3\)
\(=125x^3-30x^2y+8y^3\)
h)
\(\left(5x^3-x^2+2x-3\right)\left(4x^2-x+2\right)\)
\(=20x^5-5x^4+10x^3-4x^4+x^3-2x^2+8x^3-2x^2+4x-12x^2+3x-6\)
\(=20x^5-9x^4+19x^3-16x^2+7x-6\)
Thực hiện phép tính:
1) ( x2 - 4xy + 4y2) : ( x - 2y )
2) ( 25x2 + 2xy + 1/25y2 ) : ( 5x + 1/5y)
1) Ta có: \(x^2-4xy+4y^2\)
\(=x^2-2.x.2y+\left(2y\right)^2\)
\(=\left(x-2y\right)^2\)
Phép tính trở thành: \(\left(x-2y\right)^2:\left(x-2y\right)=x-2y\)
2) Ta có: \(25x^2+2xy+\dfrac{1}{25}y^2\)
\(=\left(5x\right)^2+2.5x.\dfrac{1}{5}y+\left(\dfrac{1}{5}y\right)^2\)
\(=\left(5x+\dfrac{1}{5}y\right)^2\)
Phép tính trở thành: \(\left(5x+\dfrac{1}{5}y\right)^2:\left(5x+\dfrac{1}{5}y\right)=5x+\dfrac{1}{5}y\)
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1) (x² - 4xy + 4y²) : (x - 2y)
= (x - 2y)² : (x - 2y)
= x - 2y
2) (25x² + 2xy + 1/25 y²) : (5x + 1/5 y)
= 5x + 1/5 y)² : (5x + 1/5 y)
= 5x + 1/5 y
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tìm x;y
a) 4x2+13y+12xy−18y−4x+104x2+13y+12xy−18y−4x+10
b) 4x2+12xy+9y2+4y2−18y−4x+104x2+12xy+9y2+4y2−18y−4x+10
c) (2x+3y)2−2(2x+3y)+1+4y2−12y+9(2x+3y)2−2(2x+3y)+1+4y2−12y+9
d) (2x+3y−1)+(2y−3)2=0
a) 2x. (x2 – 7x -3)
b) ( -2x3 + y2 -7xy). 4xy2
c)(-5x3). (2x2+3x-5)
d) (2x2 - xy+ y2).(-3x3)
e)(x2 -2x+3). (x-4)
f) ( 2x3 -3x -1). (5x+2)
g) ( 25x2 + 10xy + 4y2). ( 5x – 2y)
h) ( 5x3 – x2 + 2x – 3). ( 4x2 – x + 2)
a,\(4x^2-14x^2-6x=-10x^2-6x\)
các câu còn lại làm tg tuj
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a) 2x.(x2 - 7x - 3)
= 2xx2 + 2x(-7x) + 2x(-3)
= 2x2x - 2.7xx - 2.3x
= 2x3 - 14x2 - 6x
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ptnttn
a,0,5x3+4x2y+0,5xy2
b,0,25x9y-1)+0,75y(1-y)
c,0,25x2-0,5xy+0,25y2-0,25
d,(2\5x+1\3)2-(x\5+2\3)2
e,1\25x2+1\49y2
f,(1\9-x2-4y2-4xy
g,x2-x-y2-y
h,5x2-6x+1
k,x5+2x4=x3
help me!!! nhanh giùm nha chiều mình học r
f,
\(a,0,5x^3+4x^2y+0,5xy^2\\ =0,5x\left(x^2+8xy+y^2\right)\\ b,0,25x^9\left(y-1\right)+0,75y\left(1-y\right)\\ =0,25x^9\left(y-1\right)-0,75y\left(y-1\right)=\left(y-1\right)\left(0,25x^9-0,75y\right)\\ c,0,25x^2-0,5xy+0,25y^2-0,25\\ =\left(0,5x-0,5y\right)^2-0,25\\ =\left(0,5x-0,5y-0,5\right)\left(0,5x-0,5y+0,5\right)\\ =0,25\left(x-y-1\right)\left(x-y+1\right)\)
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