\(a,\frac{-2}{3}x=8\)<=> \(x=-12\)

\(b,\frac{1}{4}:x=-3+\frac{3}{4}\)<=>\(\frac{1}{4}:x=\frac{-9}{4}\)<=>\(x=-9\)

\(c,\orbr{\begin{cases}2x-\frac{1}{3}=0\\0.5x+0.25=0\end{cases}}\)<=>\(\orbr{\begin{cases}x=\frac{1}{6}\\x=\frac{-3}{4}\end{cases}}\)

a) \(\frac{-2}{3}x+4=12\)

\(\Rightarrow\frac{-2}{3}x=12-4\)

\(\Rightarrow\frac{-2}{3}x=8\)

\(\Rightarrow x=8:\frac{-2}{3}\)

\(\Rightarrow x=-12\)

Vậy x = -12

b) \(\frac{-3}{4}+\frac{1}{4}:x=-3\)

\(\Rightarrow\frac{1}{4}:x=-3-\left(\frac{3}{4}\right)\)

\(\Rightarrow\frac{1}{4}:x=\frac{-9}{4}\)

\(\Rightarrow x=\frac{1}{4}:\frac{-9}{4}\)

\(\Rightarrow x=\frac{-1}{9}\)

Vậy  \(x=\frac{-1}{9}\)

c) \(\left(2x-\frac{1}{3}\right)\left(0,5x+0,25\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-\frac{1}{3}=0\\0,5x+0,25=0\end{cases}}\Rightarrow\orbr{\begin{cases}2x=\frac{1}{3}\\0,5x=-0,25\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{6}\\x=-0,5\end{cases}}\)

Vậy  \(x=\frac{1}{6}\)hoặc \(x=-0,5\)

_Chúc bạn học tốt_

a)12(x-1)=0

=>x-1=0

=>x=1

b) 3/5x-3/4=(-3)²-|-11|

3/5x-3/4=9-11=-2

3/5x=-2+3/4=-5/4

=>x=-5/4:3/5=-25/12

c)4(x-5/8)-3/4=0,25

4(x-5/8)=0,25+3/4=1

=>x-5/8=1/4

x=1/4+5/8=7/8

2) Số đó là

27:3/5=45

a) \(215+x=400\)

\(\Rightarrow x=400-215\)

\(\Rightarrow x=185\)

b) \(12,5-2x=\dfrac{1}{5}\)

\(\Rightarrow2x=12,5-\dfrac{1}{5}\)

\(\Rightarrow2x=\dfrac{123}{10}\)

\(\Rightarrow x=\dfrac{123}{10}:2\)

\(\Rightarrow x=\dfrac{123}{20}\)

còn câu c d nhanh cậu ơi

Bạn xem lại đề phần e nha .

\(c)x.0,25-\dfrac{3}{25}:x=2\dfrac{1}{4}\)

\(x.0,25-\dfrac{25}{3}.x=\dfrac{9}{4}\)

\(x.\left(0,25-\dfrac{25}{3}\right)=\dfrac{9}{4}\)

\(x.\dfrac{-97}{12}=\dfrac{9}{4}\)

\(x=\dfrac{-27}{97}\)

\(d)\left(x-\dfrac{1}{3}\right).\left(x-\dfrac{1}{4}\right)=0\)

Do : 2 số đó nhân với nhau bằng 0 nên một trong 2 số là số 0.

Do đó :

\(Th1:x-\dfrac{1}{3}=0\)

\(x=\dfrac{1}{3}\)

\(Th2:x-\dfrac{1}{4}=0\)

\(x=\dfrac{1}{4}\)

2/3xX-1/4:(11/2-3/4)=1/6

2/3xX:19/4=1/6

2/3xX=1/6x19/4

2/3xX=19/24

       X=19/24:2/3

       X=19/16

chắc luôn

sai rồi em ạ

bài này mk vừa mới giúp bạn đó, tìm đi, có đó

( Chúc you học good )

a, \(7\left(x-1\right)+2x\left(1-x\right)=0\)

\(\Rightarrow\left(7-2x\right)\left(x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}7-2x=0\\x-1=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=1\end{cases}}\)

b, \(0,25-\left|3,5-x\right|=0\)

\(\Rightarrow\left|3,5-x\right|=2,5\)

\(\Rightarrow\orbr{\begin{cases}3,5-x=2,5\\3,5-x=-2,5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=6\end{cases}}\)

c, \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)

\(\Rightarrow\left|x+\frac{3}{4}\right|=\frac{1}{2}\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=\frac{-1}{2}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{4}\\x=\frac{-5}{4}\end{cases}}\)

a) 7.(x-1) + 2x.(1-x) = 0

7.(x-1) - 2x.(x-1) = 0

(x-1).(7-2x) = 0

=> (x-1) = 0 => x = 1

7-2x = 0 => 2x = 7 => x = 7/2

KL:...

b) 0,25 - | 3,5-x| = 0

=> |3,5 - x| = 0,25

TH1: 3,5 - x = 0,25

x = 3,25

TH2: 3,5 - x = -0,25

x = 3,75

phần c bn dựa vào phần b mak lm nha

a) 7.(x - 1) + 2x.(1 - x) = 0

<=> -2x² + 9x - 7 = 0

<=> \(\orbr{\begin{cases}x=1\\x=\frac{7}{2}\end{cases}}\)

=> \(\orbr{\begin{cases}x=1\\x=\frac{7}{2}\end{cases}}\)

b) 0,25 - |3,5 - x| = 0

<=> - |3,5 - x| = 0 - 0,25

<=> - |3,5 - x| = -0,25 

<=> |3,5 - x| = 0,25

Ta xét 2 th:

Th1: |x| = 3,5 - 0,25

<=> |x| = \(\frac{13}{4}\)

Th2: |x| = 3,5 + 0,25

<=> x = \(\frac{15}{4}\)

=> \(\orbr{\begin{cases}x=\frac{13}{4}\\\frac{15}{4}\end{cases}}\)

c) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)

<=> \(\left|x+\frac{3}{4}\right|=0+\frac{1}{2}\)

<=> \(\left|x+\frac{3}{4}\right|=\frac{1}{2}\)

Ta xét 2 th:

Th1: \(x+\frac{3}{4}=\frac{1}{2}\)

<=> \(x=\frac{1}{2}-\frac{5}{4}\)

<=> \(x=-\frac{3}{4}\)

Th2: \(x+\frac{3}{4}=\frac{1}{2}\)

<=> \(x=\frac{1}{2}-\frac{3}{4}\)

<=> \(x=-\frac{1}{4}\)

=> \(\orbr{\begin{cases}x=-\frac{3}{4}\\x=-\frac{1}{4}\end{cases}}\)

\(a,\dfrac{-3}{4}x+1=\dfrac{5}{6}\\ \Rightarrow\dfrac{-3}{4}x=\dfrac{-1}{6}\\ \Rightarrow x=\dfrac{2}{9}\\ b,\left(2x-3\right)\left(x-5\right)=0\\ \Rightarrow\left[{}\begin{matrix}2x-3=0\\x-5=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=5\end{matrix}\right.\\ c,\dfrac{1}{2}-\left|x+1\right|=0,25\\ \Rightarrow\left|x+1\right|=0,25\\ \Rightarrow\left[{}\begin{matrix}x+1=0,25\\x+1=-0,25\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-0,75\\x=-1,25\end{matrix}\right.\)

a: =>-3/4x=-1/6

hay x=2/9

b: =>2x-3=0 hoặc x-5=0

hay x=3/2 hoặc x=5

c: =>|x+1|=1/4

\(\Leftrightarrow x+1\in\left\{\dfrac{1}{4};-\dfrac{1}{4}\right\}\)

hay \(x\in\left\{-\dfrac{3}{4};-\dfrac{5}{4}\right\}\)

b, \(=>2x-3=0\)      hay       \(x-5=0\)

           \(2x=0+3\)                   \(x=0+5\)

          \(2x=3\)                           \(x=5\)

            \(x=\dfrac{3}{2}\)

Vậy x ϵ { \(\dfrac{3}{2}\);5}

   3/3 - 1/4.x=0,25
=> 1-1/4x=0,25
        1/4x=1-0,25
        1/4x=0,75
             x=0,75:1/4
             x=3

Vậy x=3