Chị ơi tìm gì đấy ạ chị noi thế có bố em cũng chả giải được

a) ( ko hỉu )

13 + ( -17 ) = ( 2 + 5 ) - 15

b) 3 - ( x + 5 ) = 11 - ( -3 )

    3 - ( x + 5 ) = 14

           x + 5   = 3 - 14

           x + 5   = ( -11 )

           x         = ( - 11 ) - 5

           x         = ( -16 )

a.|x-1|=3

=>x-1=3 hoặc x-1=-3

=>x=4 hoăc x=-2

vậy...

b.2x+17=15

=>2x=15-17

=>2x=-2

=>x=-1

vậy...

c.tự giải

d.4x-15=-75-x

=>4x+x=-75+15

=>5x=-60

=>x=-12

vậy...

2.2+(-3)+4+...+(-2011)+2012

=(-3+2)+...+(-2011+2010)+2012 (có 2010 cặp)

=-1.2010+2012

=-2010+2012=2

Ai mún kb vs mink ko

2.

Tổng A có số số hạng  là:2012-2+1=2011(số)

A=[2+(-3)]+....+[2010+(-2011)]+2012

A=(-1)+..+(-1)+2012

Vậy sẽ có:1005 cặp số

A=[(-1)*1005]+2012

A=(-1005)+2012

A=1007

Nhớ k cho mình nhé

9/11 x 10/13 + 9/13 x 12/11 - 7/11

= 9/13 x 10/11 + 9/13 x 12/11 - 7/11

= 9/13 x (10/11 + 12/11) - 7/11

= 9/13 x 22/11 - 7/11

= 9/13 x 2 - 7/11

= 18/13 - 7/11

= 198/143 - 91/143

= 107/143

\(\dfrac{9}{11}\times\dfrac{10}{13}+\dfrac{9}{13}\times\dfrac{12}{11}-\dfrac{7}{11}=\dfrac{9}{13}\times\dfrac{10}{11}+\dfrac{9}{13}\times\dfrac{12}{11}-\dfrac{7}{11}=\dfrac{9}{13}\times\left(\dfrac{10}{11}+\dfrac{12}{11}\right)-\dfrac{7}{11}=\dfrac{9}{13}\times2-\dfrac{7}{11}=\dfrac{18}{13}-\dfrac{7}{11}=\dfrac{107}{143}\)

3/2-5/6+7/12-9/20+11/30-13/42+15/56-17/72

=1.5-0.8(3)+0.58(3)-0.3(6)-0.3(095238)+0.267(857142)-0236(1)

=0.(8)

560394 : 294 = .......................

giúp mình với mình đang vội

`@` `\text {Ans}`

`\downarrow`

`a)`

`-9/34*17/4`

`=`\(\dfrac{-9}{17\cdot2}\cdot\dfrac{17}{4}\)

`=`\(-\dfrac{9}{2}\cdot\dfrac{1}{4}\)

`=`\(-\dfrac{9}{8}\)

`b)`

\(\dfrac{17}{15}\div\dfrac{4}{3}\)

`=`\(\dfrac{17}{15}\cdot\dfrac{3}{4}\)

`=`\(\dfrac{17}{3\cdot5}\cdot\dfrac{3}{4}\)

`=`\(\dfrac{17}{5}\cdot\dfrac{1}{4}\)

`=`\(\dfrac{17}{20}\)

`c)`

\(4\dfrac{1}{5}\div\left(-2\dfrac{4}{5}\right)\)

`=`\(4\dfrac{1}{5}\cdot\left(-\dfrac{5}{14}\right)\)

`=`\(\dfrac{21}{5}\cdot\left(-\dfrac{5}{14}\right)\)

`=`\(-\dfrac{21}{14}=-\dfrac{3}{2}\)

a) \(\dfrac{-9}{34}\cdot\dfrac{17}{4}\)

\(=\dfrac{-9\cdot17}{34\cdot4}\)

\(=-\dfrac{153}{136}\)

\(=\dfrac{9}{8}\)

b) \(\dfrac{17}{15}:\dfrac{4}{3}\)

\(=\dfrac{17}{15}\cdot\dfrac{3}{4}\)

\(=\dfrac{17\cdot3}{15\cdot4}\)

\(=\dfrac{51}{60}=\dfrac{17}{20}\)

c) \(4\dfrac{1}{5}:\left(-2\dfrac{4}{5}\right)\)

\(=\dfrac{21}{5}:-\dfrac{14}{5}\)

\(=\dfrac{21}{5}\cdot-\dfrac{5}{14}\)

\(=\dfrac{21\cdot-5}{5\cdot14}\)

\(=-\dfrac{105}{70}=\dfrac{3}{2}\)

a) −934⋅17434−9​⋅417​

=−9⋅1734⋅4=34⋅4−9⋅17​

=−153136=−136153​

=98=89​

b) 1715:431517​:34​

=1715⋅34=1517​⋅43​

=17⋅315⋅4=15⋅417⋅3​

=5160=1720=6051​=2017​

c) 415:(−245)451​:(−254​)

=215:−145=521​:−514​

=215⋅−514=521​⋅−145​

=21⋅−55⋅14=5⋅1421⋅−5​

=−10570=32=−70105​=2

\(x+17\) \(⋮\) \(x\) + 11 đkxđ \(x\) \(\ne\) - 11

\(x+11\) + 6  ⋮ \(x\) + 11

              6   \(⋮\) \(x+11\)

\(x+11\) \(\in\) Ư(6) = { -6; -3; -2; -1; 1; 2; 3; 6}

\(x\) \(\in\) {  -17; - 14; -13;-12; -10; - 9; -8; -5}

X + 17 = X + 11 + 6

Để (X + 17) ⋮ (X + 11) thì 6 ⋮ (X + 11)

⇒ X + 11 ∈ Ư(6) = {-6; -3; -2; -1; 1; 2; 3; 6}

⇒ X ∈ {-17; -14; -13; -12; -10; -9; -8; -5}

( 9/5 +  8/5 )  : 17 /15

= 17/15 : 17/15

=225/85=3

\(=\frac{\left(\frac{9}{5}+\frac{8}{5}\right)}{\frac{17}{15}}=\frac{\left(\frac{17}{5}\right)}{\left(\frac{17}{15}\right)}=\frac{255}{85}\)

\(=\frac{135}{85}+\frac{120}{85}=\frac{255}{85}\)