#)Giải :
a)\(\left(x-149\right)\div35=270\)
\(\Leftrightarrow x-149=9450\)
\(\Leftrightarrow x=9599\)
\(a,(x-149):35=270\)
\(\Leftrightarrow x-149=9450\)
\(\Leftrightarrow x=9450+149=9599\)
Vậy x = 9599
\(b,(2009-x):29+32=100\)
\(\Leftrightarrow(2009-x):29=68\)
\(\Leftrightarrow2009-x=1972\)
\(\Leftrightarrow x=2009-1972=37\)
Vậy x = 37
\(c,x+472=918\)
\(\Leftrightarrow x=918-472=446\)
Vậy x = 446
a) (x - 149) : 35 = 270
x - 149 = 270 . 35
x - 149 = 9450
x = 9450 + 149
x = 9599
b) (2009 - x) : 29 + 32 = 100
(2009 - x) : 29 = 100 - 32
(2009 - x) : 29 = 68
2009 - x = 68 x 29
2009 - x = 1972
x = 2009 - 1972
x = 37
c) x + 172 = 918
x = 918 - 472
x = 446
a, (x - 149) : 35 = 270
=> x - 149 = 270 . 35
=> x - 149 = 9450
=> x = 9450 + 149
=> x = 9599
Vậy x = 9599
b, (2009 - x) : 29 + 32 = 100
=> (2009 - x) : 29 = 100 - 32
=> (2009 - x) : 29 = 68
=> 2009 - x = 68 . 29
=> 2009 - x = 1972
=> x = 2009 - 1972
=> x = 37
c, x + 472 = 918
=> x = 918 - 472
=> x = 446
Vậy x = 446
#)Next :
c)\(x+472=918\)
\(\Leftrightarrow x=446\)
P/s : Câu b) viết thiếu hay lỗi ph k ? tính ra kết quả cứ sao sao ý ?
a, \(\left(x-149\right):35=270\)
\(\Rightarrow x-149=270.35\)
\(\Rightarrow x-149=9450\)
\(\Rightarrow x=9450+149\)
\(\Rightarrow x=9599\)
b, \(\left(2009-x\right):29+32=100\)
\(\Rightarrow\left(2009-x\right):29=100-32\)
\(\Rightarrow\left(2009-x\right):29=68\)
\(\Rightarrow2009-x=68.29\)
\(\Rightarrow2009-x=1972\)
\(\Rightarrow x=2009-1972\)
\(\Rightarrow x=37\)
c, \(x+472=918\)
\(\Rightarrow x=918-472\)
\(\Rightarrow x=446\)
a)(x - 149) : 35 = 270
=> x - 149 = 270 x 35
=> x - 149 = 9450
=> x = 9450 + 149
=> x = 9599
b) (2009 - x) : 29 + 32 = 100
=> (2009 - x) : 29 = 100 - 32
=> (2009 - x) : 29 = 68
=> 2009 - x = 68 x 29
=> 2009 - x =1972
=> x = 2009 - 1972
=> x = 37
c) x + 472 = 918
=> x = 918 - 472
=> x = 446
