a. \(\dfrac{x}{5}=\dfrac{8}{10}\)

\(\Rightarrow10x=8.5\)

\(\Rightarrow10x=40\)

\(\Rightarrow x=\dfrac{40}{10}=4\)

b. \(\dfrac{9}{x}=\dfrac{90}{100}\)

\(\Rightarrow9.100=90x\)

\(\Rightarrow900=90x\)

\(\Rightarrow x=\dfrac{900}{90}=10\)

c. \(17+\dfrac{x}{35}=\dfrac{5}{7}\)

\(\Rightarrow\dfrac{595+x}{35}=\dfrac{25}{35}\)

\(\Rightarrow595+x=25\)

\(\Rightarrow x=25-595=-570\)

d. \(x:\dfrac{5}{27}=\dfrac{2}{9}\)

\(\Rightarrow\dfrac{27x:5}{27}=\dfrac{6}{27}\)

\(\Rightarrow27x:5=6\)

\(\Rightarrow27x=5.6\)

\(\Rightarrow27x=30\)

\(\Rightarrow x=\dfrac{30}{27}=\dfrac{10}{9}\approx1,11\)

c: 90\(⋮\)x-2

=>\(x-2\in\){1;-1;2;-2;3;-3;5;-5;6;-6;9;-9;10;-10;15;-15;18;-18;30;-30;45;-45;90;-90}

=>x\(\in\){3;1;4;0;5;-1;7;-3;8;-4;11;-7;12;-8;17;-13;20;-16;32;-28;47;-43;92;-88}

mà 10<=x<=90

nên \(x\in\left\{11;12;17;20;32;47\right\}\)

d: \(x⋮12\)

=>\(x\in\left\{0;12;24;36;48;60;72;...\right\}\)

mà 30<=x<=60

nên \(x\in\left\{36;48;60\right\}\)

a: x-140:35=270

=>x-4=270

=>x=270+4=274

b: \(\left(3x-1\right)^2-3^2=4^2\)

=>(3x-1)²-9=16

=>\(\left(3x-1\right)^2=25\)

=>\(\left[{}\begin{matrix}3x-1=5\\3x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=6\\3x=-4\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=2\\x=-\dfrac{4}{3}\end{matrix}\right.\)

\(\left(2009-x\right):29+32=100\\ =>\left(2009-x\right):29=100-32=68\\ =>2009-x=68.29=1972\\ =>x=2009-1972=37\)

-

\(\left(x-2\right).3-270:45=120\\ =>3\left(x-2\right)-6=120\\ =>3\left(x-2\right)=120+6=126\\ =>x-2=126:3=42\\ =>x=42+2=44\)

( 2009 - x ) : 29 + 32 = 100

( 2009 - x ) : 29        = 100 - 32 

( 2009 - x ) : 29        = 68 

( 2009 - x )              = 68 . 29  

  2009 - x                = 1972

            x                = 2009 - 1972

            x                = 37

[2009 - x] : 29 =100-32

[2009-x] : 29 =68

2009-x =68x29

2009-x=1972

x=2009-1972

x=37

(2009-x):29+32=100

=>(2009-x):29=100-32

=>(2009-x):29=68

=>2009-x=68x29

=>2009-x=1972

=>x=2009-1972

=>x=37

(2009-x) : 29 + 32 = 100

(2009-x): 29 = 68

2009-x = 68 x 29

2009 - x = 2001

x= 2009 - 2001

x=8

( 2009 - x ) : 29 + 32 = 100

( 2009 - x ) : 29 = 100 - 32

( 2009 - x ) : 29 = 68

  2009 - x = 68 x 29

  2009 - x = 1972

            x = 2009 - 1972

            x = 37

bài 2 tìm x

a,106- ( x+ 7) =9

x+7 = 106 - 9

x+7 = 107

x= 107 - 7

x=100

b, 2 x ( x+ 4) + 5 =65

2 x (x+4) = 65 - 5

2 x (x+4) = 60

x+4 = 60:2

x+4= 30

x= 30 - 4

x=26

c, (16x x -32) x 45=0

16 x X - 32 = 0: 45

16 x X - 32 =0

16 x X = 0 + 32

16 x X = 32

X= 32:16

X=2

d, x+4 x x = 100 : 5

X + 4 x X = 20

(1+4) x X = 20

5 x X  = 20

X= 20:5

X=4

Bài 1:

a, 24 x 66 - 24 + 36 x 24

= 24 x (66-1+36)

= 24 x 101

= 24 x 100 + 24

= 2400+24

=2424

b, 29 x 173 - 29 x 72 - 29

= 29 x (173 - 72 -1)

= 29 x 100

= 2900

c, 1+5+10+15+...+55+60

= (5+60) x 6 + 1 (có 6 cặp)

= 65 x 6 + 1

= 390 +1 =391

d, D= 1 x 2 + 2 x 3 + 3 x 4 +...+18 x 19 + 19 x 20

3D= 1 x 2 x 3+ 2 x 3 x (4-1) + 3 x 4 x (5-2) +...+ 18 x 19 x (20 - 17) + 19 x 20 x (21-18)

3D= 1 x 2 x 3 - 1 x 2 x 3 + 2 x 3 x 4 - 2 x 3 x 4 +.... + 19 x 20 x 21 - 18 x 19 x 20

3D= 19 x 20 x 21 =7980

=> D= 7980:3=2660

a) => 12925 : x = 3522 - 3247

12925 : x = 275

x = 12925 : 275

x = 47

b) => 17658 : x = 149 + 178

17658 : x = 327

x = 17658 : 327

x = 54

a)  x ∈ 4 ; 3

b)  − 19 23 < − 19 x < − 19 29 ⇒ x ∈ 24 ; 25 ; 26 ; 27 ; 28

a: =>31-x=60

=>x=-29

b: =>(x-140):35=280-270=10

=>x-140=350

=>x=490

c: =>(1900-2x):35=48

=>1900-2x=1680

=>2x=220

=>x=110

d: =>\(2^{2x-1}=2^9\cdot2=2^{11}\)

=>2x-1=11

=>x=6

e: =>(x+2)^5=4^5

=>x+2=4

=>x=2

f: =>3x-4=0 hoặc x-1=0

=>x=4/3 hoặc x=1

g: =>(2x-1)^2=49

=>2x-1=7 hoặc 2x-1=-7

=>x=-3 hoặc x=4

h: =>x(x+1)/2=78

=>x(x+1)=156

=>x=12