Ta có: \(4\cdot52+81:3^2-\left(13-4\right)^2\)

\(=208+81:9-9^2\)

\(=208+9-81\)

\(=217-81=136\)

a) \(4^7.3^2.9^6:6^{13}=2^{14}.3^2.3^{12}:6^{13}=2^{14}.3^{14}:6^{13}=\left(2.3\right)^{14}:6^{13}=6^{14}:6^{13}=6\)

b) \(\left(2^{16}+2^8\right):\left(2^{13}+2^5\right)=2^8\left(2^8+1\right):2^5\left(2^8+1\right)=2^8:2^5=2^{8-5}=2^3=8\)

-320

c) 3⁴ - 5.42

= 81 - 210

= -129

d) 120 : {54 - [50 : 2 - (3² - 2.4)]}

= 120 : {54 - [25 - (9 - 8)]}

= 120 : [54 - (25 - 1)]

= 120 : (54 - 24)

= 120 : 30

= 4

\(1.33,6\\ 2.-0,615\\ 3.-10\\ 4.-2,885\)

=28+32-28-32+5

=(28-28)+(32-32)+5

=5

28 - ( -32 ) + ( -28 ) - 32 + 5

= 28 + 32 + ( -28 ) - 32 + 5

= ( -28 + 28 ) + ( -32 + 32 ) + 5

= 0 + 0 + 5

= 5 

28-(-32)+(-28)-32+5

=[28+(-28)] +[(-32)+32]+5

= 0+0+5=5

mk tính nhanh

Bài 1: Thực hiện các phép tính sau:

\(a)\)Chưa rỏ đề

\(b)\)\(5025\div5-25\div5\)

\(=\)\(1005-5\)

\(=\)\(1000\)

\(c)\)\(218-180\div2\div9\)

\(=\)\(218-10\)

\(=\)\(208\)

\(d)\)\(\left(328-8\right)\div32\)

\(=\)\(320\div32\)

\(=\)\(10\)

Bài 1:

a) ( Tôi không nhìn rõ đầu bài )

b) 5025  :  5  -  25  :  5

=  ( 5025  -  25 )  :  5

=        5000   :   5

=       1000

c)   218  -  180  :  2  :  9

=     218   -    180  :  (  2  .  9 )

=      218    -    180   :  18

=       218    -    10

=       208

d)   (  328  -  8  )  :  32

=      320   :   32

=     10 

Bài 2: Thực hiện phép tính:

\(a)\)\(27.75+25.27-150\)

\(=\)\(27.\left(75+25\right)-150\)

\(=\)\(27.100-150\)

\(=\)\(2700-150\)

\(=\)\(2550\)

\(b)\)\(12\div\left\{400\div\left[500-\left(125+25.7\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-\left(125+175\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-300\right]\right\}\)

\(=\)\(12\div\left\{400\div200\right\}\)

\(=\)\(12\div2\)

\(=\)\(6\)

\(c)\)\(13.17-256\div16+14\div7-1\)

\(=\)\(221-16+2-1\)

\(=\)\(206\)

\(d)\)\(18\div3+182+3.\left(51\div17\right)\)

\(=\)\(6+182+3.3\)

\(=\)\(6+182+9\)

\(=\)\(197\)

36:32 + 23.22 = 36-2 + 23+2 = 34 + 25 = 81 + 32 = 113

Giải : 

\(=\left(2,86\times4\right)+\left(3,14\times4\right)-\left(6,01\times5\right)+3^2\\ =4\times\left(2,86+3,14\right)-30,05+9\\ =4\times6-30,05+9\\ =24-30,05+9\\ =2,95\)

a: \(\left(-2\right)^3-45:\left(-3\right)^2+\left(-2019\right)^0\cdot1^{2019}\)

\(=-8-45:9+1\)

\(=-8-5+1\)

=-13+1

=-12

b: \(11^{25}:11^{13}-3^5:\left(1^{10}+2^3\right)-60\)

\(=11^{25-13}-3^5:3^2-60\)

\(=11^{12}-27-60\)

\(=11^{12}-87\)